Quantitative Aptitude Practice Question and Answer
8Q: Find the odd one out of the group ? 1996 05b5cc6e1e4d2b4197774ebca
5b5cc6e1e4d2b4197774ebca- 1708false
- 2392true
- 3618false
- 4816false
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Answer : 2. "392"
Explanation :
Answer: B) 392 Explanation: The sum of the digits in 708, 618 and 816 is 15, but not in 392.
Q: Three unbiased coins are tossed. What is the probability of getting at most two heads ? 1994 05b5cc764e4d2b4197774fd76
5b5cc764e4d2b4197774fd76- 14/3false
- 22/3false
- 33/2false
- 43/4true
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Answer : 4. "3/4"
Explanation :
Answer: D) 3/4 Explanation: Let S be the sample space.Here n(S)= 23 = 8Let E be the event of getting atmost two heads. Then,n(E) = {(H,T,T), (T,H,T), (T,T,H), (H,H,T), (T,H,H), (H,T,H)}Required probability = n(E)/n(S) = 6/8 = 3/4.
Q: Ali and Faizer are 27m apart. They both start walking and meet 9 hrs later, if they travel in the same direction and meet after 3 hrs if they walk in opposite dirction, Ali’s speed must most likely be ? 1993 05b5cc715e4d2b4197774f44f
5b5cc715e4d2b4197774f44f- 19 m/hfalse
- 23 m/hfalse
- 36 m/htrue
- 412 m/hfalse
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Answer : 3. "6 m/h"
Explanation :
Answer: C) 6 m/h Explanation: let, speed of Ali=X mph and Faizer=Y mph Now, relative speed when Ali is walking int the same direction with Faizer= (X-Y)mphhence, according to question, 27/(X-Y)=9 ; solving X-Y=3; --- (1) Now relative speed when walking in the opposite direction= (X+Y) mphhence, according to question, 27/(X+y)=3; solving X+Y=9; --- (2) solving 1 and 2 we get X=6 and Y=3, where X is the speed of Ali.
Q: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is ? 1992 05b5cc6d7e4d2b4197774e6e2
5b5cc6d7e4d2b4197774e6e2- 142 secfalse
- 244 secfalse
- 346 secfalse
- 448 sectrue
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Answer : 4. "48 sec"
Explanation :
Answer: D) 48 sec Explanation: Relative speed = 60 + 90 = 150 km/hr. = 150 x 5/18 = 125/3 m/sec. Distance covered = 1.10 + 0.9 = 2 km = 2000 m. Required time = 2000 x 3/125 = 48 sec.
Q: A work which could be finished in 11 days was finished 4 days earlier after 4 more men joined. The number of men employed was ? 1991 05b5cc6e1e4d2b4197774ebb6
5b5cc6e1e4d2b4197774ebb6- 17true
- 28false
- 39false
- 410false
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Answer : 1. "7"
Explanation :
Answer: A) 7 Explanation: As the work is sameM1D1 = M2D2 Here Let the number of men employed was M=> 11M = 7(M+4)=> 11M - 7M = 28=> M = 7
Q: If the average height of boys in a hall is 180 cm and that of girls is 150 cm. If the average height of the gathering is 165 cm, then find the number of girls present in the hall if the number of boys present in the hall are 78 ? 1991 05b5cc6c7e4d2b4197774dea0
5b5cc6c7e4d2b4197774dea0- 156false
- 264false
- 387false
- 478true
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Answer : 4. "78"
Explanation :
Answer: D) 78 Explanation: Using Trial and error method, we get the number of girls in the hall = 78
Q: Simplify the following and find the value of ? 13 of ? + 47 of 114 of 539 = 31% of 2000 1990 05b5cc6ace4d2b4197774d091
5b5cc6ace4d2b4197774d091- 11134true
- 21237false
- 31187false
- 41249false
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Answer : 1. "1134"
Explanation :
Answer: A) 1134 Explanation: 13 x ? + 47 x 114 x 539 = 31100 x 2000? = 378 x 3? = 1134
Q: If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0', What is the value of (a+b) (b+c) (a+c) ? 1989 05b5cc709e4d2b4197774f258
5b5cc709e4d2b4197774f258- 13false
- 22false
- 31false
- 40true
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Answer : 4. "0"
Explanation :
Answer: D) 0 Explanation: Let assume the value of a,b &c that will satisfy the equation.so a=1,b=1,c= -1 or a=1,b= -1 &c=1 or a= -1,b=1,c=1here all three cases satisfy the equationassume any one a=1,b=1,c= -1 Hence (a+b)(b+c)(c+a)=(1+1)(1-1)(-1+1) = 0