Quantitative Aptitude Practice Question and Answer
8Q: Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ? 1506 05b5cc73de4d2b4197774f90c
5b5cc73de4d2b4197774f90c- 123false
- 224false
- 325false
- 426true
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Answer : 4. "26"
Explanation :
Answer: D) 26 Explanation: Let, Hema attempted 'k' sum correctly, then k x 3 -2 x(35-k) = 605k = 130k = 26 so 26 correct sums.
Q: If the price of a commodity is decreased by 20% and its consumption is increased by 10%, what will be the increase or decrease in the expenditure on the commodity? 1505 05b5cc6a2e4d2b4197774cb70
5b5cc6a2e4d2b4197774cb70- 1increase 12%false
- 2decrease 12%true
- 3increase 16%false
- 4decrease 16%false
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Answer : 2. "decrease 12%"
Explanation :
Answer: B) decrease 12% Explanation: Given the price of a commodity is decreased by p = 20% And its consumption is increased by q = 10% Now, required increase or decrease in the expenditure on the commodity can be p + q + pq/100 = -20 + 10 - 200/100 = -10 - 2 = -12%. Hence, decrease in the expenditure = 12%
Q: A train travels 325 km in 3.5 hours and 470 km in 4 hours. Find the average speed of train ? 1502 05b5cc764e4d2b4197774fd99
5b5cc764e4d2b4197774fd99- 1107 kmphfalse
- 2106 kmphtrue
- 372 kmphfalse
- 476 kmphfalse
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Answer : 2. "106 kmph"
Explanation :
Answer: B) 106 kmph Explanation: As we know that Speed = Distance / Timefor average speed = Total Distance / Total Time TakenThus, Total Distance = 325 + 470 = 795 kmThus, Total Speed = 7.5 hrsAverage Speed = 795/7.5 => 106 kmph.
Q: A sum of Rs. 8,000 is deposited for 3 years at 5% per annum compound interest (compounded annually). The difference of interest for 3 years and 2 years will be 1502 05b5cc695e4d2b4197774c4ec
5b5cc695e4d2b4197774c4ec- 1Rs. 387false
- 2Rs. 441true
- 3Rs. 469false
- 4Rs. 503false
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Answer : 2. "Rs. 441"
Explanation :
Answer: B) Rs. 441 Explanation: Given principal amount = Rs. 8000 Time = 3yrs Rate = 5% C.I for 3 yrs = 8000 x 105100 x 105100 x 105100 - 8000= Rs. 1261 Now, C.I for 2 yrs = 8000 x 105100 x 105100= Rs. 820 Hence, the required difference in C.I is 1261 - 820 = Rs. 441
Q: It was Tuesday on Jan 1, 2006. What was the day of the week Jan 1, 2010 ? 1502 05b5cc6d0e4d2b4197774e367
5b5cc6d0e4d2b4197774e367- 1Sundayfalse
- 2Fridaytrue
- 3Mondayfalse
- 4Tuesdayfalse
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Answer : 2. "Friday"
Explanation :
Answer: B) Friday Explanation: On 31st December, 2005 it was Monday. Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. On 31st December 2009, it was Thursday. Thus, on 1st Jan, 2010 it is Friday.
Q: Simple interest on a certain sum at 7% per annum for 4 years is Rs. 2415. What will be the compound interest on the same principal at 4% per annum in two years? 1501 05b5cc6a7e4d2b4197774ce22
5b5cc6a7e4d2b4197774ce22- 1Rs. 704true
- 2Rs. 854false
- 3Rs. 893false
- 4Rs. 914false
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Answer : 1. "Rs. 704"
Explanation :
Answer: A) Rs. 704 Explanation: We know that, S.I. = PTR100⇒ P = S.I x 100T x RAnd also,C.I = P1 + R100n- 1 From given data, P = Rs. 8625 Now, C.I = 86251+41002-1= 862526252-1= 8625676625-1= 8625 x 51625C.I = Rs. 703.80
Q: If K earns 12% less than L, then how much percent more does L earn than K ? 1499 05b5cc6c4e4d2b4197774dcb8
5b5cc6c4e4d2b4197774dcb8- 113.96%false
- 213.63%true
- 313.56%false
- 414.01%false
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Answer : 2. "13.63%"
Explanation :
Answer: B) 13.63% Explanation: Required % is given by => 12100-12x100 = 1200/88 = 13.636%
Q: Train K crosses a pole in 30 seconds and train L crosses the same pole in one minute and 20 seconds. The length of train K is three-fourths the length of train L. What is the ratio of the speed of train K to that of train L ? 1498 05b5cc6e0e4d2b4197774eb39
5b5cc6e0e4d2b4197774eb39- 11 : 3false
- 22 : 1true
- 33 : 1false
- 41 : 2false
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Answer : 2. "2 : 1"
Explanation :
Answer: B) 2 : 1 Explanation: Given that train K crosses a pole in 30 seconds and train L crosses the same pole in one minute and 15 seconds. Let the length of train K be Lk and that of train L be Ll given that Lk = 3/4 Ll As the train K and L crosses the pole in 30 seconds and 80 seconds respectively, => Speed of train K = sk = Lk/30 Speed of train L = sl = Ll/80 Lk = 3/4 Ll => sk = 3/4 Ll/(30) = Ll/40 Ratio of their speeds = sk : sl = Ll/40 : Ll/80 => 1/40 : 1/80 = 2 : 1