IIT JEE प्रश्न और उत्तर का अभ्यास करें
8प्र: One year ago the ratio between Maneela’s and Shanthi’s salary was 3 : 4. The ratios of their individual salaries between last year’s and this year’s salaries are 4 : 5 and 2 : 3 respectively. At present the total of their salary is Rs. 4160. The salary of Maneela, now is? 6337 05b5cc678e4d2b4197774c165
5b5cc678e4d2b4197774c165- 1Rs. 1600true
- 2Rs. 1700false
- 3Rs. 1800false
- 4Rs. 1900false
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उत्तर : 1. "Rs. 1600"
व्याख्या :
Answer: A) Rs. 1600 Explanation: Let the salaries of Maneela and Shanthi one year before be M1, S1 & now be M2, S2 respectively. Then, from the given data, M1/S1 = 3/4 .....(1) M1/M2 = 4/5 .....(2) S1/S2 = 2/3 .....(3) and M2 + S2 = 4160 .....(4) Solving all these eqtns, we get M2 = Rs. 1600.
प्र: If A + B = 2C and C + D = 2A, then 6332 05b5cc7b9e4d2b4197775096e
5b5cc7b9e4d2b4197775096e- 1A + C = B + Dtrue
- 2A + C = 2Dfalse
- 3A + D = B + Cfalse
- 4A + C = 2Bfalse
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उत्तर : 1. "A + C = B + D"
व्याख्या :
Answer: A) A + C = B + D Explanation: Given, A + B = 2C ----(i) C + D = 2A----(ii) Adding (i) and (ii) we get : A + B + C + D = 2C + 2A => B + D = A + C
प्र: Find the odd number out of the following number series? 2 4 8 11.5 18.25 28.375 6329 05b5cc68be4d2b4197774c380
5b5cc68be4d2b4197774c380- 118.25false
- 228.375false
- 311.5false
- 48true
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उत्तर : 4. "8"
व्याख्या :
Answer: D) 8 Explanation: Given number series follows a pattern that, 2 2 x 1.5 + 1 = 4 4 x 1.5 + 1 = 7 (not equal to 8) 7 x 1.5 + 1 = 11.5 11.5 x 1.5 + 1 = 18.25 18.25 x 1.5 + 1 = 28.375 Hence, the odd number in the given number series is 8.
प्र: The process of collecting, organizing and analyzing data is called 6292 05b5cc694e4d2b4197774c47f
5b5cc694e4d2b4197774c47f- 1Statisticstrue
- 2Data collectionfalse
- 3Probabilityfalse
- 4Systematic evaluationfalse
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उत्तर : 1. "Statistics"
व्याख्या :
Answer: A) Statistics Explanation: The process of collecting, organizing and analyzing data is called Statistics.
प्र: Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there be three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue? 6248 05b5cc7f2e4d2b41977751eac
5b5cc7f2e4d2b41977751eac- 141false
- 240false
- 328true
- 427false
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उत्तर : 3. "28"
व्याख्या :
Answer: C) 28 Explanation: Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB. We may consider the two cases as under: Case I: ←3C↔8B↔5A→21 Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40 Case II: ←3C A↔5B Number of persons between A and C = (8 - 6) = 2 ∵[C↔8B A→21B] Clearly number of persons in the queue = (3+1+2+1+21) = 28 Now, 28 < 40. So, 28 is the minimum number of persons in the queue.
प्र: Vaunt : Flaunt :: Disparate : ? 6245 05b5cc6a0e4d2b4197774ca7b
5b5cc6a0e4d2b4197774ca7b- 1Similarfalse
- 2Homogenousfalse
- 3Contrasttrue
- 4Alikefalse
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उत्तर : 3. "Contrast"
व्याख्या :
Answer: C) Contrast Explanation: Vaunt - Vaunt means to boast or to praise about something excessively. Flaunt - Flaunt also means to boast about something or to praise something. Flaunt is the synonym of the word Vaunt. Disparate - Disparate means essentially different in its kind or unlike or not able to be compared. Then the required word is the synonym of Disparate. Here in the given options, Contrast is the only word which is similar in meaning of Disparate. Hence, Vaunt : Flaunt :: Disparate : Contrast.
प्र: What is the number of digits in 333? Given that log3 = 0.47712? 6237 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
- 415false
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उत्तर : 2. "13"
व्याख्या :
Answer: B) 13 Explanation: Let Let x=333 = 333 Then, logx = 33 log3 = 27 x 0.47712 = 12.88224 Since the characteristic in the resultant value of log x is 12 ∴The number of digits in x is (12 + 1) = 13 Hence the required number of digits in 333is 13.
प्र: Amar can do a piece of work in 10 days. He works at it for 4 days and then Arun finishes it in 9 days. In how many days can Amar and Arun together finish the work ? 6228 05b5cc6d6e4d2b4197774e66a
5b5cc6d6e4d2b4197774e66a- 14 daysfalse
- 28 daysfalse
- 33 daysfalse
- 46 daystrue
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उत्तर : 4. "6 days"
व्याख्या :
Answer: D) 6 days Explanation: 4/10 + 9/x = 1 => x = 15 Then both can do in 1/10 + 1/15 = 1/6 => 6 days

