Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8 प्र: एक निश्चित समूह के 28% सदस्य विवाहित हैं। अविवाहित सदस्यों की संख्या में विवाहित सदस्यों की संख्या के बीच संबंधित अनुपात क्या है?
2067 05d4a9f58108bca202e8a3645
5d4a9f58108bca202e8a3645- 17:17false
- 25: 18false
- 37:18true
- 4Cannot determinedfalse
- 5None of thesefalse
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उत्तर : 3. "7:18"
व्याख्या :
Let total number of person is=100
married person=28
unmarried person will be 100-28=72
The ratio will be 28/72=7/18
प्र: 1.12.91 is the first Tuesday. Which is the fourth Thursday of December 91 ? 2065 05b5cc6dbe4d2b4197774e8ff
5b5cc6dbe4d2b4197774e8ff- 122.12.91false
- 225.12.91true
- 324.12.91false
- 423.12.91false
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उत्तर : 2. "25.12.91"
व्याख्या :
Answer: B) 25.12.91 Explanation: Given that 2.12.91 is the first TuesdayHence we can assume that 4.12.91 is the first Thursday If we add 7 days to 4.12.91, we will get second ThursdayIf we add 14 days to 4.12.91, we will get third ThursdayIf we add 21 days to 4.12.91, we will get fourth Thursday => fourth Thursday = (4.12.91 + 21 days) = 25.12.91.
प्र: If L exceeds K by 30%, then K is less than L by ? 2065 05b5cc6f8e4d2b4197774f05e
5b5cc6f8e4d2b4197774f05e- 114 2/5 %false
- 223 1/3 %true
- 320 %false
- 416 %false
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उत्तर : 2. "23 1/3 %"
व्याख्या :
Answer: B) 23 1/3 % Explanation: K = 100 L = 130130------ 30100------- ? => 23 1/13 %
प्र: 92613 x 62742241 = ? + 89 Find the value of '?' 2064 05b5cc6bae4d2b4197774d7fd
5b5cc6bae4d2b4197774d7fd- 1166251false
- 2166259false
- 3166252true
- 4166253false
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उत्तर : 3. "166252"
व्याख्या :
Answer: C) 166252 Explanation: Given 92613 x 62742241 = ? + 89 Using unit digit method, On LHS, 1 x 1 x 1 = 1 sqrt of last digit 1 => it must end with either 9 or 1 so now 1 x 1 = 1 1 x 9 = 9 On RHS, ? + 89 => ? = ...1 - 89 = last digit is 11- 9 = 2 or => ? = ...9 - 89 = last digit is 9 - 9 = 0 Here in the options last digit 2 is option C.
प्र: A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained? 2064 05b5cc669e4d2b4197774bf4d
5b5cc669e4d2b4197774bf4d- 11/5false
- 21/6true
- 31/7false
- 41/8false
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उत्तर : 2. "1/6"
व्याख्या :
Answer: B) 1/6 Explanation: Total work is given by L.C.M of 72, 48, 36 Total work = 144 units Efficieny of A = 144/72 = 2 units/day Efficieny of B = 144/48 = 3 units/day Efficieny of C = 144/36 = 4 units/day According to the given data, 2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100 3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54 p = 198/16.5 p = 12 days. Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day (C+D) in p days = (4 + 6) x 12 = 120 unit Remained part of work = (144-120)/144 = 1/6.
प्र: 30% of 500 rupees is? 2063 05b5cc690e4d2b4197774c460
5b5cc690e4d2b4197774c460- 1Rs. 180false
- 2Rs. 150true
- 3Rs. 120false
- 4Rs. 240false
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उत्तर : 2. "Rs. 150"
व्याख्या :
Answer: B) Rs. 150 Explanation: Given 30% of 500 = 30100 x 500= 30 x 5= 150 Hence, 30% of Rs. 500 = Rs. 150.
प्र: 12% of 70,000 is 2063 05b5cc622e4d2b4197774b7df
5b5cc622e4d2b4197774b7df- 18400true
- 27200false
- 36000false
- 45600false
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उत्तर : 1. "8400"
व्याख्या :
Answer: A) 8400 Explanation: 12% of 70,000 => 12 x 70,000/100 => 8400 Hence, 12% of 70,000 = 8,400
प्र: A work which could be finished in 11 days was finished 4 days earlier after 4 more men joined. The number of men employed was ? 2062 05b5cc6e1e4d2b4197774ebb6
5b5cc6e1e4d2b4197774ebb6- 17true
- 28false
- 39false
- 410false
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उत्तर : 1. "7"
व्याख्या :
Answer: A) 7 Explanation: As the work is sameM1D1 = M2D2 Here Let the number of men employed was M=> 11M = 7(M+4)=> 11M - 7M = 28=> M = 7

