IIT JEE Practice Question and Answer
8Q: Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work ? 4757 05b5cc6e1e4d2b4197774ebbb
5b5cc6e1e4d2b4197774ebbb- 118 daysfalse
- 220 daystrue
- 316 daysfalse
- 414 daysfalse
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Answer : 2. "20 days"
Explanation :
Answer: B) 20 days Explanation: (5m + 9w)10 = (6m + 12w)8 => 50m + 90w = 48w + 96 w => 1m = 3w 5m + 9w = 5m + 3m = 8m 8 men can do the work in 10 days. 3m +3w = 3m + 1w = 4m So, 4 men can do the work in (10 x 8)/4 = 20 days.
Q: In a mens hostel, there were 95 students. To accommodate 30 more students the average is decreased by rupees 5. But total expenditure increased by Rs.500. Find the total expenditure of the hostel now ? 4749 05b5cc6d4e4d2b4197774e5cf
5b5cc6d4e4d2b4197774e5cf- 1Rs. 4680true
- 2Rs. 4420false
- 3Rs. 4960false
- 4Rs. 5480false
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Answer : 1. "Rs. 4680"
Explanation :
Answer: A) Rs. 4680 Explanation: Let the expenditure on the 95 students be 'x' Then, 95x + 500 = 120(x – 5)95x + 500 = 120x - 600120x - 95x = 110025x = 1100=> x = 44 Therefore, total expenditure of the hostel becomes95 x 44 + 500 = 4680.
Q: Which best describes how air moves during convection? 4727 05b5cc6a0e4d2b4197774ca56
5b5cc6a0e4d2b4197774ca56- 1cool air falls downtrue
- 2warm air falls downfalse
- 3cool air is replaced by warm airfalse
- 4air always falls downfalse
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Answer : 1. "cool air falls down"
Explanation :
Answer: A) cool air falls down Explanation: During convection, cool and dense air falls through the warmer and less dense air. The warm air having less mass is being displaced by the cooler which is much heavy. Convection always involves the air rising through the atmosphere.
Q: Thread is to String as Cask is to 4713 05b5cc6b6e4d2b4197774d58e
5b5cc6b6e4d2b4197774d58e- 1Barreltrue
- 2Discfalse
- 3Walletfalse
- 4Boxfalse
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Answer : 1. "Barrel"
Explanation :
Answer: A) Barrel Explanation: Here Thread and String are Synonyms of each other. Then the answer will be the synonym of Cask. Cask is nothing but a large barrel-like container used for storing liquids, typically alcoholic drinks. Ex : Drum, Vessel, Tank, Barrel, Hogshead, Firkin,... Here from the options Barrel is the only synonym of Cask. Thus, Thread : String :: Cask : Barrel
Q: Artist is to painting as senator is to 4706 05b5cc636e4d2b4197774b9fa
5b5cc636e4d2b4197774b9fa- 1politicianfalse
- 2constituentsfalse
- 3attorneyfalse
- 4lawtrue
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Answer : 4. "law"
Explanation :
Answer: D) law Explanation: As we know that an artist makes paintings, similarly, a senator makes laws. Hence, Artist : Painting :: Senator : Law.
Q: इनमें से कौन एक साधारण मशीन नहीं है? 4702 15b5cc607e4d2b4197774b55e
5b5cc607e4d2b4197774b55e- 1कैंची की एक जोड़ीtrue
- 2एक लीवरfalse
- 3एक रैंपfalse
- 4चरखीfalse
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Answer : 1. "कैंची की एक जोड़ी"
Explanation :
Answer: A) कैंची की एक जोड़ी व्याख्या: बल लगाने के लिए किसी भी बुनियादी यांत्रिक उपकरण को सरल मशीन कहा जाता है। 6 बुनियादी सरल मशीनें हैं; लीवर, पहिया और धुरी, झुका हुआ विमान, पच्चर, चरखी और पेंच। इनमें से कई सरल मशीनें एक दूसरे से संबंधित हैं। लेकिन, काम करने की दुनिया में प्रत्येक का एक विशिष्ट उद्देश्य होता है।
Q: Find the missing number in the given number series? 2676, 445, ?, 21,6, 2, 1 4686 05b5cc69de4d2b4197774c8b2
5b5cc69de4d2b4197774c8b2- 188true
- 292false
- 396false
- 4102false
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Answer : 1. "88"
Explanation :
Answer: A) 88 Explanation: The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that, From right side, 1 1 x 1 + 1 = 2 2 x 2 + 2 = 6 6 x 3 + 3 = 21 21 x 4 + 4 = 88 88 x 5 + 5 = 445 445 x 6 + 6 = 2676 Hence the missing number in the given number series is 88.
Q: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 4666 05b5cc6dee4d2b4197774ea65
5b5cc6dee4d2b4197774ea65- 120true
- 235false
- 354false
- 440false
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Answer : 1. "20"
Explanation :
Answer: A) 20 Explanation: Numbers of students in section A = x ∴ Numbers of students in section B and C = (100 – x) ∴ x 70 + (100 – x) 87.5 = 84 100 => 70x + 87.5 100 – 87.5x = 8400 => 8750 – 17.5x = 8400 => 17.5x = 8750 – 8400 => x = 20.