Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present ? 1835 05b5cc6dce4d2b4197774e983
5b5cc6dce4d2b4197774e983- 136 yrsfalse
- 238 yrsfalse
- 340 yrstrue
- 442 yrsfalse
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उत्तर : 3. "40 yrs"
व्याख्या :
Answer: C) 40 yrs Explanation: Let the mother's present age be x years. Then, the person's present age = 2/5 x years. (2x/5 + 8) = 1/2 (x + 8) 2(2x + 40) = 5(x + 8) => x = 40.
प्र: Two candidates fought in a municipality election. One of them got 54% of the total votes pooled and won by 1080 votes. What was the total number of votes polled ? 1835 05b5cc74fe4d2b4197774fb2b
5b5cc74fe4d2b4197774fb2b- 112000false
- 213500true
- 315400false
- 411000false
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उत्तर : 2. "13500"
व्याख्या :
Answer: B) 13500 Explanation: Given in municipality election 54% votes have won by 1080 Let the total number of votes be x. 54x100 - 46x100 = 1080 8x = 108000 x = 13,500 Therefore, total number of votes = 13,500.
प्र: Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is : 1834 05b5cc6eee4d2b4197774ef09
5b5cc6eee4d2b4197774ef09- 183false
- 289false
- 385true
- 479false
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उत्तर : 3. "85"
व्याख्या :
Answer: C) 85 Explanation: Since the numbers are co-prime, they contain only 1 as the common factor.Also, the given two products have the middle number in common.So, middle number = H.C.F of 551 and 1073 = 29;First number = 551/29 = 19Third number = 1073/29 = 37.Required sum = 19 + 29 + 37 = 85.
प्र: What value will come in place of question mark (?) in the number - series given below ? 4, 30, ?, 1440, 7195, 71940 1833 05b5cc6c4e4d2b4197774dca9
5b5cc6c4e4d2b4197774dca9- 1145true
- 2545false
- 3650false
- 4999false
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उत्तर : 1. "145"
व्याख्या :
Answer: A) 145 Explanation: 4 30 ? 1440 7195 71940 Here the given series follows a pattern of 4 4 x 10 - 10 = 30 30 x 5 - 5 = 145 145 x 10 - 10 = 1440 1440 x 5 - 5 = 7195 7195 x 10 - 10 = 71940 Hence, the missing number is 145
प्र: 9 girls working 7 hours a day can complete a piece of work in 15 day. In how many days can 6 girls working for 9 hours a day, complete the same piece of work? 1833 05b5cc6b3e4d2b4197774d3c8
5b5cc6b3e4d2b4197774d3c8- 135/4 daysfalse
- 217.5 daystrue
- 319 3/4 daysfalse
- 437/3 daysfalse
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उत्तर : 2. "17.5 days"
व्याख्या :
Answer: B) 17.5 days Explanation: Let the number of days be 'p' As the work is same, we know that M1 x D1 x H1 = M2 x D2 x H2 Where M = Men, D = Days, H = Hours per day Here M1 = 9, D1 = 15, H1 = 7 M2 = 6, D2 = p, H2 = 9 => 9 x 15 x 7 = 6 x p x 9 => p = 35/2 = 17.5 days.
प्र: In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ? 1831 05b5cc6c6e4d2b4197774de5e
5b5cc6c6e4d2b4197774de5e- 12:3false
- 24:3false
- 33:4false
- 43:2true
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उत्तर : 4. "3:2"
व्याख्या :
Answer: D) 3:2 Explanation: Let he mixes the oils in the ratio = x : y Then, the cost price of the oils = 60x + 65y Given selling price = Rs. 68.20 => Selling price = 68.20(x+y) Given profit = 10% = SP - CP => 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y) => 6x + 6.5y = 8.20x + 3.20y =>2.2x = 3.3y => x : y = 3 : 2
प्र: The total of the ages of Ashok, Akbar and Anil is 65 years. What was the total of their ages six years ago ? 1831 05b5cc723e4d2b4197774f695
5b5cc723e4d2b4197774f695- 159false
- 243false
- 357false
- 447true
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उत्तर : 4. "47"
व्याख्या :
Answer: D) 47 Explanation: Let their ages be x, y, zHence given that x + y + z = 65Now, six years ago x age is x - 6, y is y - 6 and that of z is z - 6Then the sum of their ages six years ago is (x + y + z) - (6 + 6 + 6) = 65 - 18 = 47
प्र: The number of ways that 7 teachers and 6 students can sit around a table so that no two students are together is 1831 05b5cc7b4e4d2b419777508a1
5b5cc7b4e4d2b419777508a1- 17! x 7!false
- 27! x 6!true
- 36! x 6!false
- 47! x 5!false
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उत्तर : 2. "7! x 6!"
व्याख्या :
Answer: B) 7! x 6! Explanation: The students should sit in between two teachers. There are 7 gaps in between teachers when they sit in a roundtable. This can be done in 7P6ways. 7 teachers can sit in (7-1)! ways. Required no.of ways is = 7P6.6! = 7!.6!

