IIT JEE Practice Question and Answer
8Q: Count the number of triangles and squares in the given figure. 3449 05b5cc7b0e4d2b41977750826
5b5cc7b0e4d2b41977750826- 136 triangles, 7 Squaresfalse
- 238 triangles, 9 Squaresfalse
- 340 triangles, 7 Squarestrue
- 442 triangles, 9 Squaresfalse
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Answer : 3. "40 triangles, 7 Squares"
Explanation :
Answer: C) 40 triangles, 7 Squares Explanation: The figure may be labelled as shown Triangles : The Simplest triangles are BGM, GHM, HAM, ABM, GIN, IJN, JHN, HGN, IKO, KLO, LJO, JIO, KDP, DEP, ELP, LKP, BCD and AFE i.e 18 in number The triangles composed of two components each are ABG, BGH, GHA, HAB, HGI, GIJ, IJH, JHG, JIK, IKL, KLJ,LJI, LKD, KDE, DEL and ELK i.e 16 in number. The triangles composed of four components each are BHI, GJK, ILD, AGJ, HIL and JKE i.e 6 in number. Total number of triangles in the figure = 18 + 16 + 6 =40. Squares : The Squares composed of two components each are MGNH, NIOJ, and OKPL i.e 3 in number The Squares composed of four components each are BGHA, GIJH, IKJL and KDEL i.e 4 in number Total number of squares in the figure = 3 + 4 =7
Q: स्मृति से बनी होती है 3447 15b5cc651e4d2b4197774bd14
5b5cc651e4d2b4197774bd14- 1कोशिकाओं की बड़ी संख्याtrue
- 2तारों का सेटfalse
- 3सर्किट का सेटfalse
- 4इनमे से कोई भी नहींfalse
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Answer : 1. "कोशिकाओं की बड़ी संख्या"
Explanation :
Answer: A) बड़ी संख्या में सेल स्पष्टीकरण: कंप्यूटिंग में, मेमोरी कंप्यूटर हार्डवेयर एकीकृत सर्किट को संदर्भित करता है जो कंप्यूटर में तत्काल उपयोग के लिए जानकारी संग्रहीत करता है। अधिकांश सेमीकंडक्टर मेमोरी को मेमोरी सेल या बिस्टेबल फ्लिप-फ्लॉप में व्यवस्थित किया जाता है, प्रत्येक एक बिट (0 या 1) को स्टोर करता है।
Q: How many number of weights do you need to weight 31 kg of Rice if you have one kg of weight stone ? 3445 05b5cc736e4d2b4197774f879
5b5cc736e4d2b4197774f879- 13false
- 25true
- 37false
- 49false
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Answer : 2. "5"
Explanation :
Answer: B) 5 Explanation: There are total 5 ways.we have only one kg of weight so,2kg = 1kg + 1kg4kg = 1 + 2 + 18kg = 1 + 2 + 4 + 116kg = 1 + 2 + 4 + 8 + 131kg = 1 + 2 + 4 + 8 + 16So 5 weights are needed.
Q: The basic operations performed by a computer are 3441 05b5cc651e4d2b4197774bcea
5b5cc651e4d2b4197774bcea- 1Logical operationfalse
- 2Storage and relativefalse
- 3Arithmetic operationfalse
- 4All the abovetrue
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Answer : 4. "All the above"
Explanation :
Answer: D) All the above Explanation: The basic operations performed by a computer are Arithmetic operation, Logical operation and Storage and relative.
Q: A merchant buys two items for Rs. 7500. One item he sells at a profit of 16% and the other item at 14% loss. In the deal, the merchant makes neither any profit nor any loss. What is the difference between the selling price of both the items? 3433 05b5cc69de4d2b4197774c88d
5b5cc69de4d2b4197774c88d- 1Rs. 620true
- 2Rs. 654false
- 3Rs. 725false
- 4Rs. 747false
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Answer : 1. "Rs. 620"
Explanation :
Answer: A) Rs. 620 Explanation: Let the C.P of one item is Rs. P and that of other is Rs. (7500 - P) According to the data given C.P = S.P => Px(116/100) + (7500-P)x(86/100) = 7500 => 30P = 105000 => P = 3500 Required difference between selling prices = Rs. [(3500/100) x 116] - [(4000/100) x 86] = 4060-3440 = Rs. 620
Q: Cube root of 729 then square it 3430 05b5cc658e4d2b4197774bdf7
5b5cc658e4d2b4197774bdf7- 19false
- 236false
- 381true
- 4144false
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Answer : 3. "81"
Explanation :
Answer: C) 81 Explanation: 729 = 9 x 9 x 9 => Cube root of 729 = 9 Now, required square of 9 = 9 x 9 = 81.
Q: The main goal for farmers in 1900 was to 3426 05b5cc672e4d2b4197774c0d8
5b5cc672e4d2b4197774c0d8- 1Force the railroads to lower freight ratesfalse
- 2Enable them to pay back their loans more easilyfalse
- 3Hold on to political and economic power.true
- 4voters greater direct participation in governmentfalse
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Answer : 3. "Hold on to political and economic power."
Explanation :
Answer: C) Hold on to political and economic power. Explanation:
Q: The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ? 3424 05b5cc6c6e4d2b4197774de59
5b5cc6c6e4d2b4197774de59- 112 yearstrue
- 210 yearsfalse
- 314 yearsfalse
- 413 yearsfalse
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Answer : 1. "12 years"
Explanation :
Answer: A) 12 years Explanation: Given the average age of couple and their son = 40 => Sum of age (H +W +S) = 40×3 Let the age of daughter in law at the time of marriage = D years Now after 10 years, (H + S +W) + 3×12 + D +12 + 10 = 38×5 178 + D = 190 D = 190 -178 = 12 years