Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: The number of sequences in which 4 players can sing a song, so that the youngest player may not be the last is ? 1867 0

  • 1
    2580
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  • 2
    3687
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  • 3
    4320
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    गलत
  • 4
    5460
    सही
    गलत
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उत्तर : 3. "4320"
व्याख्या :

Answer: C) 4320 Explanation: Let 'Y' be the youngest player. The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways. The required number of ways = 3(3!) = 4320.

प्र: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B ? 1866 0

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    10 yrs
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  • 2
    11 yrs
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  • 3
    12 yrs
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  • 4
    13 yrs
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उत्तर : 1. "10 yrs"
व्याख्या :

Answer: A) 10 yrs Explanation: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years. (2x + 2) + 2x + x = 27 5x = 25 => x = 5 Hence, B's age = 2x = 10 years.

प्र: Maneela lent Rs. 8000 partly at the rate of 5% and partly at the rate of 6% per annum simple interest. The total interest she get after 2 years is Rs. 820, then in which ratio will Rs. 8000 is to be divided? 1865 0

  • 1
    7:1
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  • 2
    13:5
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  • 3
    15:7
    सही
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  • 4
    2:7
    सही
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उत्तर : 1. "7:1"
व्याख्या :

Answer: A) 7:1 Explanation: Maneela lent Rs. 8000 in two parts,

प्र: Raju sold an article by giving a discount of 8% for Rs. 17,940 and earn profit of 19.6 %. If he did not give discount then how much profit percentage he gets ? 1865 0

  • 1
    27%
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  • 2
    30%
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  • 3
    32%
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  • 4
    25%
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उत्तर : 2. "30%"
व्याख्या :

Answer: B) 30% Explanation: Let the M.R.P of an article be 100 %   Selling price of article =Rs. 17940   If he give a discount of 8 % then S.P = 92 % 92 % = 17490 100 % = 19500   Now C.P of the article is    17490 x 100/119.6 = 15000   If he did not give the discount, then    Required profit percentage =

प्र: A person lends Rs. 1540 for five years and Rs. 1800 for four years. If he gets Rs. 1788 as interest on both amounts, what is the rate of interest ? 1861 0

  • 1
    14.5%
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  • 2
    11%
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  • 3
    12%
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  • 4
    10.5%
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उत्तर : 3. "12%"
व्याख्या :

Answer: C) 12% Explanation: Let the interest rate be r% We know that, S.I = PTR/100 => (1540 x 5 x r)/100  +  (1800 x 4 x r)/100 = 1788 => r = 178800/14900 = 12%

प्र: Question : What is the sum which earned interest ? Statements : a. The total simple interest was Rs. 9000 after 9 years.b. The total of sum and simple interest was double of the sum after 6 years. 1860 0

  • 1
    Only a is sufficient
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  • 2
    Neither a nor b is sufficient
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  • 3
    Only b is sufficient
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  • 4
    Both a and b sufficient
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उत्तर : 4. "Both a and b sufficient"
व्याख्या :

Answer: D) Both a and b sufficient Explanation: Let the sum be Rs. x a. gives, S.I = Rs. 9000 and time = 9 years. b. gives, Sum + S.I for 6 years = 2 x Sum --> Sum = S.I for 6 years. Now, S.I for 9 years = Rs. 9000 S.I for 1 year = Rs. 9000/9 = Rs. 1000. S.I for 6 years = Rs. (1000 x 6)= Rs. 6000. --> x = Rs. 6000 Thus, both a and b are necessary to answer the question.

प्र: A bus covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of bus will have to increase ? 1860 0

  • 1
    85 km/hr
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  • 2
    95 km/hr
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  • 3
    105 km/hr
    सही
    गलत
  • 4
    120 km/hr
    सही
    गलत
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उत्तर : 4. "120 km/hr"
व्याख्या :

Answer: D) 120 km/hr Explanation: Initial speed = 80km/hrTotal distance = 80 x 10 = 800kmNew speed = 800/4 =200km/hrIncrease in speed = 200 - 80 = 120km/hr

प्र: K, L and M can do a piece of work in 20, 30 and 60 days respectively. In how many days can K do the total work if he is assisted by L and M on every third day ? 1860 0

  • 1
    15 days
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  • 2
    13 days
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  • 3
    12 days
    सही
    गलत
  • 4
    10 days
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उत्तर : 1. "15 days"
व्याख्या :

Answer: A) 15 days Explanation: In one day work done by K = 1/20 Work done by K in 2 days = 1/10   Work done by K,L,M on 3rd day =1/20 + 1/30 + 1/60 = 1/10 Therefore, workdone in 3 days is = 1/10 + 1/10 = 1/5   1/5th of the work will be completed at the end of 3 days. The remaining work = 1 - 1/5 = 4/5 1/5 of work is completed in 3 days Total work wiil be done in 3 x 5 = 15 days.

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