Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: If A1, A2, A3, A4, ..... A10 are speakers for a meeting and A1 always speaks after, A2 then the number of ways they can speak in the meeting is 1945 05b5cc7b4e4d2b419777508a6
5b5cc7b4e4d2b419777508a6- 19!false
- 29!/2false
- 310!false
- 410!/2true
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 4. "10!/2"
व्याख्या :
Answer: D) 10!/2 Explanation: As A1 speaks always after A2, they can speak only in 1st to 9th places and A2 can speak in 2nd to 10 the places only when A1 speaks in 1st place A2 can speak in 9 places the remaining A3, A4, A5,...A10 has no restriction. So, they can speak in 9.8! ways. i.e when A2 speaks in the first place, the number of ways they can speak is 9.8!. When A2 speaks in second place, the number of ways they can speak is 8.8!. When A2 speaks in third place, the number of ways they can speak is 7.8!. When A2 speaks in the ninth place, the number of ways they can speak is 1.8! Therefore,Total Number of ways they can speak = (9+8+7+6+5+4+3+2+1) 8! = 92(9+1)8! = 10!/2
प्र: If three eighth of a number is 141. What will be the approximately value of 32.08% of this number ? 1942 05b5cc6ebe4d2b4197774ee73
5b5cc6ebe4d2b4197774ee73- 1101false
- 2112false
- 3104false
- 4120true
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 4. "120"
व्याख्या :
Answer: D) 120 Explanation: K x 3/8 = 141 => K = 376 376 x 32.08/100 = 120
प्र: Write 0.125 as a percent %? 1942 05b5cc6b3e4d2b4197774d42d
5b5cc6b3e4d2b4197774d42d- 112%false
- 212.5%true
- 313%false
- 413.5%false
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 2. "12.5%"
व्याख्या :
Answer: B) 12.5% Explanation: Here to convert 0.125 into % First convert to fractio Multiply and divide by 1000 => 0.125 x 10001000 = 1251000 = 18 => Now, in percentage18 x 100 = 12.5%
प्र: A wholesale dealer allows a discount of 20 % on the marked price to the retailer. The retailer sells at 5% below the marked price. If the customer pays Rs.19 for an article, what profit is made by the retailer on it ? 1942 05b5cc72ce4d2b4197774f7ab
5b5cc72ce4d2b4197774f7ab- 1Rs. 4false
- 2Rs. 3true
- 3Rs. 5false
- 4Rs. 1false
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 2. "Rs. 3"
व्याख्या :
Answer: B) Rs. 3 Explanation: Let wholesaler dealers marked price = 100%, Retailer's C.P = 80% And the retailer sells at 5% less than the marked price => S.P = 95%If S.P of 95% of the retailer costs Rs.19 to customer,so its C.P of 80% will cost 80 x 19/95 = 16 Profit made by the retailer = 19-16 = Rs.3
प्र: How many iron rods, each of length 7 mts and diameter 2 cms can be made out of 0.88 cubic metre of iron ? 1940 05b5cc77fe4d2b419777501c4
5b5cc77fe4d2b419777501c4- 1500false
- 2600false
- 3400true
- 4300false
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 3. "400"
व्याख्या :
Answer: C) 400 Explanation: Given length of iron rod =7 mts and and diameter of rod = 2 cms => r = 1/100 mts Therefore, Volume of one rod = πr2h cu. m = 227×11002×7cu. m = 115000 cu. m Given volume of iron = 0.88 cu. m Therefore, Number of rods = 0.88×500011 = 400.
प्र: There are four prime numbers written in ascending order of magnitude. The product of the first three is 385 and of the last three is 1001. Find the fourth number ? 1939 05b5cc6dce4d2b4197774e974
5b5cc6dce4d2b4197774e974- 117false
- 219false
- 313true
- 411false
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 3. "13"
व्याख्या :
Answer: C) 13 Explanation: (385/1001) = 5/13 First Number is 5 => Fourth number is 13
प्र: The probability that a number selected at random from the first 100 natural numbers is a composite number is ? 1937 05b5cc6e3e4d2b4197774ec8e
5b5cc6e3e4d2b4197774ec8e- 13/2true
- 22/3false
- 31/2false
- 434/7false
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 1. "3/2"
व्याख्या :
Answer: A) 3/2 Explanation: The number of exhaustive events = 100 C₁ = 100. We have 25 primes from 1 to 100. Number of favourable cases are 75. Required probability = 75/50 = 3/2.
प्र: 640 ml of a mixture contains milk and water in ratio 6:2. How much of the water is to be added to get a new mixture containing half milk and half water ? 1936 05b5cc731e4d2b4197774f7e7
5b5cc731e4d2b4197774f7e7- 1360 mlfalse
- 2320 mltrue
- 3310 mlfalse
- 4330 mlfalse
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 2. "320 ml"
व्याख्या :
Answer: B) 320 ml Explanation: Here total parts of milk and water in the solution is 6+2 = 8 parts. 1part = 640/8 = 80 old mixture contains 6parts of milk and 2 parts of water(6:2). To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same. i.e, 4 x 80 = 320 ml.