Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: 12 students of class IX took part in GK quiz. If the number of boys is 4 more than the number of girls. Find the number of boys and girls took part in the quiz ? 1963 0

  • 1
    7, 5
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  • 2
    9, 3
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  • 3
    8, 4
    सही
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  • 4
    6, 6
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उत्तर : 3. "8, 4"
व्याख्या :

Answer: C) 8, 4 Explanation: Let the number of girls = x => x + x + 4 = 12 => 2x = 8 => x = 4 => Number of girls = 4 => Number of boys = 4 + 4 = 8

प्र: How many squares with sides 1/2 inch long are needed to cover a rectangle that is 4 ft long and 4 ft wide ? 1963 0

  • 1
    9216
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  • 2
    10246
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  • 3
    12345
    सही
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  • 4
    7527
    सही
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उत्तर : 1. "9216"
व्याख्या :

Answer: A) 9216 Explanation: It takes four of those little squares -- each one 1/2 inch on a side -- to cover one square inch. That's because each one is 1/2 x 1/2, or 1/4 of a square inch. In a rectangle that is 48 inches by 48 inches, there are 2304 square inches.(1 ft = 12 inches) Since it takes 4 little squares to cover 1 sq inch, then it would need 2304 x 4 squares (1/2 inch on a side each) to cover a rectangle 4 feet by 4 feet. That is 9,216 of those squares.

प्र: If the price of diesel increases by 25% and Karthik intends to spend only an additional 15% on diesel, by how much % will he reduce the quantity of diesel purchased ? 1963 0

  • 1
    6.67 %
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  • 2
    8 %
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  • 3
    7.41 %
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  • 4
    9 %
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उत्तर : 2. "8 %"
व्याख्या :

Answer: B) 8 % Explanation: Let the price of 1 litre of diesel be Rs.x and let Karthik initially buy 'y' litres of diesel. Therefore, he would have spent Rs. xy on diesel. When the price of diesel increases by 25%, the new price per litre of diesel is 1.25x. Karthik intends to increase the amount he spends on diesel by 15%.i.e., he is willing to spend xy + 15% of xy = 1.15xy Let the new quantity of diesel that he can get be 'q'.Then, 1.25x x q = 1.15xyOr q = (1.15/1.25)y = 0.92y. As the new quantity that he can buy is 0.92y, he gets 0.08y lesser than what he used to get earlier. Or a reduction of 8%.

प्र: 1.12.91 is the first Tuesday. Which is the fourth Thursday of December 91  ? 1962 0

  • 1
    22.12.91
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  • 2
    25.12.91
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  • 3
    24.12.91
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  • 4
    23.12.91
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उत्तर : 2. "25.12.91"
व्याख्या :

Answer: B) 25.12.91 Explanation: Given that 2.12.91 is the first TuesdayHence we can assume that 4.12.91 is the first Thursday If we add 7 days to 4.12.91, we will get second ThursdayIf we add 14 days to 4.12.91, we will get third ThursdayIf we add 21 days to 4.12.91, we will get fourth Thursday => fourth Thursday = (4.12.91 + 21 days) = 25.12.91.

प्र: Rajitha invested 25% more than Santhosh. Santhosh invested 30% less than Raju, who invested Rs. 6,000. What is the ratio of the amount that Rajitha invested to the total amount invested by all of them together ? 1959 0

  • 1
    25 : 114
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  • 2
    35 : 103
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  • 3
    15 : 108
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  • 4
    41 : 94
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उत्तर : 2. "35 : 103"
व्याख्या :

Answer: B) 35 : 103 Explanation: Santhosh's investment = 6000 x 70/100 = Rs.4200Rajitha's investment = 4200 x 5/4 = Rs.5250Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.Required ratio = 5250 : 15450 = 35 : 103.

प्र: A flagstaff 17.5 m high casts a shadow of length 40.25 m. What will be the height of a building, which casts a shadow of length 28.75 m under similar conditions ? 1959 1

  • 1
    14 cm
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  • 2
    13.5 cm
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  • 3
    12.5 cm
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  • 4
    11.4 cm
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उत्तर : 3. "12.5 cm"
व्याख्या :

Answer: C) 12.5 cm Explanation: Let the required height of the building be x meter More shadow length, More height(direct proportion) Hence we can write as (shadow length) 40.25 : 28.75 :: 17.5 : x⇒ 40.25 × x = 28.75 × 17.5⇒ x = 28.75 × 17.5/40.25= 2875 × 175/40250= 2875 × 7/1610= 2875/230= 575/46= 12.5 cm

प्र: A passenger train is moving at a speed of 120 km/hr. If the length of the train is 101 meters, how long will it take to cross a railway platform 154 meters long ? 1958 0

  • 1
    6.24 sec
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  • 2
    6.58 sec
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  • 3
    7.325 sec
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  • 4
    7.65 sec
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उत्तर : 4. "7.65 sec"
व्याख्या :

Answer: D) 7.65 sec Explanation: Here total distance = 154 + 101 = 255 mtsGiven speed = 120 kmph = 120x5/18 m/secHence, Time = d/s = 255x18/120x5 = 7.65 sec

प्र: In a 100 litre of mixture the ratio of milk and water is 6:4. How much milk must be added to the mixture in order to make the ratio 3 : 1? 1957 0

  • 1
    85
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  • 2
    60
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  • 3
    55
    सही
    गलत
  • 4
    45
    सही
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उत्तर : 2. "60"
व्याख्या :

Answer: B) 60 Explanation: Let M litres milk be added => 60 + M40 = 31 => 60 + M = 120 => M = 60 lit.

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