Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: There are two numbers such that the sum of twice the first number and thrice the second number is 300 and the sum of thrice the first number and twice the second number is 265. Which is the largest number ? 1902 05b5cc7c7e4d2b41977750db4
5b5cc7c7e4d2b41977750db4- 124false
- 239false
- 385false
- 474true
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उत्तर : 4. "74"
व्याख्या :
Answer: D) 74 Explanation:
प्र: If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon? 1901 05b5cc6bfe4d2b4197774da42
5b5cc6bfe4d2b4197774da42- 114 kmphfalse
- 213 kmphfalse
- 312 kmphtrue
- 411 kmphfalse
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उत्तर : 3. "12 kmph"
व्याख्या :
Answer: C) 12 kmph Explanation: The distance is constant in this case. Let the time taken for travel with a speed of 10 kmph be 't'. Now the speed of 15 kmph is 3/2 times the speed of 10 kmph. Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time) Extra time taken = t - 2t/3 = t/3 => 1pm - 11am = 2hrs => t/3 = 2h => t = 6 hrs. Now, Distance = speed x time = 10 x 6 = 60 kms Time he takes to reach at noon = 6 - 1 = 5 hrs Now, Speed = 60/5 = 12 kmph.
प्र: What is the sum of all 3 digits number that can be formed using digits 0,1,2,3,4,5 with no repitition ? 1901 05b5cc709e4d2b4197774f2a3
5b5cc709e4d2b4197774f2a3- 128450false
- 226340false
- 332640true
- 436450false
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उत्तर : 3. "32640"
व्याख्या :
Answer: C) 32640 Explanation: We know that zero can't be in hundreds place. But let's assume that our number could start with zero. The formula to find sum of all numbers in a permutation is 111 x no of ways numbers can be formed for a number at given position x sum of all given digits No of 1 s depends on number of digits So,the answer us 111 x 20 x (0+1+2+3+4+5) = 33300 We got 20 as follows. If we have 0 in units place we can form a number in 4*5 ways. This is for all numbers. So we have substituted 20 in formula. Now, this is not the final answer because we have included 0 in hundreds place. so we have to remove the sum of all numbers that starts with 0. This is nothing but the sum of all 2 digits numbers formed by 1 2 3 4 5. Because 0 at first place makes it a 2 digit number. So the sum for this is 11 x 4 x (1+2+3+4+5). =660 Hope u understood why we use 4. Each number can be formed in 4x1 ways So, the final answer is 33300-660 = 32640
प्र: The number of ways that 7 teachers and 6 students can sit around a table so that no two students are together is 1900 05b5cc7b4e4d2b419777508a1
5b5cc7b4e4d2b419777508a1- 17! x 7!false
- 27! x 6!true
- 36! x 6!false
- 47! x 5!false
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उत्तर : 2. "7! x 6!"
व्याख्या :
Answer: B) 7! x 6! Explanation: The students should sit in between two teachers. There are 7 gaps in between teachers when they sit in a roundtable. This can be done in 7P6ways. 7 teachers can sit in (7-1)! ways. Required no.of ways is = 7P6.6! = 7!.6!
प्र: A laborer is engaged for 30 days on the condition that he receives Rs.25 for each day he works and is fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many days was he absent ? 1897 05b5cc6dfe4d2b4197774ead0
5b5cc6dfe4d2b4197774ead0- 110 daystrue
- 214 daysfalse
- 311 daysfalse
- 49 daysfalse
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उत्तर : 1. "10 days"
व्याख्या :
Answer: A) 10 days Explanation: For 30 days he receives 30 x 25 = 750 Actually he gets 425 Therefore, Fine is 750 - 425 = 325 => No of days absent = 325/(25+7.50)= 10
प्र: If x = 2 + 223 + 213 then find the value of x3-6x2+6x ? 1894 05b5cc745e4d2b4197774fa09
5b5cc745e4d2b4197774fa09- 11false
- 22true
- 33false
- 44false
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उत्तर : 2. "2"
व्याख्या :
Answer: B) 2 Explanation: Given that x = 2+ 223 + 213 So x - 2 = 223 + 213 Now cubing on both sides, we get => x3-8-6x2+12x = 4 + 2 + 6(x-2) Therefore, x3-6x2+6x = -6 + 8 = 2
प्र: A woman fills a bucket in 6 minutes. 1845 buckets have to be filled from 8 am. to 9:30 am. How many woman employees should be employed for this task? 1892 05b5cc6b5e4d2b4197774d543
5b5cc6b5e4d2b4197774d543- 1111false
- 2117false
- 3123true
- 4139false
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उत्तर : 3. "123"
व्याख्या :
Answer: C) 123 Explanation: We know that, M1 × D1W1 = M2 × D2W2 Here M1 = 1, D1 = 6 min, W1 = 1 and M2 = M, D2 = 90 min, W2 = 1845 1 × 61 = M × 901845 => M = 123
प्र: 12 men complete a work in 9 days. After they have worked for 6 days, 4 more men join them. How many days will they take to complete the remaining work ? 1892 05b5cc6d7e4d2b4197774e700
5b5cc6d7e4d2b4197774e700- 12 daysfalse
- 22.5 daysfalse
- 32.25 daystrue
- 43 daysfalse
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उत्तर : 3. "2.25 days"
व्याख्या :
Answer: C) 2.25 days Explanation: 1 man's 1 day work = 1/108 12 men's 6 day's work = 1/9 x 6 = 2/3 Remaining work = 1 - 2/3 = 1/3 16 men's 1 day work = 1/108 x 16 = 4/274/27 work is done by them in 1 day. 1/3 work is done by them in 27/4 x 1/3 = 9/4 days.

