Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: One year ago the ratio between Maneela’s and Shanthi’s salary was 3 : 4. The ratios of their individual salaries between last year’s and this year’s salaries are 4 : 5 and 2 : 3 respectively. At present the total of their salary is Rs. 4160. The salary of Maneela, now is? 6463 05b5cc678e4d2b4197774c165
5b5cc678e4d2b4197774c165- 1Rs. 1600true
- 2Rs. 1700false
- 3Rs. 1800false
- 4Rs. 1900false
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उत्तर : 1. "Rs. 1600"
व्याख्या :
Answer: A) Rs. 1600 Explanation: Let the salaries of Maneela and Shanthi one year before be M1, S1 & now be M2, S2 respectively. Then, from the given data, M1/S1 = 3/4 .....(1) M1/M2 = 4/5 .....(2) S1/S2 = 2/3 .....(3) and M2 + S2 = 4160 .....(4) Solving all these eqtns, we get M2 = Rs. 1600.
प्र: Find the odd number out of the following number series? 2 4 8 11.5 18.25 28.375 6462 05b5cc68be4d2b4197774c380
5b5cc68be4d2b4197774c380- 118.25false
- 228.375false
- 311.5false
- 48true
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उत्तर : 4. "8"
व्याख्या :
Answer: D) 8 Explanation: Given number series follows a pattern that, 2 2 x 1.5 + 1 = 4 4 x 1.5 + 1 = 7 (not equal to 8) 7 x 1.5 + 1 = 11.5 11.5 x 1.5 + 1 = 18.25 18.25 x 1.5 + 1 = 28.375 Hence, the odd number in the given number series is 8.
प्र: X और Y नामक दो संस्थानों में दाखिल छात्रों की संख्या क्रमशः 5ः8 के अनुपात में है।यदि संस्थान X में छात्रों की संख्या में 20 प्रतिशत की वृद्धि हो जाए, और संस्थान Y में 10 प्रतिशत वृद्धि हो जाए, तो क्रमशः नया अनुपात क्या होगा? 6442 15d1b13e08a754124194a7564
5d1b13e08a754124194a7564- 115:22true
- 215:16false
- 35:4false
- 45:7false
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उत्तर : 1. "15:22"
प्र: एक दूधवाले के पास 20 लीटर दूध है। यदि वह 20 लीटर शुद्ध दूध में 5 लीटर पानी मिलाता है, जो कि मुफ्त में उपलब्ध है। यदि शुद्ध दूध की कीमत रु. 18 प्रति लीटर, तो दूधवाले का लाभ, जब वह सभी मिश्रण को लागत मूल्य पर बेचता है, है: 6374 65b5cc7d7e4d2b4197775151f
5b5cc7d7e4d2b4197775151f- 120%false
- 225%true
- 333.33%false
- 418%false
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उत्तर : 2. "25%"
व्याख्या :
Answer: B) 25% व्याख्या: जब पानी मुफ्त में उपलब्ध हो और सारा पानी दूध की कीमत पर बेचा जाता है, तो पानी 20 लीटर दूध की कीमत पर लाभ देता है। चूँकि, लाभ% = ProfitCostPricex100 इसलिए, लाभ प्रतिशत = 520x100 = 25%
प्र: What is the number of digits in 333? Given that log3 = 0.47712? 6371 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
- 415false
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उत्तर : 2. "13"
व्याख्या :
Answer: B) 13 Explanation: Let Let x=333 = 333 Then, logx = 33 log3 = 27 x 0.47712 = 12.88224 Since the characteristic in the resultant value of log x is 12 ∴The number of digits in x is (12 + 1) = 13 Hence the required number of digits in 333is 13.
प्र: A sum of Rs. 427 is to be divided among A, B and C in such a way that 3 times A’s share, 4 times B’s share and 7 times C’s share are all equal. The share of C is ? 6351 05b5cc72ce4d2b4197774f792
5b5cc72ce4d2b4197774f792- 164false
- 276false
- 384true
- 498false
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उत्तर : 3. "84"
व्याख्या :
Answer: C) 84 Explanation: Given total sum = Rs. 427And given that 3 times A’s share, 4 times B’s share and 7 times C’s share are all equal.=> 3A = 4B = 7CBut given=> A + B + C = 427Now express A and B in terms of C i.e=> (7C/3) + (7C/4) + C = 427=> C = 84
प्र: Two persons start running simultaneously around a circular track of length 300 m from the same point at speeds of 15 km/hr and 25 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions ? 6350 05b5cc6e5e4d2b4197774ecf2
5b5cc6e5e4d2b4197774ecf2- 127 sectrue
- 231 secfalse
- 323 secfalse
- 429 secfalse
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उत्तर : 1. "27 sec"
व्याख्या :
Answer: A) 27 sec Explanation: Time taken to meet for the first time anywhere on the track = length of the track / relative speed = 300 / (15 + 25)5/18 = 300x 18 / 40 x 5 = 27 seconds.
प्र: Find the unit digit of 4198 + 612345 + 34866 + 2411 + 1. 6343 05b5cc77fe4d2b41977750179
5b5cc77fe4d2b41977750179- 13false
- 22false
- 31true
- 40false
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उत्तर : 3. "1"
व्याख्या :
Answer: C) 1 Explanation: Given that, 4198+612345+34866+2411+1 Now Power Cycle of 4 is 4, 6 6 is 6 8 is 8, 4, 2, 6 1 is 1 4198- 198 is even number , So the unit digit value is 6 612345 - It is always 6 34866- 66/4 the remainder is 2 , So the second value is 4 2411- 11 is odd number, So the unit digit value is 4 1 - It is always 1 Total = 21 Therefore, The unit digit is 1

