Quantitative Aptitude Practice Question and Answer
8Q: Raghu earns 25% on an investment but loses 10% on another investment. If the ratio of the two investment is 3:5. What is the gain or loss on two investments taken together ? 1661 05b5cc754e4d2b4197774fb72
5b5cc754e4d2b4197774fb72- 11.251 %false
- 23.125 %true
- 37.21 %false
- 49.451 %false
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Answer : 2. "3.125 %"
Explanation :
Answer: B) 3.125 % Explanation: Taking the 2 investments to be 3x and 5x respectivelyTotal income of Raghu = (3x) x 1.25 + (5x) x 0.9 = 8.25Therefore, Gain% = 0.25/8 x 100 = 3.125 %.
Q: Which one of the following is not a prime number? 1660 05b5cc6a8e4d2b4197774ce5c
5b5cc6a8e4d2b4197774ce5c- 191true
- 271false
- 341false
- 431false
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Answer : 1. "91"
Explanation :
Answer: A) 91 Explanation: Prime Numbers :: Numbers which are divisible by only 1 and itself are Prime Numbers. It's answer will be 91. Because 91 can be divisible by 7,13,91,1. It is quite clear that prime number should be divisible only by itself and by 1.
Q: If A1, A2, A3, A4, ..... A10 are speakers for a meeting and A1 always speaks after, A2 then the number of ways they can speak in the meeting is 1660 05b5cc7b4e4d2b419777508a6
5b5cc7b4e4d2b419777508a6- 19!false
- 29!/2false
- 310!false
- 410!/2true
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Answer : 4. "10!/2"
Explanation :
Answer: D) 10!/2 Explanation: As A1 speaks always after A2, they can speak only in 1st to 9th places and A2 can speak in 2nd to 10 the places only when A1 speaks in 1st place A2 can speak in 9 places the remaining A3, A4, A5,...A10 has no restriction. So, they can speak in 9.8! ways. i.e when A2 speaks in the first place, the number of ways they can speak is 9.8!. When A2 speaks in second place, the number of ways they can speak is 8.8!. When A2 speaks in third place, the number of ways they can speak is 7.8!. When A2 speaks in the ninth place, the number of ways they can speak is 1.8! Therefore,Total Number of ways they can speak = (9+8+7+6+5+4+3+2+1) 8! = 92(9+1)8! = 10!/2
Q: In one year, the Amount collected for social welfare, of a village increased by 10% and in the next year, it decreased by 10%. If at the end of 2nd year, the amount was 7920, what was it in the beginning ? 1659 05b5cc6d8e4d2b4197774e773
5b5cc6d8e4d2b4197774e773- 18800false
- 28650false
- 38000true
- 48980false
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Answer : 3. "8000"
Explanation :
Answer: C) 8000 Explanation: Let the amount collected be 'A'Then, from the given conditions,A x 110/100 x 90/100 = 7920 A x 0.99 = 7920 A = 7920/0.99=> 8000
Q: Karthik could cover a distance of 200 km in 22 days while resting for 2 hrs. per day. In how many days (approx) he will cover a distance of 250 km while resting for 2 hrs. per day and moving with 2/3rd of the previous speed ? 1657 05b5cc6cee4d2b4197774e203
5b5cc6cee4d2b4197774e203- 141.25 daystrue
- 237.5 daysfalse
- 339.75 daysfalse
- 440 daysfalse
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Answer : 1. "41.25 days"
Explanation :
Answer: A) 41.25 days Explanation: Given Karthik can cover the distance of 200 kms resting 2 hrs per day in 22 days. Let the initial speed be '1' Hence, Time = 22(24hrs - 2) Noe new speed = 2/3 Let the number of days he take be 'D' Therefore, 2224-2x3200=D24-2x2250 D = 11 x 3 x 5/4 = 41.25 days. = 41 1/4 days.
Q: The mean of 100 observations is 40. It is found that an observation 84 was misread as 48. Then the correct mean is ? 1656 05b5cc6c0e4d2b4197774dab2
5b5cc6c0e4d2b4197774dab2- 140.36true
- 241.24false
- 341.92false
- 442.05false
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Answer : 1. "40.36"
Explanation :
Answer: A) 40.36 Explanation: Given, mean of 100 observations is 40 => Total of 100 observations = 40 x 100 = 4000 84 is misread as 48 => Difference = 84 - 48 = 36 => Now, new total of 100 observations = 4000 + 36 = 4036 Correct Mean = 4036/100 = 40.36
Q: A train 125 m long passes a man, running at 4 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is: 1656 05b5cc6d6e4d2b4197774e65b
5b5cc6d6e4d2b4197774e65b- 149 kmphtrue
- 250 kmphfalse
- 351 kmphfalse
- 452 kmphfalse
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Answer : 1. "49 kmph"
Explanation :
Answer: A) 49 kmph Explanation: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) x (18/5)] km/hr = 45 km/hr. Let the speed of the train be 'x' km/hr. Then, relative speed = (x - 4) km/hr. x - 4 = 45 => x = 49 km/hr.
Q: Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ? 1655 05b5cc6c1e4d2b4197774db82
5b5cc6c1e4d2b4197774db82- 1A is eldest & C is youngestfalse
- 2D is eldest & C is youngesttrue
- 3C is eldest & A is youngestfalse
- 4A is eldest & B is youngestfalse
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Answer : 2. "D is eldest & C is youngest"
Explanation :
Answer: B) D is eldest & C is youngest Explanation: Given sum of present ages of A, B, C & D A + B + C + D = 176 and also given that, (A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14 Let the ratio = x => A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x => (A + B + C + D ) - 16 = 40x => 176 - 16 = 40x => x = 4 => A = 44 + 4 = 48 => B = 40 => C = 28 => D = 60 Therefore, from the above conclusions D is eldest with 60 years and C is youngest with 28 years of ages.