Answer: D) 16.38 Explanation: Given, Manideep purchases 30kg of barley at the rate of 11.50/kg nad 20kg at the rate of 14.25/kg. Total cost of the mixture of barley = (30 x 11.50) + (20 x 14.25) => Total cost of the mixture = Rs. 630 Total kgs of the mixture = 30 + 20 = 50kg Cost of mixture/kg = 630/50 = 12.6/kg To make 30% of profit => Selling price for manideep = 12.6 + 30% x 12.6 => Selling price for manideep = 12.6 + 3.78 = 16.38/kg.

Answer: D) 555681 Explanation: Given number is 987 = 3 x 7 x 47. So, required number must be divisible by each one of 3, 7, 47. None of the numbers in 553681 and 555181 are divisible by 3. While 556581 is not divisible by 7.Correct answer is 555681.

Answer: B) 64 & 48 Explanation: Given Karthik + Kalyan = 112 Given that when karthik is at the age of kalyan he is twice of Kalyan's age i.e When he was 48 means Kalyan is at 24 => Present age of Kalyan is 48 And that of Karthik is 112 - 48 = 64

Answer: D) 39 Explanation: Let the two-digit number be 10a + ba + b = 12 --- (1)If a>b, a - b = 6If b>a, b - a = 6If a - b = 6, adding it to equation (1), we get2a = 18 => a =9so b = 12 - a = 3Number would be 93.if b - a = 6, adding it to the equation (1), we get2b = 18 => b = 9a = 12 - b = 3.Number would be 39.There fore, Number would be 39 or 93.

Answer: B) 141.17 % Explanation: Px85100=120   => p = 12000/85 = 141.17 %

Answer: B) 1962 Explanation: Arithmetic Series ::   An Arithmetic Series is a series of numbers in which each term increases by a constant amount.   How to find the sum of the Arithmetic Sequence or Series for the given Series ::   When the series contains a large amount of numbers, its impractical to add manually. You can quickly find the sum of any arithmetic sequence by multiplying the average of the first and last term by the number of terms in the sequence.   That is given by Sn = n(a1 + an)2 Where n = number of terms, a1 = first term, an = last term   Here Last term is given by an = a1 + n-1d where d = common difference   Now given Arithmetic Series is    2, 5, 8, 11,...   Here a1 = 2,  d = 3, n = 36    Now, an= a1 + n - 1d a36= 2 + 36 - 13 = 105 + 2 = 107    Now, Sum to 36 terms is given by   S36 = 36(2 + 107)2 = 36 x 1092 = 39242 = 1962       Therefore, Sum to 36 terms of the series 2, 5, 8, 11,... is 1962.

Answer: D) 81.5 Explanation: Let the number of students in classes A, B and C be P, Q and R respectively.Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.Also given that,(83P + 76Q) / (P + Q) = 79=>4P = 3Q.(76Q + 85R)/(Q + R) = 81=>4R = 5Q,=>Q = 4P/3 and R = 5P/3Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12 = 81.5

Answer: A) 14/33 Explanation: Total number of chairs = (3 + 5 + 4) = 12. Let S be the sample space. Then, n(s)= Number of ways of picking 2 chairs out of 12 = 12×11/2×1 = 66 Let n(E) = number of events of selecting 2 chairs for selecting no white chairs. => 8C2 = 8×7/2×1 = 28 Therefore required probability = 28/66 = 14/33.