Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is 1615 0

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    196 mts
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  • 2
    220 mts
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  • 3
    230 mts
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  • 4
    245 mts
    सही
    गलत
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उत्तर : 4. "245 mts"
व्याख्या :

Answer: D) 245 mts Explanation: Let the length of the brigade is x mtsThen Distance = 130 + x mtsgiven speed = 45 kmph = 45 x5/18 m/sTime = 30 secT = D/S => 30 = 130+x/(45x5/18)=> x = 245 mts.

प्र: A man reads 3/7 of a book on a day and 2/5 of the remaining, on the second day. If the number of pages still unread are 36, how many pages did the book contain ? 1615 0

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    105
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  • 2
    101
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  • 3
    98
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  • 4
    109
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उत्तर : 1. "105"
व्याख्या :

Answer: A) 105 Explanation: Let number of pages in a book = p According to questions p - [3p/7 + (2/5 x 4p/7)] = 36 = p - 23p/35 = 36 => 12p = 36 × 35 p = 105

प्र: The compound interest on a certain sum for 2 years at 10% per annum is Rs. 1155. The simple interest on the same sum for double the time at half the rate percent per annum is ? 1614 1

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    Rs. 1100
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  • 2
    Rs. 5500
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  • 3
    Rs. 1400
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    गलत
  • 4
    Rs. 4120
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उत्तर : 1. "Rs. 1100"
व्याख्या :

Answer: A) Rs. 1100 Explanation: Let the sum be Rs.x. Then,     x1+101002-x=1155   ⇒x11102-1=1155   => x =5500   sum = Rs. 5500.   So, S.I = Rs. 5500×5×4100 = 1100

प्र: Question : What is the sum which earned interest ? Statements : a. The total simple interest was Rs. 9000 after 9 years.b. The total of sum and simple interest was double of the sum after 6 years. 1614 0

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    Only a is sufficient
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  • 2
    Neither a nor b is sufficient
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  • 3
    Only b is sufficient
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  • 4
    Both a and b sufficient
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उत्तर : 4. "Both a and b sufficient"
व्याख्या :

Answer: D) Both a and b sufficient Explanation: Let the sum be Rs. x a. gives, S.I = Rs. 9000 and time = 9 years. b. gives, Sum + S.I for 6 years = 2 x Sum --> Sum = S.I for 6 years. Now, S.I for 9 years = Rs. 9000 S.I for 1 year = Rs. 9000/9 = Rs. 1000. S.I for 6 years = Rs. (1000 x 6)= Rs. 6000. --> x = Rs. 6000 Thus, both a and b are necessary to answer the question.

प्र: Anu's present age is 9 years more than that of what Raj's age will be after five years. Raj's present age is seven years more than that of what Renu's age was 4 years ago. Renu's present age is 19 years. What will be Anu's age after 5 years ? 1613 0

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    39 yrs
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  • 2
    36 yrs
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  • 3
    46 yrs
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  • 4
    41 yrs
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उत्तर : 4. "41 yrs"
व्याख्या :

Answer: D) 41 yrs Explanation: Anu = (Raj + 5) + 9 = Raj + 14 -------- (I) Raj = (Renu - 4) + 7 = Renu + 3 ------- (II) Raj's age = 19 + 3 = 22 years After 5 years Anu's age = 22 + 14 + 5 = 41 years

प्र: Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m. ? 1612 0

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    20 kmph
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  • 2
    18 kmph
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  • 3
    12 kmph
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  • 4
    16 kmph
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उत्तर : 3. "12 kmph"
व्याख्या :

Answer: C) 12 kmph Explanation: Let the distance traveled be x km.Then, x/10 - x/15 = 23x - 2x = 60 => x = 60 km.Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.Required speed = 60/5 = 12 kmph.

प्र: In how many ways can letter of the word RAILINGS arrange so that R and S always come together? 1611 0

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    1260
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  • 2
    2520
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  • 3
    5040
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  • 4
    1080
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उत्तर : 3. "5040"
व्याख्या :

Answer: C) 5040 Explanation: The number of ways in which the letters of the word RAILINGS can be arranged such that R & S always come together is   Count R & S as only 1 space or letter so that RS or SR can be arranged => 7! x 2!   But in the word RAILINGS, I repeated for 2 times => 7! x 2!/2! = 7! ways = 5040 ways.

प्र: A bus covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of bus will have to increase ? 1610 0

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    85 km/hr
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  • 2
    95 km/hr
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  • 3
    105 km/hr
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  • 4
    120 km/hr
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उत्तर : 4. "120 km/hr"
व्याख्या :

Answer: D) 120 km/hr Explanation: Initial speed = 80km/hrTotal distance = 80 x 10 = 800kmNew speed = 800/4 =200km/hrIncrease in speed = 200 - 80 = 120km/hr

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