IIT JEE प्रश्न और उत्तर का अभ्यास करें

प्र: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58 4046 0

  • 1
    A
    सही
    गलत
  • 2
    B
    सही
    गलत
  • 3
    C
    सही
    गलत
  • 4
    D
    सही
    गलत
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उत्तर : 3. "C"
व्याख्या :

Answer: C) C Explanation: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C

प्र: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 4015 0

  • 1
    1080 cm
    सही
    गलत
  • 2
    180 m
    सही
    गलत
  • 3
    108 m
    सही
    गलत
  • 4
    118 cm
    सही
    गलत
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उत्तर : 3. "108 m"
व्याख्या :

Answer: C) 108 m Explanation: We know the rule that,   At particular time for all object , ratio of height and shadow are same.   Let the height of the pole be 'H'   Then  188=H48   => H = 108 m.

प्र: Read the arrangement carefully and give the answer of following questions ? K$23DBE8HM4@5JF4%K1+WR#AA*415 How many such symbols are there which is not immediately preceded by a letter but immediately followed by a number ? 4015 0

  • 1
    1
    सही
    गलत
  • 2
    2
    सही
    गलत
  • 3
    3
    सही
    गलत
  • 4
    0
    सही
    गलत
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उत्तर : 1. "1"
व्याख्या :

Answer: A) 1 Explanation: Only one such symbol is there in the given arrangement. It is 4@5.

प्र: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 4014 0

  • 1
    75 min
    सही
    गलत
  • 2
    82 min
    सही
    गलत
  • 3
    90 min
    सही
    गलत
  • 4
    101 min
    सही
    गलत
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उत्तर : 3. "90 min"
व्याख्या :

Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.

प्र: John sells his laptop to Mark at a loss of 20% who subsequently sells it to Kevin at a profit of 25%. Kevin after finding some defect in the laptop, returns it to Mark but could recover only Rs.4.50 for every Rs. 5 he had paid. Find the amount of Kevin’s loss if John had paid Rs. 1,75,000 for the laptop ? 4012 0

  • 1
    Rs.16,500
    सही
    गलत
  • 2
    Rs.17,500
    सही
    गलत
  • 3
    Rs.14,200
    सही
    गलत
  • 4
    Rs.15,520
    सही
    गलत
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उत्तर : 2. "Rs.17,500"
व्याख्या :

Answer: B) Rs.17,500 Explanation: Let’s assume John bought the laptop for Rs. 100He then sells it to Mark at a loss of 20% => Rs. 80,Who consequently sells it to Kevin at a profit of 25% =>  Rs. 100Then, Kevin sells it back to Mark for Rs. 90 (Rs.4.50 for every Rs. 5 that he had paid initially), so he suffers a loss of Rs. 10Therefore, for Rs. 100 there is a loss of Rs. 10,Then for Rs. 1,75,000 there will be a loss of Rs. 17,500.

प्र: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 4008 0

  • 1
    7 : 12
    सही
    गलत
  • 2
    8 : 13
    सही
    गलत
  • 3
    9 : 4
    सही
    गलत
  • 4
    2 : 5
    सही
    गलत
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उत्तर : 2. "8 : 13"
व्याख्या :

Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13

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उत्तर : 2. "30 min"
व्याख्या :

Answer: B) 30 min Explanation: Distance travelled by Ramu = 45 x 4 = 180 km Somu travelled the same distance in 6 hours. His speed = 180/6 = 30 km/hr Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr. Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively. Hence difference in the time taken = 0.5 hours = 30 minutes.

प्र: What is the main component of biogas and natural gas? 4005 0

  • 1
    Carbon dioxide
    सही
    गलत
  • 2
    Butane
    सही
    गलत
  • 3
    Hydrogen Sulphide
    सही
    गलत
  • 4
    Methane
    सही
    गलत
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उत्तर : 4. "Methane"
व्याख्या :

Answer: D) Methane Explanation: Methane is the main component of biogas and natural gas.

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