Answer: A) 5100 sq.m Explanation: Let the breadth of floor be 'b' m. Then, length of the floor is 'l = (b + 25)' Area of the rectangular floor = l x b = (b + 25) × b According to the question, (b + 15) (b + 8) = (b + 25) × b b2 + 8b + 15b + 120 = b2 + 25b 2b = 120 b = 60 m. l = b + 25 = 60 + 25 = 85 m.   Area of the floor = 85 × 60 = 5100 sq.m.

Answer: A) Rs. 6000 Explanation: Let the sum invested be Rs. P Let the rate of interest be R% per annum => Interest earned for 5 years = (P x 5 x R/100) = PR/20 Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)% => SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100 Hence, PR/20 + 10P/100 = PR/20 + 600 => P = 6000 Therefore, the sum invested is Rs. 6000

Answer: C) 13 Explanation: (385/1001) = 5/13 First Number is 5 => Fourth number is 13

Answer: D) 38.57 cm Explanation: We know that perimeter of rectangle = 2(l+b) = 2(8+7)= 30cmGiven perimeter of square is twice the perimeter of rectangle = 2(30) = 60cmTherefore, side of the square is = 1/4 x 60 = 15cmCircumference of the required semicircle = πr + 2r = 227× 152 + 2×152 = 23.57 + 15 = 38.57cm.

Answer: C) 3.75 km Explanation: Let 'd' be the distance between A and BK -time = d/10 + d/9 = 19d/90 hoursL -time = 2d/12 = d/6 hoursWe know that, 10 min = 1/6 hoursThus, time difference between K and L is given as 10 minutes. => 19d/90 - d/6 = 1/6=> (19d-15d)/90 = 1/6=> 4d/90 = 1/6Thus,d= 15/4 km = 3.75 km. hence the distance between A and B is 3.75 km.

Answer: B) 100 Explanation: Given  4 45 of 259.99 = ? % of 1247.9 24/5 x 260 = ? x 1248/100 ? = 1248 x 100/1248 ? = 100.

Answer: A) 48 kmph Explanation: we know that speed = distance traveled/time takenlet the total distance traveled by the car is 2x km.then time taken by it to cover first half is x/60 hour.and for second half is x/40 hour.Then average speed= total distance travelled / total time taken.   i.e. 2xx60+x40   => 2x5x120   = 48 kmph.

Answer: A) 47.5 Explanation: