Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm) 1494 05b5cc73de4d2b4197774f943
5b5cc73de4d2b4197774f943- 180%true
- 270%false
- 375%false
- 462%false
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उत्तर : 1. "80%"
व्याख्या :
Answer: A) 80% Explanation: Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm. After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm. So % of water = 100 x 60/75 = 80%.
प्र: A town has a population of 4000 requires 140 liters of water per head. It has a tank measuring 18m x 12m x 8m. The water of this tank will suffice for ____ days? 1493 05b5cc6bfe4d2b4197774da60
5b5cc6bfe4d2b4197774da60- 13true
- 24false
- 35false
- 42false
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उत्तर : 1. "3"
व्याख्या :
Answer: A) 3 Explanation: Water required = 4000 x 140 = 560000 lit = 560 cu.m (1 cu.m = 1000 lit) Volume of tank = 18 x 12 x 8 = 1728 cu.m Water of this tank will suffice for = 1728/560 = 3 days.
प्र: P can do a piece of work in 5 less days than Q. If both of them can do the same work in 1119days, in how many days will Q alone do the same work ? 1493 05b5cc6c2e4d2b4197774dbcd
5b5cc6c2e4d2b4197774dbcd- 124 daysfalse
- 225 daystrue
- 320 daysfalse
- 419 daysfalse
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उत्तर : 2. "25 days"
व्याख्या :
Answer: B) 25 days Explanation: Let Q complete that work in 'L' days => 1L + 1L-5 = 9100 => 9L2-245L+500=0 L = 25 days.
प्र: A 260 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train ? 1493 05b5cc6d6e4d2b4197774e651
5b5cc6d6e4d2b4197774e651- 1240 mtstrue
- 2270 mtsfalse
- 3260 mtsfalse
- 4250 mtsfalse
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उत्तर : 1. "240 mts"
व्याख्या :
Answer: A) 240 mts Explanation: Relative speed = 120 + 80 = 200 km/hr.= 200 x 5/18 = 500/9 m/sec. Let the length of the other train be L mts.Then, (L + 260)/9 = 500/9 => L = 240 mts.
प्र: [(24)2+(27)2]÷? = 9.0625 1492 05b5cc7c8e4d2b41977750e31
5b5cc7c8e4d2b41977750e31- 1121false
- 2144true
- 3169false
- 481false
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उत्तर : 2. "144"
व्याख्या :
Answer: B) 144 Explanation:
प्र: A person walking 6/7 of his usual rate is 30 minutes late. What is his usual time ? 1492 05b5cc720e4d2b4197774f62c
5b5cc720e4d2b4197774f62c- 12 hrs 50 minfalse
- 23 hrs 25 minfalse
- 33 hrstrue
- 42 hrs 5 minfalse
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उत्तर : 3. "3 hrs"
व्याख्या :
Answer: C) 3 hrs Explanation: Let t be the usual time. If the usual rate is 1 unit, then the unusual rate is 6/7.Balance by the distance,1 x t = (6/7)(t + 30)7t = 6(t + 30)we get t as,t = 180 minutes = 3 hrs.
प्र: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B ? 1491 05b5cc6e7e4d2b4197774ed6f
5b5cc6e7e4d2b4197774ed6f- 110 yrstrue
- 211 yrsfalse
- 312 yrsfalse
- 413 yrsfalse
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उत्तर : 1. "10 yrs"
व्याख्या :
Answer: A) 10 yrs Explanation: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years. (2x + 2) + 2x + x = 27 5x = 25 => x = 5 Hence, B's age = 2x = 10 years.
प्र: In an old Palace there are 50 stairs to go on top floor. Each is 20 cm high, 30 cm wide and 60 cm long. If all the stairs are re-plastered at the rate of Rs. 4 per 100 sq.cm. What is the expenditure ? 1490 05b5cc6cbe4d2b4197774e0f9
5b5cc6cbe4d2b4197774e0f9- 1Rs. 4680false
- 2Rs. 7600false
- 3Rs. 6000true
- 4Rs. 5480false
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उत्तर : 3. "Rs. 6000"
व्याख्या :
Answer: C) Rs. 6000 Explanation: Total are of all stairs = 50 (20x60 + 30x60) = 50 (1200 + 1800) = 50 x 3000 = 150000 sq cm. Given rate of 100 sq cm = Rs. 4 Then for 150000 sq. cm = ? => 4 x 150000/100 = Rs. 6000

