Quantitative Aptitude Practice Question and Answer
8Q: A man reads 3/7 of a book on a day and 2/5 of the remaining, on the second day. If the number of pages still unread are 36, how many pages did the book contain ? 1611 05b5cc6c3e4d2b4197774dc4f
5b5cc6c3e4d2b4197774dc4f- 1105true
- 2101false
- 398false
- 4109false
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Answer : 1. "105"
Explanation :
Answer: A) 105 Explanation: Let number of pages in a book = p According to questions p - [3p/7 + (2/5 x 4p/7)] = 36 = p - 23p/35 = 36 => 12p = 36 × 35 p = 105
Q: The compound interest on a certain sum for 2 years at 10% per annum is Rs. 1155. The simple interest on the same sum for double the time at half the rate percent per annum is ? 1611 15b5cc767e4d2b4197774fdfc
5b5cc767e4d2b4197774fdfc- 1Rs. 1100true
- 2Rs. 5500false
- 3Rs. 1400false
- 4Rs. 4120false
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Answer : 1. "Rs. 1100"
Explanation :
Answer: A) Rs. 1100 Explanation: Let the sum be Rs.x. Then, x1+101002-x=1155 ⇒x11102-1=1155 => x =5500 sum = Rs. 5500. So, S.I = Rs. 5500×5×4100 = 1100
Q: The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is 1608 05b5cc6d9e4d2b4197774e80c
5b5cc6d9e4d2b4197774e80c- 1196 mtsfalse
- 2220 mtsfalse
- 3230 mtsfalse
- 4245 mtstrue
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Answer : 4. "245 mts"
Explanation :
Answer: D) 245 mts Explanation: Let the length of the brigade is x mtsThen Distance = 130 + x mtsgiven speed = 45 kmph = 45 x5/18 m/sTime = 30 secT = D/S => 30 = 130+x/(45x5/18)=> x = 245 mts.
Q: Question : What is the sum which earned interest ? Statements : a. The total simple interest was Rs. 9000 after 9 years.b. The total of sum and simple interest was double of the sum after 6 years. 1608 05b5cc767e4d2b4197774fe10
5b5cc767e4d2b4197774fe10- 1Only a is sufficientfalse
- 2Neither a nor b is sufficientfalse
- 3Only b is sufficientfalse
- 4Both a and b sufficienttrue
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Answer : 4. "Both a and b sufficient"
Explanation :
Answer: D) Both a and b sufficient Explanation: Let the sum be Rs. x a. gives, S.I = Rs. 9000 and time = 9 years. b. gives, Sum + S.I for 6 years = 2 x Sum --> Sum = S.I for 6 years. Now, S.I for 9 years = Rs. 9000 S.I for 1 year = Rs. 9000/9 = Rs. 1000. S.I for 6 years = Rs. (1000 x 6)= Rs. 6000. --> x = Rs. 6000 Thus, both a and b are necessary to answer the question.
Q: 3, 12, 5, ? 1608 05b5cc6b9e4d2b4197774d725
5b5cc6b9e4d2b4197774d725- 136false
- 226false
- 330true
- 424false
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Answer : 3. "30"
Explanation :
Answer: C) 30 Explanation: 332 + 3 = 12552 + 5 = 30
Q: A bus covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of bus will have to increase ? 1606 05b5cc6cfe4d2b4197774e2dc
5b5cc6cfe4d2b4197774e2dc- 185 km/hrfalse
- 295 km/hrfalse
- 3105 km/hrfalse
- 4120 km/hrtrue
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Answer : 4. "120 km/hr"
Explanation :
Answer: D) 120 km/hr Explanation: Initial speed = 80km/hrTotal distance = 80 x 10 = 800kmNew speed = 800/4 =200km/hrIncrease in speed = 200 - 80 = 120km/hr
Q: In how many ways can letter of the word RAILINGS arrange so that R and S always come together? 1606 05b5cc6b9e4d2b4197774d6a8
5b5cc6b9e4d2b4197774d6a8- 11260false
- 22520false
- 35040true
- 41080false
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Answer : 3. "5040"
Explanation :
Answer: C) 5040 Explanation: The number of ways in which the letters of the word RAILINGS can be arranged such that R & S always come together is Count R & S as only 1 space or letter so that RS or SR can be arranged => 7! x 2! But in the word RAILINGS, I repeated for 2 times => 7! x 2!/2! = 7! ways = 5040 ways.
Q: Anu's present age is 9 years more than that of what Raj's age will be after five years. Raj's present age is seven years more than that of what Renu's age was 4 years ago. Renu's present age is 19 years. What will be Anu's age after 5 years ? 1605 05b5cc6cae4d2b4197774dfd4
5b5cc6cae4d2b4197774dfd4- 139 yrsfalse
- 236 yrsfalse
- 346 yrsfalse
- 441 yrstrue
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Answer : 4. "41 yrs"
Explanation :
Answer: D) 41 yrs Explanation: Anu = (Raj + 5) + 9 = Raj + 14 -------- (I) Raj = (Renu - 4) + 7 = Renu + 3 ------- (II) Raj's age = 19 + 3 = 22 years After 5 years Anu's age = 22 + 14 + 5 = 41 years