Quantitative Aptitude Practice Question and Answer
8Q: A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container ? 1821 05b5cc6c3e4d2b4197774dc86
5b5cc6c3e4d2b4197774dc86- 188.01 litfalse
- 287.48 littrue
- 387.51 litfalse
- 487.62 litfalse
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Answer : 2. "87.48 lit"
Explanation :
Answer: B) 87.48 lit Explanation: For these type of problems, Quantity of Diesel remained = q1-pqn Here p = 12 , q = 120 => 1201-121203 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.
Q: What will come in place of the question mark (?) in the following question ? 52.5% of 800 + 30.5% of 2800 = ? + 87.30 1820 05b5cc6c1e4d2b4197774db2d
5b5cc6c1e4d2b4197774db2d- 11096.30false
- 21226.70false
- 31124.20false
- 41186.70true
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Answer : 4. "1186.70"
Explanation :
Answer: D) 1186.70 Explanation: 52.5% of 800 + 30.5% of 2800 = ? + 87.30 420 + 854 - 87.30 = ? 1274 - 87.30 = ? ? = 1186.70
Q: An item is sold at a loss of 10%. Had it sold for Rs. 9 more, a profit of 25/2% would have gained. What is the cost price of the item? 1819 05b5cc688e4d2b4197774c2f0
5b5cc688e4d2b4197774c2f0- 1Rs. 90false
- 2Rs. 75false
- 3Rs. 55false
- 4Rs. 40true
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Answer : 4. "Rs. 40"
Explanation :
Answer: D) Rs. 40 Explanation: Let the cost price of the item = Rs. 50 Sold at 10% loss => for Rs. 50 loss S.P = Rs. 45 From the given data, 25/2 % gain if it is sold at Rs. 9 more 56.25 - 45 = 9 => 11.25 = 9 => 22.5 = 18 => 45 = 36 => 50 = ? => C.P = 50 x 3645 = 40 Hence, the Cost price of the item = Rs. 40.
Q: Navaneet has thrice the money Poonam has and Poonam has 25% more money than Hebah. If the average money of the three is Rs. 350, What is the amount that Navaneet has ? 1814 05b5cc6c4e4d2b4197774dceb
5b5cc6c4e4d2b4197774dceb- 1Rs. 175false
- 2Rs. 220.75false
- 3Rs. 218.55false
- 4Rs. 656.25true
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Answer : 4. "Rs. 656.25"
Explanation :
Answer: D) Rs. 656.25 Explanation: Assume Hebah has Rs. M Since 25% more money at Poonam => Money at Poonam = M + (25% of M) => Money at Poonam = M + 0.25M = Rs. 1.25M Money with Navaneet is thrice the money with Poonam, => Money at Navaneet = 3(1.25M) = Rs. 3.75M Now, sum of all Money = (M + 1.25M + 3.75M) = Rs. 6M But given the average of the money is Rs. 350 => 6M/3 = 350 => 2M = 350 => M = 350/2 = Rs. 175 => Amount of money Navaneet has = Rs. 3.75M = 3.75 x 175 = Rs. 656.25.
Q: A man sold two flats for Rs. 4.15 lakhs each. On one he gained 2% and on the other he lost 2%. What percent is the effect of the sale on the whole ? 1814 05b5cc6d3e4d2b4197774e4cd
5b5cc6d3e4d2b4197774e4cd- 10.25 %false
- 20.04 %true
- 30.5 %false
- 40 %false
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Answer : 2. "0.04 %"
Explanation :
Answer: B) 0.04 % Explanation: In this type cases we always have loss only. Loss% = Common Gain or Loss102= 2102= 1/25 = 0.04 %
Q: K men agree to donate a gift of Rs. L to trust. If three men drop out how much more will each have to contribute towards the purchase of the gift ? 1813 05b5cc74fe4d2b4197774fb44
5b5cc74fe4d2b4197774fb44- 1L / (k-3)false
- 2k / (L-3)false
- 32K / 3L-Kfalse
- 43L / K(K-3)true
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Answer : 4. "3L / K(K-3)"
Explanation :
Answer: D) 3L / K(K-3) Explanation: Intial contribution = L/KAfter 3 men drop, then contribution =L/K-3The amount more to pay in contribution = LK-3 - LK = 3LK(K-3)
Q: Ratio between heights of two cylinder in the ratio 3:5. Their volumes are in the ratio 27:80. Find ratio between their radius ? 1811 05b5cc6c5e4d2b4197774dde1
5b5cc6c5e4d2b4197774dde1- 11:3false
- 22:1false
- 33:4true
- 44:7false
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Answer : 3. "3:4"
Explanation :
Answer: C) 3:4 Explanation:
Q: On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is ? 1810 05b5cc6dfe4d2b4197774eac6
5b5cc6dfe4d2b4197774eac6- 1476190476false
- 248617false
- 347619true
- 44587962false
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Answer : 3. "47619"
Explanation :
Answer: C) 47619 Explanation: By hit and trail, we find that 47619 x 7 = 333333. 7) 333333 (47619 333333---------------- 0 And 476190476 x 7 = 3333333333 but smallest number is 47619.