Answer: A) 8400 Explanation: 12% of 70,000 => 12 x 70,000/100 => 8400   Hence, 12% of 70,000 = 8,400

Answer: C) 166252 Explanation: Given 92613 x 62742241 = ? + 89   Using unit digit method,   On LHS,   1 x 1 x 1 = 1   sqrt of last digit 1 => it must end with either 9 or 1   so now   1 x 1 = 1   1 x 9 = 9   On RHS,   ? + 89   => ? = ...1 - 89 = last digit is 11- 9 = 2   or   => ? = ...9 - 89 = last digit is 9 - 9 = 0   Here in the options last digit 2 is option C.

Answer: D) Rs. 960 Explanation: Let C.P. = Rs. C. Then, 832 - C = C - 4482C = 1280 => C = 640Required S.P. = 150% of Rs. 640 = 150/100 x 640 = Rs. 960.

Answer: B) 1/8 Explanation: 125 over 1000 in Simplest Form means 1251000 in its simple fraction form.   Now, to get the simplest form of 125/1000, find the HCF or GCD of both numerator and denominator i.e, 125 and 1000.   HCF of 125, 1000 = 125   Then, divide both numerator and denominator by 125 i.e, 1251251000125 = 18   Hence, 18 is the simplest form of 125 over 1000.

Answer: B) 20 Explanation: 4, 14, 24, 34, 44, 54, 64, 74, 84, 94 => has 11 number of (4's)40, 41, 42, 43, 45, 46, 47, 48, 49 => has 9 number of (4's)So, totally (11 + 9 = 20) number of 4's in 1 to 100.

Answer: B) 115.395 sq cm Explanation: Because each vertice of the square is the center of a circle(1/4) part of the total area of each circle inside of the square.(3/4) part of the total area of each circle outside of the square.Thus total area outside the square is 434×227×3.5×3.5 = 115.3955 sq cm.

Answer: A) 41.25 days Explanation: Given Karthik can cover the distance of 200 kms resting 2 hrs per day in 22 days.   Let the initial speed be '1'   Hence, Time = 22(24hrs - 2)   Noe new speed = 2/3   Let the number of days he take be 'D'   Therefore, 2224-2x3200=D24-2x2250   D = 11 x 3 x 5/4 = 41.25 days. = 41 1/4 days.

Answer: A) 91 Explanation: Prime Numbers :: Numbers which are divisible by only 1 and itself are Prime Numbers.   It's answer will be 91. Because 91 can be divisible by 7,13,91,1. It is quite clear that prime number should be divisible only by itself and by 1.