Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Find the sum of the all the numbers formed by the digits 2,4,6 and 8 without repetition. Number may be of any of the form like 2,24,684,4862 ? 1675 05b5cc701e4d2b4197774f1bc
5b5cc701e4d2b4197774f1bc- 1133345false
- 2147320true
- 313320false
- 4145874false
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उत्तर : 2. "147320"
व्याख्या :
Answer: B) 147320 Explanation: Sum of 4 digit numbers = (2+4+6+8) x P33 x (1111) = 20 x 6 x 1111 = 133320 Sum of 3 digit numbers = (2+4+6+8) x P23 x (111) = 20 x 6 x 111 = 13320 Sum of 2 digit numbers = (2+4+6+8) x P13 x (11) = 20 x 3 x 11 = 660 Sum of 1 digit numbers = (2+4+6+8) x P03 x (1) = 20 x 1 x 1 = 20 Adding All , Sum = 147320
प्र: Rajitha invested 25% more than Santhosh. Santhosh invested 30% less than Raju, who invested Rs. 6,000. What is the ratio of the amount that Rajitha invested to the total amount invested by all of them together ? 1671 05b5cc736e4d2b4197774f850
5b5cc736e4d2b4197774f850- 125 : 114false
- 235 : 103true
- 315 : 108false
- 441 : 94false
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उत्तर : 2. "35 : 103"
व्याख्या :
Answer: B) 35 : 103 Explanation: Santhosh's investment = 6000 x 70/100 = Rs.4200Rajitha's investment = 4200 x 5/4 = Rs.5250Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.Required ratio = 5250 : 15450 = 35 : 103.
प्र: What is the interest rate per annum, if a sum of money invested at compound interest amount to Rs. 2400 in 3 years and in 4 years to Rs. 2,520? 1670 05b5cc68be4d2b4197774c38a
5b5cc68be4d2b4197774c38a- 13.5%false
- 24%false
- 35%true
- 46.5%false
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उत्तर : 3. "5%"
व्याख्या :
Answer: C) 5% Explanation: Let 'R%' be the rate of interest From the given data, 25202400 = 1 + R10041 + R1003⇒1 + R100 = 6360⇒R = 5 Hence, the rate of interest R = 5% per annum.
प्र: Find the sum of the Arithmetic Series upto 36 terms 2, 5, 8, 11,... 1670 15b5cc6afe4d2b4197774d259
5b5cc6afe4d2b4197774d259- 13924false
- 21962true
- 31684false
- 41452false
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उत्तर : 2. "1962"
व्याख्या :
Answer: B) 1962 Explanation: Arithmetic Series :: An Arithmetic Series is a series of numbers in which each term increases by a constant amount. How to find the sum of the Arithmetic Sequence or Series for the given Series :: When the series contains a large amount of numbers, its impractical to add manually. You can quickly find the sum of any arithmetic sequence by multiplying the average of the first and last term by the number of terms in the sequence. That is given by Sn = n(a1 + an)2 Where n = number of terms, a1 = first term, an = last term Here Last term is given by an = a1 + n-1d where d = common difference Now given Arithmetic Series is 2, 5, 8, 11,... Here a1 = 2, d = 3, n = 36 Now, an= a1 + n - 1d a36= 2 + 36 - 13 = 105 + 2 = 107 Now, Sum to 36 terms is given by S36 = 36(2 + 107)2 = 36 x 1092 = 39242 = 1962 Therefore, Sum to 36 terms of the series 2, 5, 8, 11,... is 1962.
प्र: A shopkeeper sold a mobile phone for Rs. 12000. Had he offered discount of 10% on the selling price, there would be a loss of 4%. What is the cost price of that Mobile phone? 1668 05b5cc6bce4d2b4197774d8a7
5b5cc6bce4d2b4197774d8a7- 1Rs. 12,500false
- 2Rs. 11,250true
- 3Rs. 12,750false
- 4Rs. 11,680false
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उत्तर : 2. "Rs. 11,250"
व्याख्या :
Answer: B) Rs. 11,250 Explanation: Given that SP = Rs. 12000 - 10% = Rs. 10,800 Loss% = 4 We know that, C.P = 100/(100 - Loss%) x 100 => 100/100-4 x 10800 => 1080000/96 C.P = Rs. 11,250
प्र: Simplify the fraction? 5 (2/7) - 3 (1/14) - 2 (1/14) - 1 (1/7) = ? + 3 (1/17) 1668 05b5cc6a5e4d2b4197774ccef
5b5cc6a5e4d2b4197774ccef- 1-4 (1/17)true
- 25 (2/17)false
- 3-2 (1/17)false
- 43 (3/17)false
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उत्तर : 1. "-4 (1/17)"
व्याख्या :
Answer: A) -4 (1/17) Explanation: Given fraction is 5 (2/7) - 3 (1/14) - 2 (1/14) - 1 (1/7) = ? + 3 (1/17) It can be written as (5 - 3 - 2 - 1) + (2/7 - 1/14 - 1/14 - 1/7) = ? + 3 (1/17) -1 + 0 - 3 (1/17) = ? => ? = -4 (1/17)
प्र: What are the Multiples of 6 and the Common Multiples of 4 and 6? 1666 05b5cc6b1e4d2b4197774d303
5b5cc6b1e4d2b4197774d303- 112, 34, 42false
- 212, 18, 36,true
- 36, 4, 14false
- 44, 8, 16false
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उत्तर : 2. "12, 18, 36,"
व्याख्या :
Answer: B) 12, 18, 36, Explanation: The Multiples of 6 are 6, 12, 18, 24, 30, 36, 42, 48, 54, 60. The Multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60. The Common Multiples of 4 & 6 upto 60 numbers are given as 12, 24, 36, 48, 60.
प्र: If 4 circles of equal radius are drawn with vertices of a square as the centre , the side of the square being 7 cm, find the area of the circles outside the square ? 1666 05b5cc718e4d2b4197774f490
5b5cc718e4d2b4197774f490- 1119.21 sq cmfalse
- 2115.395 sq cmtrue
- 3104.214 sq cmfalse
- 4111.241 sq cmfalse
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उत्तर : 2. "115.395 sq cm"
व्याख्या :
Answer: B) 115.395 sq cm Explanation: Because each vertice of the square is the center of a circle(1/4) part of the total area of each circle inside of the square.(3/4) part of the total area of each circle outside of the square.Thus total area outside the square is 434×227×3.5×3.5 = 115.3955 sq cm.

