Quantitative Aptitude Practice Question and Answer

Q: Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ? 1865 0

  • 1
    43929
    Correct
    Wrong
  • 2
    59049
    Correct
    Wrong
  • 3
    15120
    Correct
    Wrong
  • 4
    0
    Correct
    Wrong
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Answer : 1. "43929"
Explanation :

Answer: A) 43929 Explanation: Number of words with 5 letters from given 9 alphabets formed = 95   Number of words with 5 letters from given 9 alphabets formed such that no letter is repeated is = 9P5   Number of words can be formed which have at least one letter repeated =  95 - 9P5   = 59049 - 15120   = 43929

Q: How many six digit odd numbers can be formed from the digits 0, 2, 3, 5, 6, 7, 8, and 9 (repetition not allowed)? 1865 0

  • 1
    8640
    Correct
    Wrong
  • 2
    720
    Correct
    Wrong
  • 3
    3620
    Correct
    Wrong
  • 4
    4512
    Correct
    Wrong
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Answer : 1. "8640"
Explanation :

Answer: A) 8640 Explanation: Let the 6 digits of the required 6 digit number be abcdef Then, the number to be odd number the last digit must be odd digit i.e 3, 5, 7 or 9 The first digit cannot be ‘0’ => possible digits = 3, 5, 7, 2, 6, 8 Remaining 4 places can be of 6 x 5 x 4 x 3 ways This can be easily understood by Therefore, required number of ways = 6 x 6 x 5 x 4 x 3 x 4 = 36 x 20 x 12 = 720 x 12 = 8640 ways.

Q: Rajitha invested 25% more than Santhosh. Santhosh invested 30% less than Raju, who invested Rs. 6,000. What is the ratio of the amount that Rajitha invested to the total amount invested by all of them together ? 1864 0

  • 1
    25 : 114
    Correct
    Wrong
  • 2
    35 : 103
    Correct
    Wrong
  • 3
    15 : 108
    Correct
    Wrong
  • 4
    41 : 94
    Correct
    Wrong
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Answer : 2. "35 : 103"
Explanation :

Answer: B) 35 : 103 Explanation: Santhosh's investment = 6000 x 70/100 = Rs.4200Rajitha's investment = 4200 x 5/4 = Rs.5250Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.Required ratio = 5250 : 15450 = 35 : 103.

Q: How many squares with sides 1/2 inch long are needed to cover a rectangle that is 4 ft long and 4 ft wide ? 1864 0

  • 1
    9216
    Correct
    Wrong
  • 2
    10246
    Correct
    Wrong
  • 3
    12345
    Correct
    Wrong
  • 4
    7527
    Correct
    Wrong
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Answer : 1. "9216"
Explanation :

Answer: A) 9216 Explanation: It takes four of those little squares -- each one 1/2 inch on a side -- to cover one square inch. That's because each one is 1/2 x 1/2, or 1/4 of a square inch. In a rectangle that is 48 inches by 48 inches, there are 2304 square inches.(1 ft = 12 inches) Since it takes 4 little squares to cover 1 sq inch, then it would need 2304 x 4 squares (1/2 inch on a side each) to cover a rectangle 4 feet by 4 feet. That is 9,216 of those squares.

Q: 125 over 1000 in Simplest Form? 1864 0

  • 1
    2/9
    Correct
    Wrong
  • 2
    1/8
    Correct
    Wrong
  • 3
    3/8
    Correct
    Wrong
  • 4
    4/7
    Correct
    Wrong
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Answer : 2. "1/8"
Explanation :

Answer: B) 1/8 Explanation: 125 over 1000 in Simplest Form means 1251000 in its simple fraction form.   Now, to get the simplest form of 125/1000, find the HCF or GCD of both numerator and denominator i.e, 125 and 1000.   HCF of 125, 1000 = 125   Then, divide both numerator and denominator by 125 i.e, 1251251000125 = 18   Hence, 18 is the simplest form of 125 over 1000.

Q: A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal. 1861 0

  • 1
    31.8%
    Correct
    Wrong
  • 2
    31%
    Correct
    Wrong
  • 3
    33.33%
    Correct
    Wrong
  • 4
    29.85%
    Correct
    Wrong
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Answer : 3. "33.33%"
Explanation :

Answer: C) 33.33% Explanation: Now, take percentage of milk and applying mixture rule 25          100        50 50            25  = 2 : 1   Hence required answer =  1/3 or 33.33%

Q: 1.12.91 is the first Tuesday. Which is the fourth Thursday of December 91  ? 1859 0

  • 1
    22.12.91
    Correct
    Wrong
  • 2
    25.12.91
    Correct
    Wrong
  • 3
    24.12.91
    Correct
    Wrong
  • 4
    23.12.91
    Correct
    Wrong
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Answer : 2. "25.12.91"
Explanation :

Answer: B) 25.12.91 Explanation: Given that 2.12.91 is the first TuesdayHence we can assume that 4.12.91 is the first Thursday If we add 7 days to 4.12.91, we will get second ThursdayIf we add 14 days to 4.12.91, we will get third ThursdayIf we add 21 days to 4.12.91, we will get fourth Thursday => fourth Thursday = (4.12.91 + 21 days) = 25.12.91.

Q: If 4 circles of equal radius are drawn with vertices of a square as the centre , the side of the square being 7 cm, find the area of the circles outside the square ? 1859 0

  • 1
    119.21 sq cm
    Correct
    Wrong
  • 2
    115.395 sq cm
    Correct
    Wrong
  • 3
    104.214 sq cm
    Correct
    Wrong
  • 4
    111.241 sq cm
    Correct
    Wrong
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Answer : 2. "115.395 sq cm"
Explanation :

Answer: B) 115.395 sq cm Explanation: Because each vertice of the square is the center of a circle(1/4) part of the total area of each circle inside of the square.(3/4) part of the total area of each circle outside of the square.Thus total area outside the square is 434×227×3.5×3.5 = 115.3955 sq cm.

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