Answer: C) 0.67 Explanation: To convert a fraction into decimal, just take the number on top which we called the numerator and divide it by the number at the bottom which we called the denominator. 2/3 How it comes : 2 ÷ 3 = 0 bring down the decimal point. 20 ÷ 3 = 6 and carry the remainder 2 to make 20 20 ÷ 3 = 6 and carry the remainder 2 to make 20 20 ÷ 3 = 6 and carry the remainder 2 to make 20 etc... This gives the recurring decimal 0.6666... If we round off to two decimals , then it becomes 0.67.   Hence, decimal fraction of 2/3 = 0.67.

Answer: A) Rs. 2000 Explanation: Let 'x' be the cost price.Now Marked price = x + 30x/100 = 13x/1010% discount = 10/100 x 13x/10 = 13x/100 Selling price = 13x/10 - 13x/100 = 117x/100Given gain = 340Here gain = 117x/100 - x = 17x/100 = 340 => x = Rs. 2000.

Answer: C) 84% Explanation: Let the number be 'x'   Then, according to the given data,  52x-25x52xx100   = 2125x100   = 84%

Answer: C) 13 Explanation: (385/1001) = 5/13 First Number is 5 => Fourth number is 13

Answer: A) 3/2 Explanation: The number of exhaustive events = 100 C₁ = 100. We have 25 primes from 1 to 100. Number of favourable cases are 75. Required probability = 75/50 = 3/2.

Answer: D) 7.65 sec Explanation: Here total distance = 154 + 101 = 255 mtsGiven speed = 120 kmph = 120x5/18 m/secHence, Time = d/s = 255x18/120x5 = 7.65 sec

Answer: A) Rs. 9500 Explanation: Given initial investments ratio = 2 : 3 : 4 At the end of 6 months, A invested an amount such that his total capital became equal to B's initial capital investment i.e, upto 6 months A's investment is 2 and after 6 months his invstment is 3 = B's investment Now, Ratio of investment for one year => A : B : C = (2×6 + 3×6) : (3×12) : (4×12) = 30 : 36 : 48 = 5 : 6 : 8 But given B's profit = 3000 => 6 ratio = 3000 For total => 19 ratio = Rs. 9500.

Answer: B) 1962 Explanation: Arithmetic Series ::   An Arithmetic Series is a series of numbers in which each term increases by a constant amount.   How to find the sum of the Arithmetic Sequence or Series for the given Series ::   When the series contains a large amount of numbers, its impractical to add manually. You can quickly find the sum of any arithmetic sequence by multiplying the average of the first and last term by the number of terms in the sequence.   That is given by Sn = n(a1 + an)2 Where n = number of terms, a1 = first term, an = last term   Here Last term is given by an = a1 + n-1d where d = common difference   Now given Arithmetic Series is    2, 5, 8, 11,...   Here a1 = 2,  d = 3, n = 36    Now, an= a1 + n - 1d a36= 2 + 36 - 13 = 105 + 2 = 107    Now, Sum to 36 terms is given by   S36 = 36(2 + 107)2 = 36 x 1092 = 39242 = 1962       Therefore, Sum to 36 terms of the series 2, 5, 8, 11,... is 1962.