Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: 640 ml of a mixture contains milk and water in ratio 6:2. How much of the water is to be added to get a new mixture containing half milk and half water ? 1836 0

  • 1
    360 ml
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  • 2
    320 ml
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  • 3
    310 ml
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  • 4
    330 ml
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उत्तर : 2. "320 ml"
व्याख्या :

Answer: B) 320 ml Explanation: Here total parts of milk and water in the solution is 6+2 = 8 parts. 1part = 640/8 = 80   old mixture contains 6parts of milk and 2 parts of water(6:2).   To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same. i.e, 4 x 80 = 320 ml.

प्र: If three eighth of a number is 141. What will be the approximately value of 32.08% of this number ? 1834 0

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    101
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  • 2
    112
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  • 3
    104
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  • 4
    120
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उत्तर : 4. "120"
व्याख्या :

Answer: D) 120 Explanation: K x 3/8 = 141 => K = 376 376 x 32.08/100 = 120

प्र: How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated ? 1834 0

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    15
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  • 2
    20
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  • 3
    5
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  • 4
    10
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उत्तर : 2. "20"
व्याख्या :

Answer: B) 20 Explanation: Since each number to be divisible by 5, we must have 5 0r 0 at the units place. But in given digits we have only 5.   So, there is one way of doing it.   Tens place can be filled by any of the remaining 5 numbers.So, there are 5 ways of filling the tens place.   The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.   Required number of numbers = (1 x 5 x 4) = 20.

प्र: At an examination in which maximum marks are 500. P got 10% less than Q, Q got 25% more than R and R got 20% less than S. If P got 360 marks what percentage of marks was obtained by S ? 1832 0

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    77
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  • 2
    74
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    80
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  • 4
    83
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उत्तर : 3. "80"
व्याख्या :

Answer: C) 80 Explanation: Let marks obtained by S = M R's marks = 0.80M Q's marks = 1.25 (0.80M) P's marks = (0.90) (1.25) (0.80M) = 0.9M But 0.9M = 360 M = ? M = 400 Hence % of marks obtained by S = 400/500 x 100 = 80%.

प्र: One lady has 2 children, one of her child is boy, what is the probability of having both are boys ? 1831 0

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    1/3
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  • 2
    1/2
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  • 3
    2/3
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  • 4
    2/5
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उत्तर : 1. "1/3"
व्याख्या :

Answer: A) 1/3 Explanation: In a family with 2 children there are four possibilities:1) the first child is a boy and the second child is a boy (bb)2) the first child is a boy and the second child is a girl (bg)3) the first child is a girl and the second child is a boy (gb)4) the first child is a girl and the second child is a girl (gg) But already given that one child is boy. So we have three possibilities of (bb)(bg)(gb).n(E)= both are boys=BB=1n(S)= 3Required probability P = n(E)/n(S) = 1/3.

प्र: Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ? 1829 0

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    3 days
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  • 2
    2 days
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  • 3
    6 days
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  • 4
    12 days
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उत्तर : 3. "6 days"
व्याख्या :

Answer: C) 6 days Explanation: From the given data, 12 children 16 days work,One child’s one day work = 1/192. 8 adults 12 days work,One adult’s one day’s work = 1/96. Work done in 3 days = ((1/96) x 16 x 3) = 1/2 Remaining work = 1 – 1/2 = 1/2 (6 adults+ 4 children)’s 1 day’s work = 6/96 + 4/192 = 1/12 1/12 work is done by them in 1 day. 1/2 work is done by them in 12 x (1/2) = 6 days.

प्र: The cost price of an article is 54% of the marked price. Calculate the gain percent after allowing a discount of 15%  ? 1829 0

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    51.32 %
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  • 2
    49.23 %
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  • 3
    48.4 %
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  • 4
    46.8 %
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उत्तर : 3. "48.4 %"
व्याख्या :

Answer: C) 48.4 % Explanation: Let marked price = Rs. 100. Then, C.P. = RS. 54, S.P. = Rs. 85Gain % = 31/64 x 100 = 48.4%.

प्र: What is 15 of 80 with simple method and examples? 1828 0

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    12.5%
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    18.75%
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    16.55%
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    17.80%
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उत्तर : 2. "18.75%"
व्याख्या :

Answer: B) 18.75% Explanation: Given that to find 15 of 80 => What % of 80 is 15 Let it be 'p' => p% of 80 = 15 => p x 80100 = 15⇒p = 15 x 10080⇒p = 150080 = 18.75   Therefore, 15 is 18.75% of 80 => 18.75% of 80 = 15   Example:: Now, in the similar way we can find 15% of 80 =? => 15x80/100 = p => p = 4 x 3 = 12   Therefore, 15% of 80 = 12

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