Quantitative Aptitude Practice Question and Answer
8Q: The calendar for the year 1988 is same as which upcoming year ? 1462 05b5cc6cfe4d2b4197774e2e3
5b5cc6cfe4d2b4197774e2e3- 12012false
- 22014false
- 32016true
- 42010false
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Answer : 3. "2016"
Explanation :
Answer: C) 2016 Explanation: We already know that the calendar after a leap year repeats again after 28 years. Here year 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.
Q: A bus covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of bus will have to increase ? 1474 05b5cc6cfe4d2b4197774e2dc
5b5cc6cfe4d2b4197774e2dc- 185 km/hrfalse
- 295 km/hrfalse
- 3105 km/hrfalse
- 4120 km/hrtrue
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Answer : 4. "120 km/hr"
Explanation :
Answer: D) 120 km/hr Explanation: Initial speed = 80km/hrTotal distance = 80 x 10 = 800kmNew speed = 800/4 =200km/hrIncrease in speed = 200 - 80 = 120km/hr
Q: In a slip test, K got the 15th rank and he was 44th from the bottom of the list of passed students. 4 students did not take up the slip test and 3 students were failed. What is the total strenght of the class ? 1146 05b5cc6cee4d2b4197774e241
5b5cc6cee4d2b4197774e241- 163false
- 262false
- 364false
- 465true
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Answer : 4. "65"
Explanation :
Answer: D) 65 Explanation: Total strength of the class is given by 15 + 44 + 4 + 3 - 1 = 65
Q: Find the odd man out from the given alternatives ? 2501 05b5cc6cee4d2b4197774e232
5b5cc6cee4d2b4197774e232- 197false
- 2233false
- 3437true
- 4599false
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Answer : 3. "437"
Explanation :
Answer: C) 437 Explanation: Except 437 all others are prime numbers.
Q: Karthik could cover a distance of 200 km in 22 days while resting for 2 hrs. per day. In how many days (approx) he will cover a distance of 250 km while resting for 2 hrs. per day and moving with 2/3rd of the previous speed ? 1657 05b5cc6cee4d2b4197774e203
5b5cc6cee4d2b4197774e203- 141.25 daystrue
- 237.5 daysfalse
- 339.75 daysfalse
- 440 daysfalse
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Answer : 1. "41.25 days"
Explanation :
Answer: A) 41.25 days Explanation: Given Karthik can cover the distance of 200 kms resting 2 hrs per day in 22 days. Let the initial speed be '1' Hence, Time = 22(24hrs - 2) Noe new speed = 2/3 Let the number of days he take be 'D' Therefore, 2224-2x3200=D24-2x2250 D = 11 x 3 x 5/4 = 41.25 days. = 41 1/4 days.
Q: A can build a wall in 16 days while B can destroy it in 8 days. A worked for 5 days. Then B joined with A for the next 2 days. Find in how many days could A build the remaining wall ? 2215 05b5cc6cee4d2b4197774e208
5b5cc6cee4d2b4197774e208- 112 daysfalse
- 214 daysfalse
- 313 daystrue
- 416 daysfalse
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Answer : 3. "13 days"
Explanation :
Answer: C) 13 days Explanation: Now, Total work = LCM(16, 8) = 48 A's one day work = + 48/16 = + 3 B's one day work = - 48/8 = -6 Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15 2days B joined with A in working = 2(3 - 6) = - 6 Remaining Work of building wall = 48 - (15 - 6) = 39 Now this remaining work will be done by A in = 39/3 = 13 days.
Q: In how many ways the letters of the word NUMERICAL can be arranged so that the consonants always occupy the even places ? 2112 05b5cc6cde4d2b4197774e1e0
5b5cc6cde4d2b4197774e1e0- 15!false
- 26!false
- 34!false
- 4Can't determinetrue
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Answer : 4. "Can't determine"
Explanation :
Answer: D) Can't determine Explanation: NUMERICAL has 9 positions in which 2, 4, 6, 8 are even positions. And it contains 5 consonents i.e, N, M, R, C & L. Hence this cannot be done as 5 letters cannot be placed in 4 positions. Therefore, Can't be determined.
Q: Find the total numbers greater than 4000 that can be formed with digits 2, 3, 4, 5, 6 no digit being repeated in any number ? 1455 05b5cc6cde4d2b4197774e1db
5b5cc6cde4d2b4197774e1db- 1120false
- 2256false
- 3192true
- 4244false
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Answer : 3. "192"
Explanation :
Answer: C) 192 Explanation: We are having with digits 2, 3, 4, 5 & 6 and numbers greater than 4000 are to be formed, no digit is repeated. The number can be 4 digited but greater than 4000 or 5 digited. Number of 4 digited numbers greater than 4000 are4 or 5 or 6 can occupy thousand place => 3 x P34 = 3 x 24 = 72. 5 digited numbers = P55 = 5! = 120 So the total numbers greater than 4000 = 72 + 120 = 192

