IIT JEE рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: Which city is located on the banks of the river Mula-Mutha? 3187 05b5cc6b1e4d2b4197774d309
5b5cc6b1e4d2b4197774d309- 1Punetrue
- 2Nagpurfalse
- 3Ahmedabadfalse
- 4Suratfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "Pune"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) Pune Explanation: The Mula-Mutha is a river in India, formed by the confluence of the Mula and Mutha rivers in the city of Pune, which later meets the Bhima River, which itself later meets the Krishna River and finally emptying to the Bay of Bengal.
рдкреНрд░: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ┬а? 3185 05b5cc6dee4d2b4197774ea79
5b5cc6dee4d2b4197774ea79- 12413 sq.mfalse
- 21234 sq.mfalse
- 34312 sq.mtrue
- 42143 sq.mfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "4312 sq.m"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 4312 sq.m Explanation: Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.┬а┬а ┬а2╧Аs = 264 and┬а2╧Аl = 352┬а┬а ┬а ┬аs =┬а2642╧А and l =┬а3522╧А┬а┬а┬а Difference between the areas =╧Аl2-╧Аs2┬а┬а┬а ┬а┬а=┬а╧А1762╧А2-1322╧А2┬а ┬а┬а= 1762╧А-1322╧А┬а┬а ┬а = (176 - 132)(176 + 132) /┬а╧А┬а┬а ┬а = (44 x 308) / (22/7) = 4312 sq.m
рдкреНрд░: Count the number of triangles and squares in the given figure. 3182 05b5cc7b0e4d2b41977750826
5b5cc7b0e4d2b41977750826- 136 triangles, 7 Squaresfalse
- 238 triangles, 9 Squaresfalse
- 340 triangles, 7 Squarestrue
- 442 triangles, 9 Squaresfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "40 triangles, 7 Squares"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 40 triangles, 7 Squares Explanation: The figure may be labelled as shown┬а ┬а ┬а Triangles : ┬а The Simplest triangles are BGM, GHM, HAM, ABM, GIN, IJN, JHN, HGN, IKO, KLO, LJO, JIO, KDP, DEP, ELP, LKP, BCD and AFE i.e 18 in number ┬а The triangles composed of two components each are ABG, BGH, GHA, HAB, HGI, GIJ, IJH, JHG, JIK, IKL, KLJ,LJI, LKD, KDE, DEL and ELK i.e 16 in number. ┬а The triangles composed of four components each are BHI, GJK, ILD, AGJ, HIL and JKE i.e 6 in number. ┬а Total number of triangles in the figure = 18 + 16 + 6 =40. ┬а Squares : ┬а The Squares composed of two components each are MGNH, NIOJ, and OKPL i.e 3 in number ┬а The Squares composed of four components each are BGHA, GIJH, IKJL and KDEL i.e 4 in number ┬а Total number of squares in the figure = 3 + 4 =7
рдкреНрд░: Directions: A string of words is fed into a computing machine. It processes the input and gives an output in the following manner: Input: Honesty is the best policy. Step 1: is Honesty the best policy Step 2: is the Honesty best policy Step 3: is the best Honesty policy Step 4: is the best policy Honesty Output: is the best policy Honesty Now, If the input is "A rolling stone gathers no moss", what will be the fifth word in the string after 4 steps? 3180 05b5cc6bde4d2b4197774d8f2
5b5cc6bde4d2b4197774d8f2- 1Mossfalse
- 2Nofalse
- 3Stonefalse
- 4Atrue
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "A"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) A Explanation: For the input "A rolling stone gathers no moss", the steps followed are: Step 1: rolling A stone gathers no moss Step 2: rolling stone A gathers no moss Step 3: rolling stone gathers A no moss Step 4: rolling stone gathers no A moss ┬а After 4 steps the fifth word is "A".
рдкреНрд░: рдПрдХреНрд╕реЗрд▓ рд╡рд░реНрдХрдмреБрдХ рдХрд┐рд╕рдХрд╛ рд╕рдВрдЧреНрд░рд╣ рд╣реИ? 3179 15b5cc636e4d2b4197774b9f5
5b5cc636e4d2b4197774b9f5- 1рдЪрд╛рд░реНрдЯfalse
- 2рд╡рд░реНрдХрд╕реАрдЯfalse
- 3рджреЛрдиреЛ A & Bfalse
- 4рдЗрдирдореЗ рд╕реЗ рдХреЛрдИ рднреА рдирд╣реАрдВtrue
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "рдЗрдирдореЗ рд╕реЗ рдХреЛрдИ рднреА рдирд╣реАрдВ"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) рджреЛрдиреЛ A & B рд╡реНрдпрд╛рдЦреНрдпрд╛: рдПрдордПрд╕ рдПрдХреНрд╕реЗрд▓ рд╡рд░реНрдХрдмреБрдХ рд╡рд░реНрдХрд╢реАрдЯ рдФрд░ рдЪрд╛рд░реНрдЯ рджреЛрдиреЛрдВ рдХрд╛ рдПрдХ рд╕рдВрдЧреНрд░рд╣ рд╣реИред
рдкреНрд░: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest ? 3179 05b5cc6ebe4d2b4197774eeb9
5b5cc6ebe4d2b4197774eeb9- 120% p.atrue
- 215% p.afalse
- 318% p.afalse
- 424% p.afalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "20% p.a"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 20% p.a Explanation: Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year. Rate of interest = (100 x 240) / (1200) = 20% p.a
рдкреНрд░: A batsman scores 26 runs and increases his average from 14 to 15. Find the runs to be made if he wants top increasing the average to 19 in the same match ? 3174 05b5cc745e4d2b4197774fa22
5b5cc745e4d2b4197774fa22- 174true
- 279false
- 372false
- 460false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "74"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 74 Explanation: Number of runs scored more to increse the ratio by 1 is 26 - 14 = 12To raise the average by one (from 14 to 15), he scored 12 more than the existing average.Therefore, to raise the average by five (from 14 to 19), he should score 12 x 5 = 60 more than the existing average. Thus he should score 14 + 60 = 74.
рдкреНрд░: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 3170 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "9:1"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters ┬а If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. ┬а Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters ┬а 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. ┬а The ratio of milk and water in the new mixture = 16:4 = 4:1 ┬а If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. ┬а Amount of water removed = 2 liters. ┬а Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. ┬а Now 10 lts milk is added => total milk = 18 lts ┬а The required ratio of milk and water in the final mixture obtained ┬а = (8 + 10):2 = 18:2 = 9:1.

