Answer: C) 243 Explanation: Digits are 0,1,2,3,4,5,6,7,8,9. So no. of digits are 10   First all possible case => 9(0 excluded) x 10 x 10 = 900   Second no repetition allowed =>9 x 9 x 8 = 648   Third all digits are same => 9 (111,222,333,444,555,666,777,888,999)   Three digit numbers where two of the three digits are same = 900 - 648 - 9 = 243 ;

Answer: A) Rs. 6000 Explanation: Let the sum invested be Rs. P Let the rate of interest be R% per annum => Interest earned for 5 years = (P x 5 x R/100) = PR/20 Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)% => SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100 Hence, PR/20 + 10P/100 = PR/20 + 600 => P = 6000 Therefore, the sum invested is Rs. 6000

Answer: C) 18.5 Explanation: The given series pattern follows   17       9       10       18.5       35       90   × 0.5 + 0.5,   × 1 + 1,   × 1.5 + 1.5,   × 2 + 2,   × 2.5 + 2.5   So here    17x0.5 + 0.5 = 9   9x1 + 1 = 10   10x1.5 + 1.5 = 16.5   16.5x2 + 2 = 35   35x2.5 + 2.5 = 90   Here the odd man in the given series is 18.5

Answer: C) 36 kmph Explanation: Given speed of the first train = 60 km/hr = 60 x 5/18 = 50/3 m/s Let the speed of the second train = x m/s Then, the difference in the speed is given by 503 - x = 12018 => x = 10 m/s => 10 x 18/5 = 36 km/hr

Answer: D) Rs.50,589.47 Explanation: Let the total earnings be Rs.x  Then 412% of x + 14% of (x-12000) =2400  ⇒92×x100+14×x-12000100=2400 =>  x=50,589.47

Answer: A) 48 kmph Explanation: we know that speed = distance traveled/time takenlet the total distance traveled by the car is 2x km.then time taken by it to cover first half is x/60 hour.and for second half is x/40 hour.Then average speed= total distance travelled / total time taken.   i.e. 2xx60+x40   => 2x5x120   = 48 kmph.

Answer: B) 144 km Explanation: Given a jeep travels a certain distance taking 6 hrs in forward journeyDuring the return journey, it takes 4 hrs with an increased speed 12 km/hrLet 'x' be the distance.Now, speed is given by distance/time.Here the difference between both speeds = 12  x4 - x6 = 12  3x - 2x12 = 12   => x = 144 km   Therefore, the distance travelled by the jeep in forward or return journey is x = 144 km.

Answer: C) Rs. 1901 Explanation: P = Rs. 15225, n = 9 months = 3 quarters, R = 16% p.a. per quarter.   Amount = 15225x1+41003   = (15225 x 26/25 x 26/25 x 26/25) = Rs. 17126.05   => C.I. = 17126 - 15625 = Rs. 1901.05.