Quantitative Aptitude Practice Question and Answer
8Q: In how many different ways can the letters of the word 'POVERTY' be arranged ? 1560 05b5cc6b4e4d2b4197774d4bb
5b5cc6b4e4d2b4197774d4bb- 12520false
- 25040true
- 31260false
- 4Nonefalse
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Answer : 2. "5040"
Explanation :
Answer: B) 5040 Explanation: The 7 letters word 'POVERTY' be arranged in 7P7 ways = 7! = 5040 ways.
Q: A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present ? 1559 05b5cc6dce4d2b4197774e983
5b5cc6dce4d2b4197774e983- 136 yrsfalse
- 238 yrsfalse
- 340 yrstrue
- 442 yrsfalse
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Answer : 3. "40 yrs"
Explanation :
Answer: C) 40 yrs Explanation: Let the mother's present age be x years. Then, the person's present age = 2/5 x years. (2x/5 + 8) = 1/2 (x + 8) 2(2x + 40) = 5(x + 8) => x = 40.
Q: The breadth of a rectangular field is 75% of its length. If perimeter of the field is 1050 m, what will be th area of field ? 1559 05b5cc6c8e4d2b4197774df0a
5b5cc6c8e4d2b4197774df0a- 165700 sq.mfalse
- 254500 sq.mfalse
- 378700 sq.mfalse
- 467500 sq.mtrue
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Answer : 4. "67500 sq.m"
Explanation :
Answer: D) 67500 sq.m Explanation: Let the length be 'l' and breadth be 'b'. b = l × 3/4__________(a) 2(l+b) = 1050 l+b = 525___________(b) From equations (a) and (b), l = 300m, b = 225 m Area = l × b = 300 × 225 = 67500 sq.m.
Q: The total of the ages of Ashok, Akbar and Anil is 65 years. What was the total of their ages six years ago ? 1559 05b5cc723e4d2b4197774f695
5b5cc723e4d2b4197774f695- 159false
- 243false
- 357false
- 447true
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Answer : 4. "47"
Explanation :
Answer: D) 47 Explanation: Let their ages be x, y, zHence given that x + y + z = 65Now, six years ago x age is x - 6, y is y - 6 and that of z is z - 6Then the sum of their ages six years ago is (x + y + z) - (6 + 6 + 6) = 65 - 18 = 47
Q: One third of a Number is 96. What will 67% of that Number be? 1558 05b5cc7c8e4d2b41977750e04
5b5cc7c8e4d2b41977750e04- 1192.96true
- 2181.44false
- 3169.92false
- 4204.48false
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Answer : 1. "192.96"
Explanation :
Answer: A) 192.96 Explanation: Let the Number be x. Given that one third of a Number is 96. i.e x = 3 x 96 = 288. 67% of x = x×67100=288×67100=192.96
Q: In a triangle ABC, angle 'a' is the smallest one & A+7B = 112. Find the range of value 'c' ? 1557 05b5cc6f4e4d2b4197774efe6
5b5cc6f4e4d2b4197774efe6- 1138 to 164false
- 2125 to 147false
- 3148 to 158false
- 4152 to 164true
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Answer : 4. "152 to 164"
Explanation :
Answer: D) 152 to 164 Explanation: A+7B=112 it is clear that A = 14, then it becomes A>=B, but A is smallest angle) givenso, range of A is 0.0001 to 13.9999 ( I am taking upto 4 decimal places)so, range of B becomes 14 to 16 ( after rounding off to 4 decimal places)so, range of C becomes 152 to 164 ( after rounding off to 4 decimal places)
Q: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is ? 1555 05b5cc6dae4d2b4197774e8a5
5b5cc6dae4d2b4197774e8a5- 145 kmphfalse
- 225 kmphfalse
- 330 kmphfalse
- 450 kmphtrue
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Answer : 4. "50 kmph"
Explanation :
Answer: D) 50 kmph Explanation: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) x (18/5)] km/hr = 45 km/hr. Let the speed of the train be 'S' km/hr. Then, relative speed = (S - 5) km/hr. S - 5 = 45 => S = 50 km/hr.
Q: An owner of a Dry fruits shop sold small packets of mixed nuts for Rs. 150 each and large packets for Rs. 250 each. One day he sold 5000 packets, for a total of Rs. 10.50 lakh. How many small packets were sold ? 1551 05b5cc6cfe4d2b4197774e308
5b5cc6cfe4d2b4197774e308- 12000true
- 23000false
- 32500false
- 43500false
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Answer : 1. "2000"
Explanation :
Answer: A) 2000 Explanation: Let 's' be the number of small packets and 'b' the number of large packets sold on that day. Therefore, s + b = 5000 ... eqn (1) Each small packet was sold for Rs.150.Therefore, 's' small packets would have fetched Rs.150s. Each large packets was sold for Rs.250.Therefore, 'b' large packets would have fetched Rs.250b. Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given) Or 150s + 250b = 10,50,000 ... eqn (2) Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3) Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000Or b = 3000 We know that s + b = 5000So, s = 5000 - b = 5000 - 3000 = 2000. 2000 small packets were sold.