Quantitative Aptitude Practice Question and Answer

Q: The price of an article has been reduced by 35%. In order to restore the original price the new price must be increased by ? 1964 0

  • 1
    51.8 %
    Correct
    Wrong
  • 2
    49.25 %
    Correct
    Wrong
  • 3
    47.2 %
    Correct
    Wrong
  • 4
    53.84 %
    Correct
    Wrong
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Answer : 4. "53.84 %"
Explanation :

Answer: D) 53.84 % Explanation: 100 65 -------65 ------- 35100 ------ ? => 53.84 %

Q: Question : What is the sum which earned interest ? Statements : a. The total simple interest was Rs. 9000 after 9 years.b. The total of sum and simple interest was double of the sum after 6 years. 1963 0

  • 1
    Only a is sufficient
    Correct
    Wrong
  • 2
    Neither a nor b is sufficient
    Correct
    Wrong
  • 3
    Only b is sufficient
    Correct
    Wrong
  • 4
    Both a and b sufficient
    Correct
    Wrong
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Answer : 4. "Both a and b sufficient"
Explanation :

Answer: D) Both a and b sufficient Explanation: Let the sum be Rs. x a. gives, S.I = Rs. 9000 and time = 9 years. b. gives, Sum + S.I for 6 years = 2 x Sum --> Sum = S.I for 6 years. Now, S.I for 9 years = Rs. 9000 S.I for 1 year = Rs. 9000/9 = Rs. 1000. S.I for 6 years = Rs. (1000 x 6)= Rs. 6000. --> x = Rs. 6000 Thus, both a and b are necessary to answer the question.

Q: K, L and M can do a piece of work in 20, 30 and 60 days respectively. In how many days can K do the total work if he is assisted by L and M on every third day ? 1963 0

  • 1
    15 days
    Correct
    Wrong
  • 2
    13 days
    Correct
    Wrong
  • 3
    12 days
    Correct
    Wrong
  • 4
    10 days
    Correct
    Wrong
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Answer : 1. "15 days"
Explanation :

Answer: A) 15 days Explanation: In one day work done by K = 1/20 Work done by K in 2 days = 1/10   Work done by K,L,M on 3rd day =1/20 + 1/30 + 1/60 = 1/10 Therefore, workdone in 3 days is = 1/10 + 1/10 = 1/5   1/5th of the work will be completed at the end of 3 days. The remaining work = 1 - 1/5 = 4/5 1/5 of work is completed in 3 days Total work wiil be done in 3 x 5 = 15 days.

Q: A merchant commences with a certain capital and gains annually at the rate of 30 per cent. At the end of 2 years he has worth Rs 10,000. What was the original capital? 1961 0

  • 1
    Rs. 4987
    Correct
    Wrong
  • 2
    Rs. 5148
    Correct
    Wrong
  • 3
    Rs. 5917
    Correct
    Wrong
  • 4
    Rs. 6254
    Correct
    Wrong
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Answer : 3. "Rs. 5917"
Explanation :

Answer: C) Rs. 5917 Explanation: Let the Original capital amount be Rs. P Given after 2 years the amount is Rs. 10000 Rate of interest = 30% According to the question, P x 130100 x 130100 = 10000=> P = 1000000169 = 5917 Therefore, the capital amount P = Rs. 5917

Q: 5% of 40,000 is 1960 0

  • 1
    20000
    Correct
    Wrong
  • 2
    2000
    Correct
    Wrong
  • 3
    200
    Correct
    Wrong
  • 4
    20
    Correct
    Wrong
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Answer : 2. "2000"
Explanation :

Answer: B) 2000 Explanation: 5% of 40,000  = 5100 × 40,000 = 5 × 400 = 2,000     Hence, 5% of 40,000 = 2,000.

Q: Raju sold an article by giving a discount of 8% for Rs. 17,940 and earn profit of 19.6 %. If he did not give discount then how much profit percentage he gets ? 1956 0

  • 1
    27%
    Correct
    Wrong
  • 2
    30%
    Correct
    Wrong
  • 3
    32%
    Correct
    Wrong
  • 4
    25%
    Correct
    Wrong
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Answer : 2. "30%"
Explanation :

Answer: B) 30% Explanation: Let the M.R.P of an article be 100 %   Selling price of article =Rs. 17940   If he give a discount of 8 % then S.P = 92 % 92 % = 17490 100 % = 19500   Now C.P of the article is    17490 x 100/119.6 = 15000   If he did not give the discount, then    Required profit percentage =

Q: 9 17 11 19 13 What Are The Next Three Numbers In The Given Number Series? 1956 0

  • 1
    17, 10, 18
    Correct
    Wrong
  • 2
    19, 14, 23
    Correct
    Wrong
  • 3
    21, 15, 23
    Correct
    Wrong
  • 4
    19, 13, 22
    Correct
    Wrong
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Answer : 3. "21, 15, 23"
Explanation :

Answer: C) 21, 15, 23 Explanation: Given number series is 9 17 11 19 13  Here the pattern is 9 9 + 8 = 17 17 - 6 = 11 11 + 8 = 19 19 - 6 = 13 13 + 8 = 21 21 - 6 = 15 15 + 8 = 23

Q: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ? 1954 0

  • 1
    2/3
    Correct
    Wrong
  • 2
    1/2
    Correct
    Wrong
  • 3
    7/8
    Correct
    Wrong
  • 4
    4/5
    Correct
    Wrong
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Answer : 2. "1/2"
Explanation :

Answer: B) 1/2 Explanation: Multiples of 3 below 20 are 3, 6, 9, 12, 15, 18 Multiples of 5 below 20 are 5, 10, 15, 20 Required number of possibilities = 10Total number of possibilities = 20Required probability = 10/20 = 1/2.

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