Quantitative Aptitude Practice Question and Answer
8Q: Find the sum of the all the numbers formed by the digits 2,4,6 and 8 without repetition. Number may be of any of the form like 2,24,684,4862 ? 2116 05b5cc701e4d2b4197774f1bc
5b5cc701e4d2b4197774f1bc- 1133345false
- 2147320true
- 313320false
- 4145874false
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Answer : 2. "147320"
Explanation :
Answer: B) 147320 Explanation: Sum of 4 digit numbers = (2+4+6+8) x P33 x (1111) = 20 x 6 x 1111 = 133320 Sum of 3 digit numbers = (2+4+6+8) x P23 x (111) = 20 x 6 x 111 = 13320 Sum of 2 digit numbers = (2+4+6+8) x P13 x (11) = 20 x 3 x 11 = 660 Sum of 1 digit numbers = (2+4+6+8) x P03 x (1) = 20 x 1 x 1 = 20 Adding All , Sum = 147320
Q: K and L start a business jointly. L invests Rs.16000 for 8 months and L remains in the business for 4 months. Out of the total profit B claims 2/7th share. How much money is contributed by B ? 2114 05b5cc6e1e4d2b4197774ebe8
5b5cc6e1e4d2b4197774ebe8- 1Rs. 9040false
- 2Rs. 10,400false
- 3Rs. 12,800true
- 4Rs. 6350false
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Answer : 3. "Rs. 12,800"
Explanation :
Answer: C) Rs. 12,800 Explanation: 16x8 : Px4 = 5:2 P = 12.8 => Rs.12,800
Q: A cistern is normally filled in 8 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in ? 2113 05b5cc6e5e4d2b4197774ed2e
5b5cc6e5e4d2b4197774ed2e- 120 hrstrue
- 228 hrsfalse
- 336 hrsfalse
- 440 hrsfalse
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Answer : 1. "20 hrs"
Explanation :
Answer: A) 20 hrs Explanation: 1/8 - 1/x = 1/10 => x = 40 hrs
Q: Two persons K and L can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days ? 2111 05b5cc6d8e4d2b4197774e7aa
5b5cc6d8e4d2b4197774e7aa- 11/6true
- 21/3false
- 32/3false
- 41/18false
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Answer : 1. "1/6"
Explanation :
Answer: A) 1/6 Explanation: K's one day's work = 1/30 L's one day's work = 1/45 (K + L)'s one day's work = 1/30 + 1/45 = 1/18 The part of the work completed in 3 days = 3 (1/18) = 1/6.
Q: It costs Rs. p each to send the first thousand messsages and Rs. q to send each subsequent one . If r is greater than 1,000, how many Rupees will it cost to send r messages ? 2109 05b5cc6cfe4d2b4197774e2ef
5b5cc6cfe4d2b4197774e2ef- 11000 (r - p) + pqfalse
- 21000 p + qrfalse
- 31000 (r - q) + prfalse
- 41000(p - q) + qrtrue
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Answer : 4. "1000(p - q) + qr"
Explanation :
Answer: D) 1000(p - q) + qr Explanation: We need to find the total cost to send r messsages, r > 1000. The first 1000 messsages will cost Rs.p each (Or) The total cost of first 1000 messsages = Rs.1000p The remaining (r - 1000) messsages will cost Rs.q each (Or) The cost of the (r - 1000) = Rs.(r - 1000)y Therefore, total cost = 1000p + rq - 1000q = 1000(p - q) + qr
Q: If 6 men and 3 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time ? 2108 05b5cc6dae4d2b4197774e8d2
5b5cc6dae4d2b4197774e8d2- 11 : 2true
- 22 : 1false
- 33 : 1false
- 41 : 3false
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Answer : 1. "1 : 2"
Explanation :
Answer: A) 1 : 2 Explanation: 6M + 3B = 4(1M + 1B)6M + 3B = 4M + 4B2M = 1B M/B = 1/2
Q: A quantity of tea is sold at Rs. 5.75 per kilogram. The total gain by selling the tea at this rate is Rs. 60. Find the quantity of tea being sold if a profit of 15% is made on the deal ? 2108 05b5cc70ee4d2b4197774f332
5b5cc70ee4d2b4197774f332- 172 kgsfalse
- 280 kgstrue
- 376 kgsfalse
- 484 kgsfalse
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Answer : 2. "80 kgs"
Explanation :
Answer: B) 80 kgs Explanation: Say total cost price of tea is x.Then total profit at a rate of 15% is = (15x/100)According to question,15x/100 = 60so x = 400C.p of the tea is Rs. 400.so total selling price will be = (400+60) = Rs.460so the quantity of the tea will be = (460/5.75) = 80kg.
Q: How many meshes are there in 1 squrare meter of wire gauge if each mesh is 8mm long and 5mm wide ? 2107 05b5cc754e4d2b4197774fb58
5b5cc754e4d2b4197774fb58- 12500false
- 225000true
- 312500false
- 415400false
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Answer : 2. "25000"
Explanation :
Answer: B) 25000 Explanation: We know that, One square meter is equal to 10,00,000 sq mm.Given, each mesh is 8mm length and 5mm wideTherefore for each mesh : 8 x 5 = 40 sq mm.So, number of meshes = 100000040 = 25000.