IIT JEE Practice Question and Answer
8Q: If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ? 3072 15b5cc74ae4d2b4197774fabd
5b5cc74ae4d2b4197774fabd- 1Rs. 175false
- 2Rs. 325false
- 3Rs. 340true
- 4Rs. 260false
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Answer : 3. "Rs. 340"
Explanation :
Answer: C) Rs. 340 Explanation: Assume first child (the youngest) get = Rs. x According to the question ;each son having Rs. 30 more than the younger one Second child will get = Rs. x + 30 Third child will get = Rs. x + 30 + 30 = x + 60 Forth child will get = Rs. x + 30 + 30 + 30 = x + 90 Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120 Total amount they got = Rs. 2000 x + (x+30) + (x+60) + (x+90) + (x+120) = 20005x + 300 = 20005x = 1700x = Rs. 340So the youngest child will get Rs. 340.
Q: Tohra is the sacred book of 3070 05b5cc655e4d2b4197774bd37
5b5cc655e4d2b4197774bd37- 1Judaismtrue
- 2Confucianismfalse
- 3Zoroastrianismfalse
- 4Taoismfalse
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Answer : 1. "Judaism"
Explanation :
Answer: A) Judaism Explanation:
Q: If 15 men 4 hours per day works for 14 days get Rs.35/- then how many men required if the work is 8 hours per day for 10 days they get 50/- ? 3069 05b5cc754e4d2b4197774fb68
5b5cc754e4d2b4197774fb68- 112false
- 213false
- 314false
- 415true
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Answer : 4. "15"
Explanation :
Answer: D) 15 Explanation: We know M1×D1×H1W1 = M2×D2×H2W2 => 15×4×1435 = M×8×1050 => M = 15
Q: How many number of weights do you need to weight 31 kg of Rice if you have one kg of weight stone ? 3067 05b5cc736e4d2b4197774f879
5b5cc736e4d2b4197774f879- 13false
- 25true
- 37false
- 49false
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Answer : 2. "5"
Explanation :
Answer: B) 5 Explanation: There are total 5 ways.we have only one kg of weight so,2kg = 1kg + 1kg4kg = 1 + 2 + 18kg = 1 + 2 + 4 + 116kg = 1 + 2 + 4 + 8 + 131kg = 1 + 2 + 4 + 8 + 16So 5 weights are needed.
Q: Contour bunding is a method of soil conservation used in 3064 05b5cc68be4d2b4197774c37b
5b5cc68be4d2b4197774c37b- 1Scrublands, liable to spread of weed growthfalse
- 2Hilly and Slopy or mountain areastrue
- 3Low flat plains, close to stream courses, liable to floodingfalse
- 4Desert margins, liable to strong wind actionfalse
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Answer : 2. "Hilly and Slopy or mountain areas"
Explanation :
Answer: B) Hilly and Slopy or mountain areas Explanation: Contour bunding is a proven sustainable land management practice for mountainous areas, marginal, sloping, and hilly land where the soil productivity is very low. It is widely adopted by the ethnic minorities of Nepal who practice the shifting cultivation system of farming.
Q: In three coloured boxes - Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ? 3058 05b5cc71be4d2b4197774f544
5b5cc71be4d2b4197774f544- 176false
- 254true
- 364false
- 448false
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Answer : 2. "54"
Explanation :
Answer: B) 54 Explanation: Let R, G and B represent the number of balls in red, green and blue boxes respectively. Then, . R + G + B = 108 ...(i), G + R = 2B ...(ii) B = 2R ...(iii) From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R. Putting G = 3R and B = 2R in (i), we get: R + 3R + 2R = 108 6R = 108 R = 18. Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.
Q: When combining with nonmetallic atoms, metallic atoms generally will 3048 05b5cc64ae4d2b4197774bc11
5b5cc64ae4d2b4197774bc11- 1Lose electrons and forms cationstrue
- 2Gain electrons and forms anionsfalse
- 3Lose electrons and forms anionsfalse
- 4Gain electrons and forms cationsfalse
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Answer : 1. "Lose electrons and forms cations"
Explanation :
Answer: A) Lose electrons and forms cations Explanation: When combining with nonmetallic atoms, metallic atoms generally will Lose electrons and forms cations. As the ionization energy of te metals are very low, so they can easily lose electrons and form positively charged ion called cations.
Q: C U B A E D E D A B E B A U C D B C A D B D U B C A C B E D A If all the A's are dropped from the above arrangement, which of the following will be eleventh from the left end of the above arrangement? 3046 05b5cc7d2e4d2b419777512e0
5b5cc7d2e4d2b419777512e0- 1Efalse
- 2Cfalse
- 3Dfalse
- 4Utrue
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Answer : 4. "U"
Explanation :
Answer: D) U Explanation: If all the A's are dropped from the above arrangement, we get C U B E D E D B E B U C D B C D B D U B C C B E D. Here the eleventh from the left end of the above arrangement is U