Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: A passenger train is moving at a speed of 120 km/hr. If the length of the train is 101 meters, how long will it take to cross a railway platform 154 meters long ? 2056 05b5cc6d3e4d2b4197774e540
5b5cc6d3e4d2b4197774e540- 16.24 secfalse
- 26.58 secfalse
- 37.325 secfalse
- 47.65 sectrue
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उत्तर : 4. "7.65 sec"
व्याख्या :
Answer: D) 7.65 sec Explanation: Here total distance = 154 + 101 = 255 mtsGiven speed = 120 kmph = 120x5/18 m/secHence, Time = d/s = 255x18/120x5 = 7.65 sec
प्र: A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days ? 2052 05b5cc6dee4d2b4197774ea99
5b5cc6dee4d2b4197774ea99- 19 daysfalse
- 211 daysfalse
- 313 daystrue
- 415 daysfalse
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उत्तर : 3. "13 days"
व्याख्या :
Answer: C) 13 days Explanation: Ratio of times taken by A and B = 100 : 130 = 10 : 13.Suppose B takes x days to do the work. Then, 10 : 13 :: 23 : x => x = ( 23 x 13/10 ) => x = 299 /10. A's 1 day's work = 1/23 ;B's 1 day's work = 10/299 . (A + B)'s 1 day's work = ( 1/23 + 10/299 ) = 23/299 = 113 . Therefore, A and B together can complete the work in 13 days.
प्र: If A1, A2, A3, A4, ..... A10 are speakers for a meeting and A1 always speaks after, A2 then the number of ways they can speak in the meeting is 2052 05b5cc7b4e4d2b419777508a6
5b5cc7b4e4d2b419777508a6- 19!false
- 29!/2false
- 310!false
- 410!/2true
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उत्तर : 4. "10!/2"
व्याख्या :
Answer: D) 10!/2 Explanation: As A1 speaks always after A2, they can speak only in 1st to 9th places and A2 can speak in 2nd to 10 the places only when A1 speaks in 1st place A2 can speak in 9 places the remaining A3, A4, A5,...A10 has no restriction. So, they can speak in 9.8! ways. i.e when A2 speaks in the first place, the number of ways they can speak is 9.8!. When A2 speaks in second place, the number of ways they can speak is 8.8!. When A2 speaks in third place, the number of ways they can speak is 7.8!. When A2 speaks in the ninth place, the number of ways they can speak is 1.8! Therefore,Total Number of ways they can speak = (9+8+7+6+5+4+3+2+1) 8! = 92(9+1)8! = 10!/2
प्र: Karthik could cover a distance of 200 km in 22 days while resting for 2 hrs. per day. In how many days (approx) he will cover a distance of 250 km while resting for 2 hrs. per day and moving with 2/3rd of the previous speed ? 2052 05b5cc6cee4d2b4197774e203
5b5cc6cee4d2b4197774e203- 141.25 daystrue
- 237.5 daysfalse
- 339.75 daysfalse
- 440 daysfalse
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उत्तर : 1. "41.25 days"
व्याख्या :
Answer: A) 41.25 days Explanation: Given Karthik can cover the distance of 200 kms resting 2 hrs per day in 22 days. Let the initial speed be '1' Hence, Time = 22(24hrs - 2) Noe new speed = 2/3 Let the number of days he take be 'D' Therefore, 2224-2x3200=D24-2x2250 D = 11 x 3 x 5/4 = 41.25 days. = 41 1/4 days.
प्र: Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ? 2051 05b5cc758e4d2b4197774fbf9
5b5cc758e4d2b4197774fbf9- 13 daysfalse
- 22 daysfalse
- 36 daystrue
- 412 daysfalse
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उत्तर : 3. "6 days"
व्याख्या :
Answer: C) 6 days Explanation: From the given data, 12 children 16 days work,One child’s one day work = 1/192. 8 adults 12 days work,One adult’s one day’s work = 1/96. Work done in 3 days = ((1/96) x 16 x 3) = 1/2 Remaining work = 1 – 1/2 = 1/2 (6 adults+ 4 children)’s 1 day’s work = 6/96 + 4/192 = 1/12 1/12 work is done by them in 1 day. 1/2 work is done by them in 12 x (1/2) = 6 days.
प्र: 2/3 as a decimal 2051 05b5cc651e4d2b4197774bcf4
5b5cc651e4d2b4197774bcf4- 10.47false
- 26.77false
- 30.67true
- 40.07false
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उत्तर : 3. "0.67"
व्याख्या :
Answer: C) 0.67 Explanation: To convert a fraction into decimal, just take the number on top which we called the numerator and divide it by the number at the bottom which we called the denominator. 2/3 How it comes : 2 ÷ 3 = 0 bring down the decimal point. 20 ÷ 3 = 6 and carry the remainder 2 to make 20 20 ÷ 3 = 6 and carry the remainder 2 to make 20 20 ÷ 3 = 6 and carry the remainder 2 to make 20 etc... This gives the recurring decimal 0.6666... If we round off to two decimals , then it becomes 0.67. Hence, decimal fraction of 2/3 = 0.67.
प्र: In a daily morning walk three persons step off together. their steps measure 75 cm, 80 cm and 85 cm respectively. What is the minimum distance each should walk so that thay can cover the distance in complete steps ? 2050 05b5cc6c0e4d2b4197774dabc
5b5cc6c0e4d2b4197774dabc- 1222 m 44 cmfalse
- 2204 mtrue
- 3201 m 21 cmfalse
- 4208 mfalse
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उत्तर : 2. "204 m"
व्याख्या :
Answer: B) 204 m Explanation: To find the minimum distance, we have to get the LCM of 75, 80, 85 Now, LCM of 75, 80, 85 = 5 x 15 x 16 x 17 = 20400 Hence, the minimum distance each should walk so that thay can cover the distance in complete steps = 20400 cms = 20400/100 = 204 mts.
प्र: Raghu earns 25% on an investment but loses 10% on another investment. If the ratio of the two investment is 3:5. What is the gain or loss on two investments taken together ? 2049 05b5cc754e4d2b4197774fb72
5b5cc754e4d2b4197774fb72- 11.251 %false
- 23.125 %true
- 37.21 %false
- 49.451 %false
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उत्तर : 2. "3.125 %"
व्याख्या :
Answer: B) 3.125 % Explanation: Taking the 2 investments to be 3x and 5x respectivelyTotal income of Raghu = (3x) x 1.25 + (5x) x 0.9 = 8.25Therefore, Gain% = 0.25/8 x 100 = 3.125 %.

