Answer: A) Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840 Explanation: Initial investment of Ram = Rs.2500.After 2 months he withdraw Rs.1250 from his capital.Therefore, we have, Ram invested Rs.2500 for 2 months and Rs.(2500-1250=) 1250 for 4 months. Raj invested Rs. 2250 for 3 months and Rs.(2250-750=) 1500 for 3 months. And, Rakesh invested Rs.3500 for 3 months; Their investing ratio:Ram:Raj:Rakesh = (2500x2 + 1250x4):(2250x3 + 1500x3):(3500x3)= (10,000):(11,250):(10,500) = 1000:1125:1050 = 40:45:42 Total profit for 6 months = Rs.2540Therefore, Ram's share = Rs.(2540 x 40/(40+45+42)) = Rs.(2540 x 40/127) = Rs.800Raj's share = Rs.(2540 x 45/127) = Rs.900Rakesh's share = Rs.(2540 x 42/127) = Rs.840

Answer: D) 437 Explanation: The series follow the rule,   21 = 77 = 92-4165 = 132-4285 = 172-4 5,9,13,17,21,(+4)...In the same way next no. will be 212-4 = 441 - 4 = 437

Answer: C) 9 Explanation: There were all parrots but six means that six birds were not parrots but only pigeons and koels. Similarly, number of parrots + number of koels = 6 and number of parrots + number of pigeons = 6. This is possible when there are 3 parrots, 3 pigeons and 3 koels i.e. 9 birds in all.

Answer: B) VIJ Explanation: First letter series S,T,U,Vsecond and third letter series CD,EF,GH,IJ...so answer = VIJ

Answer: C) 102 men Explanation: From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2) so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)] so, M = 136 men   Number of men to be added to finish the work = 136-34 = 102 men.

Answer: A) बड़ी संख्या में सेल स्पष्टीकरण: कंप्यूटिंग में, मेमोरी कंप्यूटर हार्डवेयर एकीकृत सर्किट को संदर्भित करता है जो कंप्यूटर में तत्काल उपयोग के लिए जानकारी संग्रहीत करता है। अधिकांश सेमीकंडक्टर मेमोरी को मेमोरी सेल या बिस्टेबल फ्लिप-फ्लॉप में व्यवस्थित किया जाता है, प्रत्येक एक बिट (0 या 1) को स्टोर करता है।

A fire grows when it eats but dies when it drinks.

Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters   If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.   Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters   10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.   The ratio of milk and water in the new mixture = 16:4 = 4:1   If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters.   Amount of water removed = 2 liters.   Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters.   Now 10 lts milk is added => total milk = 18 lts   The required ratio of milk and water in the final mixture obtained   = (8 + 10):2 = 18:2 = 9:1.