Quantitative Aptitude Practice Question and Answer

Q: A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ? 2078 0

  • 1
    45, 10
    Correct
    Wrong
  • 2
    10, 50
    Correct
    Wrong
  • 3
    9, 50
    Correct
    Wrong
  • 4
    50, 15
    Correct
    Wrong
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Answer : 3. "9, 50"
Explanation :

Answer: C) 9, 50 Explanation: Let the age of A = A, B = B and C = C From given A = 3B 4 years ago, C-4 = 2(A-4); After 4 years A + 4 = 31; A = 27;sub in above B, we get B = 9 C = 2(27 - 4) + 4 = 46 + 4 = 50 Hence B = 9yrs and C = 50yrs.

Q: A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal. 2075 0

  • 1
    31.8%
    Correct
    Wrong
  • 2
    31%
    Correct
    Wrong
  • 3
    33.33%
    Correct
    Wrong
  • 4
    29.85%
    Correct
    Wrong
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Answer : 3. "33.33%"
Explanation :

Answer: C) 33.33% Explanation: Now, take percentage of milk and applying mixture rule 25          100        50 50            25  = 2 : 1   Hence required answer =  1/3 or 33.33%

Q: 18 as a decimal? 2067 0

  • 1
    0.375
    Correct
    Wrong
  • 2
    0.247
    Correct
    Wrong
  • 3
    0.214
    Correct
    Wrong
  • 4
    0.125
    Correct
    Wrong
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Answer : 4. "0.125"
Explanation :

Answer: D) 0.125 Explanation: Here  18 in decimal means 8th part in 1. We know that 110 = 0.1 Then,   18 = ? => ? = 18 x 0.1110= 0.1 x 108= 0.5418= 0.125

Q: How many three digit numbers 'abc' are formed where two of the three digits are same ? 2067 0

  • 1
    252
    Correct
    Wrong
  • 2
    648
    Correct
    Wrong
  • 3
    243
    Correct
    Wrong
  • 4
    900
    Correct
    Wrong
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Answer : 3. "243"
Explanation :

Answer: C) 243 Explanation: Digits are 0,1,2,3,4,5,6,7,8,9. So no. of digits are 10   First all possible case => 9(0 excluded) x 10 x 10 = 900   Second no repetition allowed =>9 x 9 x 8 = 648   Third all digits are same => 9 (111,222,333,444,555,666,777,888,999)   Three digit numbers where two of the three digits are same = 900 - 648 - 9 = 243 ;

Q: 12 days payment to the servant in a cloth showroom in festival season is Rs. 400 plus one shirt. The servant leaves after 9 days and recieves Rs. 280 and a shirt. What is the price of the shirt ? 2067 0

  • 1
    Rs. 80
    Correct
    Wrong
  • 2
    Rs. 120
    Correct
    Wrong
  • 3
    Rs. 70
    Correct
    Wrong
  • 4
    Rs. 100
    Correct
    Wrong
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Answer : 1. "Rs. 80"
Explanation :

Answer: A) Rs. 80 Explanation: The servant worked for 9 days instead of 12 days, he should receive 9/12 of his total payment Let the price of 1 shirt be Rs. S  i.e., 3/4 (400 + S). However, the question states that the servant receive Rs. 280 + S where S is the price of the shirt. By equating the two equations we get 3/4 (400 + S) = 280 + S. Therefore, Price of the shirt S = Rs. 80.

Q: Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m. ? 2066 0

  • 1
    20 kmph
    Correct
    Wrong
  • 2
    18 kmph
    Correct
    Wrong
  • 3
    12 kmph
    Correct
    Wrong
  • 4
    16 kmph
    Correct
    Wrong
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Answer : 3. "12 kmph"
Explanation :

Answer: C) 12 kmph Explanation: Let the distance traveled be x km.Then, x/10 - x/15 = 23x - 2x = 60 => x = 60 km.Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.Required speed = 60/5 = 12 kmph.

Q: A shopkeeper sells two articles at Rs.1000 each, making a profit of 30% on the first article and a loss of 20% on the second article. Find the net profit or loss that he makes ? 2065 0

  • 1
    0.85 %
    Correct
    Wrong
  • 2
    0.95 %
    Correct
    Wrong
  • 3
    1.0 %
    Correct
    Wrong
  • 4
    1.3 %
    Correct
    Wrong
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Answer : 2. "0.95 %"
Explanation :

Answer: B) 0.95 % Explanation: SP of first article = 1000Profit = 30%CP = (SP)x[100/(100+P)] = 10000/13 SP of second article = 1000Loss = 20%CP = (SP)x[100/(100-L)] = 5000/4 = 1250 Total SP = 2000 Total CP = 10000/13 + 1250 = 2019.23 CP is more than SP, he makes a loss. Loss = CP-SP = 2019.23 - 2000 = 19.23Loss Percent = [(19.23)/(2019.23)]x100 = 0.95 %.

Q: Ajay and his wife Reshmi appear in an interview for two vaccancies in the same post. The Probability of Ajay's selection is 1/7 and that of his wife Reshmi's selection is 1/5. What is the probability that only one of them will be selected? 2064 0

  • 1
    5/7
    Correct
    Wrong
  • 2
    1/5
    Correct
    Wrong
  • 3
    2/7
    Correct
    Wrong
  • 4
    2/35
    Correct
    Wrong
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Answer : 3. "2/7"
Explanation :

Answer: C) 2/7 Explanation: P( only one of them will be selected) = p[(E and not F) or (F and not E)]   = PE∩F∪F∩E    = PEPF+PFPE    =17×45+15×67=27

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