IIT JEE Practice Question and Answer

Q: Movement of cell against concentration gradient is called 3569 0

  • 1
    active transport
    Correct
    Wrong
  • 2
    diffusion
    Correct
    Wrong
  • 3
    osmosis
    Correct
    Wrong
  • 4
    passive transport
    Correct
    Wrong
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Answer : 1. "active transport"
Explanation :

Answer: A) active transport Explanation: The only transport method that can move species against their concentration gradient i.e, from low to high concentration is called Active transport.   Facilitated diffusion only moves species down their concentration gradient i.e, from high to low concentration.

Q: The longest ship canal in the world is the 3568 0

  • 1
    Suez canal, Egypt
    Correct
    Wrong
  • 2
    Kiel canal, Germany
    Correct
    Wrong
  • 3
    Panama canal, Central America
    Correct
    Wrong
  • 4
    St. Laurence Seaway (USA and Canada)
    Correct
    Wrong
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Answer : 4. "St. Laurence Seaway (USA and Canada)"
Explanation :

Answer: D) St. Laurence Seaway (USA and Canada) Explanation:

Q: Find the odd one out of the following options. 3565 0

  • 1
    Sapphire
    Correct
    Wrong
  • 2
    Ruby
    Correct
    Wrong
  • 3
    Topaz
    Correct
    Wrong
  • 4
    Granite
    Correct
    Wrong
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Answer : 4. "Granite"
Explanation :

Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.

Q: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3558 0

  • 1
    127.5 m
    Correct
    Wrong
  • 2
    254 m
    Correct
    Wrong
  • 3
    184 m
    Correct
    Wrong
  • 4
    212 m
    Correct
    Wrong
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Answer : 1. "127.5 m"
Explanation :

Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.

Q: छाया क्षेत्र मौजूद है क्योंकि 3556 0

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Answer :
Explanation :

छाया क्षेत्र किसी दिए गए भूकंप से १०४ से १४० डिग्री की कोणीय दूरी से पृथ्वी का वह क्षेत्र है जिसे कोई सीधी पी तरंगें प्राप्त नहीं होती हैं। छाया क्षेत्र S तरंगों के तरल कोर द्वारा पूरी तरह से बंद होने और P तरंगों के तरल कोर द्वारा मुड़े (अपवर्तित) होने के परिणामस्वरूप होता है। शैडो ज़ोन दो प्रकार के होते हैं: एक P तरंगों के लिए और दूसरा S तरंगों के लिए। पी तरंग छाया 104-140 डिग्री, दोनों तरफ; S तरंग छाया एक तरफ के 105 से दूसरी तरफ 105 तक।

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Answer :
Explanation :

They walked and did this. It was never specified that the boat was at sea. Since this logic is observed by them to tackle situation.

Q: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ? 3554 0

  • 1
    145
    Correct
    Wrong
  • 2
    165
    Correct
    Wrong
  • 3
    175
    Correct
    Wrong
  • 4
    135
    Correct
    Wrong
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Answer : 3. "175"
Explanation :

Answer: C) 175 Explanation: Given that,  working days = 5  working hours = 8  A man get rupess per hour is Rs.2.40  So in one day the man get total rupees is 2.40 x 8 = 19.2  So in 5 days week the man get total rupees is 19.2 x 5 = 96  So in 4 week the man get total rupees is 96 x 4 = 384  So the man worked for = 160hours in 4 weeks    But given that the man earned Rs.432    Hence remaning money is (432-384 = 48)which is earn by doing overtime work   Overtime hours  = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.

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Answer : 3. "J"
Explanation :

Answer: C) J Explanation: Given word is TIRADESNow the consonants T, R, D, S are replaced by S, Q, C, RAnd Vowels are I, A, E are replaced by J, B and FThey are arranged alphabeticallyNew word is BCFJQRS The fourth letter from the right end is J.

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