IIT JEE प्रश्न और उत्तर का अभ्यास करें
8प्र: Movement of cell against concentration gradient is called 3449 05b5cc696e4d2b4197774c565
5b5cc696e4d2b4197774c565- 1active transporttrue
- 2diffusionfalse
- 3osmosisfalse
- 4passive transportfalse
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उत्तर : 1. "active transport"
व्याख्या :
Answer: A) active transport Explanation: The only transport method that can move species against their concentration gradient i.e, from low to high concentration is called Active transport. Facilitated diffusion only moves species down their concentration gradient i.e, from high to low concentration.
प्र: The main function of a school board is to 3448 05b5cc651e4d2b4197774bd2d
5b5cc651e4d2b4197774bd2d- 1manage public schools in accordance with state and federal law.true
- 2raise revenue for public schools through local taxes and fees.false
- 3propose and legislate state laws that affect the public schools.false
- 4serve as a school’s principals, teachers, and administrators.false
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उत्तर : 1. "manage public schools in accordance with state and federal law."
व्याख्या :
Answer: A) manage public schools in accordance with state and federal law. Explanation: The main function of a school board is to manage public schools in accordance with state and federal law. The functions of the school board of a public school are: • to establish strategic direction and priorities for the school. • to monitor and review school performance and to report on it to the Director-General, parents of students at the school and staff. • to develop, maintain and review curriculum for the school. • to develop and review education policies at the school. • to establish budgetary policies for the school and approve the school budget. • to establish policies for the efficient and effective use of school assets and the management of financial risk. • to develop relationships between the school and the community and between the school and community organisations. • to make recommendations to the Director-General on issue affecting the school and to give effect to the Director-General’s directions. • to encourage parent participation in their children’s learning; and • to exercise any other function given to the board under this Act or any otherTerritory law.
प्र: Fumble is to Finesse as Malign is to 3447 05b5cc6a2e4d2b4197774cba8
5b5cc6a2e4d2b4197774cba8- 1Slanderfalse
- 2Extoltrue
- 3Criticizefalse
- 4Assurancefalse
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उत्तर : 2. "Extol"
व्याख्या :
Answer: B) Extol Explanation: Fumble means grope, mishandle, drop, mistake, blunder, bungle. Finesse means skill, grace, elegance, assurance, diplomacy, discretion. So, they are opposites. Similarly, Malign means slander or criticize. Extol means being kind or good-natured. A person without finesse often fumbles. A person without extol in his heart often maligns. Extol means praise or exalt, benevolence
प्र: What is the value of P in the following Equation ? 192.5 × 19p = 197 3446 15b5cc6bee4d2b4197774d9a6
5b5cc6bee4d2b4197774d9a6- 13.9false
- 24.1false
- 33.7false
- 44.5true
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उत्तर : 4. "4.5"
व्याख्या :
Answer: D) 4.5 Explanation: Given equation is 192.5 ×19p = 197 Here it is in the form of am × an = am+n Here m = 2.5 , n = p, m+n = 7 => 2.5 + p = 7 => p = 7 - 2.5 => p = 4.5
प्र: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3439 05b5cc731e4d2b4197774f7b5
5b5cc731e4d2b4197774f7b5- 11:3false
- 22:1false
- 33:2true
- 42:3false
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उत्तर : 3. "3:2"
व्याख्या :
Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.
प्र: Solve the Riddle :: Three men were on a boat that was stuck one mile from the shore. One was afraid of Sharks. The other couldn't Swim. And the last one didn't have a life jacket. However, they reached the shore without any problems. How did they do it? 3435 05b5cc69fe4d2b4197774c9dc
5b5cc69fe4d2b4197774c9dc- उत्तर देखेंउत्तर छिपाएं
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उत्तर :
व्याख्या :
They walked and did this. It was never specified that the boat was at sea. Since this logic is observed by them to tackle situation.
प्र: Which of the following statements about Australian football is TRUE? 3433 05b5cc651e4d2b4197774bce0
5b5cc651e4d2b4197774bce0- 1Goals are scored by kicking the ball through goal posts.true
- 2Each team has a number of set plays for both offense and defense.false
- 3Constant movement of the ball is similar to baseball.false
- 4The players tend to wear a large amount of padding.false
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उत्तर : 1. "Goals are scored by kicking the ball through goal posts."
व्याख्या :
Answer: A) Goals are scored by kicking the ball through goal posts. Explanation:
प्र: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3431 05b5cc6e5e4d2b4197774ed42
5b5cc6e5e4d2b4197774ed42- 1127.5 mtrue
- 2254 mfalse
- 3184 mfalse
- 4212 mfalse
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उत्तर : 1. "127.5 m"
व्याख्या :
Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.

