IIT JEE प्रश्न और उत्तर का अभ्यास करें
8प्र: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ? 3015 05b5cc6e7e4d2b4197774edb0
5b5cc6e7e4d2b4197774edb0- 11900true
- 22100false
- 31700false
- 42000false
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उत्तर : 1. "1900"
व्याख्या :
Answer: A) 1900 Explanation: Given 2000 ---- 54 days The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days. i.e, 2000 ----- 39 days == m ---- 20 days => m x 20 = 2000 x 39 m = 3900 So total men for 20 days is 3900 => 2000 old and 1900 new reinforcement. Hence, reinforcement = 1900.
प्र: Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ? 3015 05b5cc6c2e4d2b4197774dba5
5b5cc6c2e4d2b4197774dba5- 117 yearsfalse
- 213 yearstrue
- 314 yearsfalse
- 416 yearsfalse
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उत्तर : 2. "13 years"
व्याख्या :
Answer: B) 13 years Explanation: Given R + S + M + D = 76 => R+7 : S+7 : M+7 : D+7 = 7:6:5:8 => Let the ratio = x => M+7 = 5x => M = 5x-7 => R = 7x-7 => S = 6x-7 => D = 8x-7 => R + S + M + D = 76 => 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76 => 26x - 28 = 76 => 26x = 104 => x = 4 => Mahesh's present age = 5x-7 = 20 - 7 = 13 years.
प्र: एक्सेल वर्कबुक किसका संग्रह है? 3014 15b5cc636e4d2b4197774b9f5
5b5cc636e4d2b4197774b9f5- 1चार्टfalse
- 2वर्कसीटfalse
- 3दोनो A & Bfalse
- 4इनमे से कोई भी नहींtrue
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उत्तर : 4. "इनमे से कोई भी नहीं"
व्याख्या :
Answer: C) दोनो A & B व्याख्या: एमएस एक्सेल वर्कबुक वर्कशीट और चार्ट दोनों का एक संग्रह है।
प्र: Find the odd one out of the floowing number series? 270, 261, 279, 252, 289, 243 3013 05b5cc639e4d2b4197774ba8c
5b5cc639e4d2b4197774ba8c- 1270false
- 2279false
- 3289true
- 4243false
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उत्तर : 3. "289"
व्याख्या :
Answer: C) 289 Explanation: Here the given number series is 270, 261, 279, 252, 289, 243 270 - 9 = 261 261 + 18 = 279 279 - 27 = 252 252 + 36 = 288 (not equals to 289) 288 - 45 = 243 Hence, the odd number in the given number series is 289.
प्र: A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ? 3012 05b5cc720e4d2b4197774f613
5b5cc720e4d2b4197774f613- 145false
- 224false
- 342false
- 454true
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उत्तर : 4. "54"
व्याख्या :
Answer: D) 54 Explanation: By trial and error method from the given options, as 54 - 45 = (1/11) x (45+54) = 99/11 = 9 Hence this satisfies the given conditions. Then the woman's husband age is 54.
प्र: What will come in place of question mark(?) in the following number series ? 6859 5832 ? 4096 3375 3008 05b5cc6c0e4d2b4197774db1e
5b5cc6c0e4d2b4197774db1e- 14589false
- 24913true
- 35013false
- 45169false
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उत्तर : 2. "4913"
व्याख्या :
Answer: B) 4913 Explanation: The given series follows a pattern that, 19 x 19 x 19 = 6859 18 x 18 x 18 = 5832 17 x 17 x 17 = 4913 16 x 16 x 16 = 4096 15 x 15 x 15 = 3375 So, the missing number in the given series = 4913
प्र: Genetic alteration probably refers to altering what 3006 05b5cc60de4d2b4197774b5dc
5b5cc60de4d2b4197774b5dc- 1Genes found on ribosomesfalse
- 2Genes found on chromosomestrue
- 3Genes found on cytoplasmfalse
- 4All of the abovefalse
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उत्तर : 2. "Genes found on chromosomes"
व्याख्या :
Answer: B) Genes found on chromosomes Explanation: Genetic alteration probably refers to altering Genes found on chromosomes. Genetic alteration refers to altering DNA sequence. Gene alteration forms genetically modified products that modifies the gene sequence. Genetic engineering, also called genetic modification or genetic manipulation, is the direct manipulation of an organism's genes using biotechnology.
प्र: What holds the sides of the DNA ladder together? 3001 05b5cc69ae4d2b4197774c78c
5b5cc69ae4d2b4197774c78c- 1Polar covalent bondsfalse
- 2Ionic bondsfalse
- 3Metallic bondsfalse
- 4Covalent bondstrue
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उत्तर : 4. "Covalent bonds"
व्याख्या :
Answer: D) Covalent bonds Explanation: Deoxyribose, which is a pentose, and a phosphate group are the two molecules together form the two sides of the DNA i.e, A sugar (deoxyribose) and a phosphate. DNA is a double-stranded molecule twisted into a helix (think of a spiral staircase). Each spiraling strand, comprised of a sugar-phosphate backbone and attached bases, is connected to a complementary strand by non-covalent hydrogen bonding between paired bases. The bases are adenine (A), thymine (T), cytosine (C) and guanine (G). A and T are connected by two hydrogen bonds. G and C are connected by three hydrogen bonds.

