IIT JEE рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: If (89)2┬аis added to the square of a number, the answer so obtained is 16202. What is the┬а(1/26) of that number? 3371 05b5cc6bde4d2b4197774d947
5b5cc6bde4d2b4197774d947- 15.65false
- 22.7false
- 33.5true
- 46.66false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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- SingleChoice
рдЙрддреНрддрд░ : 3. "3.5"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 3.5 Explanation: Let the number is = x (89)2┬а+ x2┬а= 16202 x2┬а= 8281 x = 91 => (1/26) of 91 = 3.5
рдкреНрд░: What is 90 days from today? ┬а Hints : Today is 20th January 2017, Sunday 3356 05b5cc6b5e4d2b4197774d516
5b5cc6b5e4d2b4197774d516- 118th April, Fridayfalse
- 220th April, Saturdaytrue
- 321th April, Sundayfalse
- 419th April, Saturdayfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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- SingleChoice
рдЙрддреНрддрд░ : 2. "20th April, Saturday"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 20th April, Saturday Explanation: Given Today is┬а20th January 2017, Sunday In january, we have 31 days February - 28 days (Non leap year) March - 31 days April - 30 days => Remaining days => 31 - 20 = 11 in Jan + 28 in Feb + 31 in Mar = 11 + 28 + 31 = 70 days More 20 days to complete 90 days => upto 20th April ┬а Therefore, after 90 days from today i.e, 20th Jan 2017 is 20th Apr 2017. ┬а Now, the day of the week will be┬а 90/7 => Remainder '6' As the day starts with '0' on sunday┬а 6 => Saturday. ┬а Required day is 20th April, Saturday.
рдкреНрд░: A does half as much work as Band C does half as much work as A and B together. If C alone can finish the work in 40 days, then together ,all will finish the work in ┬а? 3352 05b5cc728e4d2b4197774f714
5b5cc728e4d2b4197774f714- 117 + 4/7 daysfalse
- 213 + 1/3 daystrue
- 315 + 3/2 daysfalse
- 416 daysfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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- SingleChoice
рдЙрддреНрддрд░ : 2. "13 + 1/3 days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 13 + 1/3 days Explanation: C alone can finish the work in 40 days.As given C does half as much work as A and B together => (A + B) can do it in 20 days(A + B)s 1 days wok = 1/20.A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)A's 1 dayтАЩs work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]B's 1 days work = (1/20) x (2/3) = 1/30(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40 All the three together will finish it in 40/3 = 13 and 1/3 days.
рдкреНрд░: Chipko movement was basically against 3348 05b5cc6a4e4d2b4197774cc76
5b5cc6a4e4d2b4197774cc76- 1Cultural pollutionfalse
- 2Deforestationtrue
- 3Water pollutionfalse
- 4Noise pollutionfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "Deforestation"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) Deforestation Explanation: The Chipko movement or Chipko Andolan refers to a forest conservation movement or deforestation. In modern india, it began in 1973 in the state of Uttar Pradesh (now Uttarakhand). Sunderlal Bahuguna and 84 villagers risked their lives to protect the forest trees from being felled on the order of the maharaja (king) and went on to become a rallying point for many future environmental movements all over the world it created a precedent for starting of nonviolent protest in India, and its success meant that the world immediately took notice of this non violent movement, which was to inspire in time many such eco-groups by helping to slow down the rapid deforestation, expose vested interests, increase ecological awareness, and demonstrate the viability of people power. Above all, it stirred up the existing civil society in India, which began to address the issues of tribal and marginalized people. ┬а Chipko type movement dates back to 1730 AD when in a khejarli village of Rajasthan, 363 people sacrificed their lives to save khejari trees.
рдкреНрд░: _ tu _ rt _ s _ _ usrtu _ 3348 05b5cc6d9e4d2b4197774e843
5b5cc6d9e4d2b4197774e843- 1rsutrrfalse
- 2rsurtrfalse
- 3rsurtstrue
- 4rtusrufalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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- SingleChoice
рдЙрддреНрддрд░ : 3. "rsurts"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) rsurts Explanation: The series rtus/rtus/rtus/rtus. Thus, the pattern 'rtus' is repeated.
рдкреНрд░: Tennis rackets and ballpoint pens are 3345 05b5cc60ae4d2b4197774b5ab
5b5cc60ae4d2b4197774b5ab- 1complementary goodsfalse
- 2independent goodstrue
- 3inferior goodsfalse
- 4substitute goodsfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "independent goods"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) independent goods Explanation: Tennis rackets and ballpoint pens are two independent goods. Since, one doesn't depend on the other.
рдкреНрд░: A large tanker can be filled by two pipes A and B in 60 and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half ? 3344 05b5cc6dce4d2b4197774e9ab
5b5cc6dce4d2b4197774e9ab- 131 minfalse
- 229 minfalse
- 328 minfalse
- 430 mintrue
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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- SingleChoice
рдЙрддреНрддрд░ : 4. "30 min"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 30 min Explanation: Part filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24Suppose the tank is filled in x minutes.Then, x/2(1/24 + 1/40) = 1(x/2) * (1/15) = 1 => x = 30 min.
рдкреНрд░: V-RAM рдХрд╛ рдкреНрд░рдпреЛрдЧ рдирд┐рдореНрди рдореЗрдВ рд╕реЗ рдХрд┐рд╕рдХреА рдкрд╣реБрдБрдЪ рдХреЗ рд▓рд┐рдП рдХрд┐рдпрд╛ рдЬрд╛рддрд╛ рд╣реИ ? 3343 35b5cc6c3e4d2b4197774dc5e
5b5cc6c3e4d2b4197774dc5e- 1рдкреНрд░реЛрдЧреНрд░рд╛рдоfalse
- 2рд╡реАрдбрд┐рдпреЛ рдФрд░ рдЧреНрд░рд╛рдлрд┐рдХреНрд╕true
- 3рдЯреЗрдХреНрд╕реНрдЯ рдФрд░ рдЗрдореЗрдЬfalse
- 4рд╕рднреАfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "рд╡реАрдбрд┐рдпреЛ рдФрд░ рдЧреНрд░рд╛рдлрд┐рдХреНрд╕"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B)рд╡реАрдбрд┐рдпреЛ рдФрд░ рдЧреНрд░рд╛рдлрд┐рдХреНрд╕ рд╕реНрдкрд╖реНрдЯреАрдХрд░рдг: рд╡реАрдЖрд░рдПрдПрдо рдпрд╛ (рд╡реАрдбрд┐рдпреЛ рд░реИрдо), рдХрд┐рд╕реА рднреА рдкреНрд░рдХрд╛рд░ рдХреА рд░реИрдВрдбрдо рдПрдХреНрд╕реЗрд╕ рдореЗрдореЛрд░реА (рд░реИрдо) рдХреЗ рд╕рдВрджрд░реНрдн рдореЗрдВ рдбрд╛рдпрдирд╛рдорд┐рдХ рд░реИрдо (рдбреАрдЖрд░рдПрдПрдо) рдХрд╛ рдПрдХ рджреЛрд╣рд░реЗ рдкреЛрд░реНрдЯ рд╡рд╛рд▓рд╛ рд╕рдВрд╕реНрдХрд░рдг рд╣реИ, рдЬрд┐рд╕рдХрд╛ рдЙрдкрдпреЛрдЧ рдЧреНрд░рд╛рдлрд┐рдХреНрд╕ рдПрдбреЗрдкреНрдЯрд░ рдореЗрдВ рдлреНрд░реЗрдордмрдлрд░ рдХреЛ рд╕реНрдЯреЛрд░ рдХрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдХрд┐рдпрд╛ рдЬрд╛рддрд╛ рд╣реИред

