Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated ? 1742 05b5cc774e4d2b4197775000c
5b5cc774e4d2b4197775000c- 115false
- 220true
- 35false
- 410false
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उत्तर : 2. "20"
व्याख्या :
Answer: B) 20 Explanation: Since each number to be divisible by 5, we must have 5 0r 0 at the units place. But in given digits we have only 5. So, there is one way of doing it. Tens place can be filled by any of the remaining 5 numbers.So, there are 5 ways of filling the tens place. The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it. Required number of numbers = (1 x 5 x 4) = 20.
प्र: Find the odd one in the number series given below ? 17, 9, 10, 18.5, 35, 90 1741 05b5cc6c5e4d2b4197774dd91
5b5cc6c5e4d2b4197774dd91- 19false
- 210false
- 318.5true
- 490false
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उत्तर : 3. "18.5"
व्याख्या :
Answer: C) 18.5 Explanation: The given series pattern follows 17 9 10 18.5 35 90 × 0.5 + 0.5, × 1 + 1, × 1.5 + 1.5, × 2 + 2, × 2.5 + 2.5 So here 17x0.5 + 0.5 = 9 9x1 + 1 = 10 10x1.5 + 1.5 = 16.5 16.5x2 + 2 = 35 35x2.5 + 2.5 = 90 Here the odd man in the given series is 18.5
प्र: Sambhu buys rice at Rs. 10/kg and puts a price tag on it so as to earn a profit of 20%. However, his faulty balance shows 1000 gm when it is actually 800 gm. What is his actual gain percentage ? 1740 05b5cc709e4d2b4197774f299
5b5cc709e4d2b4197774f299- 150%true
- 225%false
- 375%false
- 460%false
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उत्तर : 1. "50%"
व्याख्या :
Answer: A) 50% Explanation: CP of 1000gm = Rs. 10SP of 800gm = Rs. 12SP of 1000gm =12x1000/800 = Rs. 15 Now take 1000gm as reference to calculate profit.Profit=SP-CP=15-10=Rs. 5Profit % = 5x100/10 = 50%
प्र: In a bag, there are 8 red, 7 blue and 6 green flowers. One of the flower is picked up randomly. What is the probability that it is neither red nor green ? 1740 05b5cc774e4d2b41977750016
5b5cc774e4d2b41977750016- 113true
- 2821false
- 3621false
- 42021false
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उत्तर : 1. "13"
व्याख्या :
Answer: A) Option A Explanation: Total number of flowers = (8+7+6) = 21. Let E = event that the flower drawn is neither red nor green. = event taht the flower drawn is blue. --> n(E)= 7 --> P(E)= 721=13
प्र: Three maths classes: A, B and C take an algebra test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. What is the average score of classes A, B, C ? 1738 05b5cc75ee4d2b4197774fcb6
5b5cc75ee4d2b4197774fcb6- 181false
- 278false
- 380.5false
- 481.5true
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उत्तर : 4. "81.5"
व्याख्या :
Answer: D) 81.5 Explanation: Let the number of students in classes A, B and C be P, Q and R respectively.Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.Also given that,(83P + 76Q) / (P + Q) = 79=>4P = 3Q.(76Q + 85R)/(Q + R) = 81=>4R = 5Q,=>Q = 4P/3 and R = 5P/3Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12 = 81.5
प्र: After working for 8 days, Arun finds that only 13 rd of the work has been done. He employs Akhil who is 60% as efficient as Arun. How many days more would Akhil take to complete the work? 1738 05b5cc76fe4d2b4197774ff67
5b5cc76fe4d2b4197774ff67- 124.5 daysfalse
- 226.6 daystrue
- 325 daysfalse
- 420 daysfalse
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उत्तर : 2. "26.6 days"
व्याख्या :
Answer: B) 26.6 days Explanation: Arun has completed 13rd of the work in 8 days Then he can complete the total work in 13 ---- 8 1 ---- ? = 24 days But given Akhil is only 60% as efficient as Arun Akhil =124×60100=140 Akhil can complete the total work in 40 days Now, remaining 2/3rd of work can be completed in 1 ------ 40 23 ------ ? = 26.66 days.
प्र: 5 sin(x)+ 12 cos(x) + r is always greater than or equal to zero. What is the smallest value satisfied by 'r' ? 1737 05b5cc77fe4d2b419777501bf
5b5cc77fe4d2b419777501bf- 1-13false
- 211false
- 313true
- 4-11false
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उत्तर : 3. "13"
व्याख्या :
Answer: C) 13 Explanation: Given, 5sinx + 12cosx ≥ -r ⇒13513sin x + 1213cos x ≥ -rcosx) ≥ -r 513= cosA => sinA =1213 => 13(sinx cosA + sinA cosx) ≥ -r => 13(sin(x + A)) ≥ -r we know that , -1 ≤ sin (angle) ≤ 1 => 13sin (x + A) ≥ -13 ⇒rmin =13
प्र: In an exhibition, Almond bought a painting for Rs. 20000. He later sold it to Olive for Rs. 23000. Olive sold it to Sarah for double the profit percentage that Almond earned. At what price should Sarah sell this painting to earn 8% profit ? 1737 05b5cc6c4e4d2b4197774dcf6
5b5cc6c4e4d2b4197774dcf6- 1Rs. 34,410false
- 2Rs. 31,184false
- 3Rs. 29,999false
- 4Rs. 32,292true
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उत्तर : 4. "Rs. 32,292"
व्याख्या :
Answer: D) Rs. 32,292 Explanation: Almond Selling price = CP(1 + P%/100) => CP = 20000, SP = 23000 => 23000 = 20000 (1 + P/100) => P% = 100(23000/20000 - 1) = 15 Then, Olive's P% = 30% SP for Olive = CP for Sarah = 23000(1 + 30/100) = 29900 Now Sarah wants to earn profit of 8% => Sp for Sarah = 29900(1 + 8/100) = Rs. 32,292.

