Quantitative Aptitude Practice Question and Answer
8Q: The difference between the squares of two consecutive odd integers is always divisible by ? 1615 05b5cc77fe4d2b419777501b5
5b5cc77fe4d2b419777501b5- 18true
- 22false
- 36false
- 44false
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Answer : 1. "8"
Explanation :
Answer: A) 8 Explanation: Let the two consecutive odd integers be (2x + 1) and (2x + 3)Then, (2x + 3)2 - (2x + 1)2 = (2x + 3 + 2x + 1) (2x + 3 - 2x - 1) = (4x + 4)(2)= 8 (x + 1), which is always divisible by 8
Q: Simplify the following equation [K-L2-K+L2]4K = a/b 1615 05b5cc6d6e4d2b4197774e674
5b5cc6d6e4d2b4197774e674- 1K = b /afalse
- 2bL = -atrue
- 3KL = 1false
- 4aK = -bfalse
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Answer : 2. "bL = -a"
Explanation :
Answer: B) bL = -a Explanation: [(K-L)2-K+L2]4K = abK2+L2-2KL-K2+L2+2KL4K= ab => - 4KL/4K = a/b => L = - a/b => bL = -a
Q: Sreya bought a plot for Rs. 6,00,000, then sold half of the plot at 10 % profit and rest at 15% profit. What is the total profit % that Sreya gain? 1607 05b5cc6bfe4d2b4197774da65
5b5cc6bfe4d2b4197774da65- 113.8 %false
- 211.4 %false
- 312.5 %true
- 414.5 %false
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Answer : 3. "12.5 %"
Explanation :
Answer: C) 12.5 % Explanation: 10% profit at half plot = 600000/2 x 10/100 = Rs. 30,000 15% profit at remaining half plot = 600000/2 x 15/100 = Rs. 45,000 Now, total profit = 30000 + 45000 = 75000 Profit % = 75000/600000 x 100 = 12.5 %
Q: What will come in place of the question mark (?) in the following question ? 52.5% of 800 + 30.5% of 2800 = ? + 87.30 1607 05b5cc6c1e4d2b4197774db2d
5b5cc6c1e4d2b4197774db2d- 11096.30false
- 21226.70false
- 31124.20false
- 41186.70true
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Answer : 4. "1186.70"
Explanation :
Answer: D) 1186.70 Explanation: 52.5% of 800 + 30.5% of 2800 = ? + 87.30 420 + 854 - 87.30 = ? 1274 - 87.30 = ? ? = 1186.70
Q: A class consists of both boys and girls along with a teacher. After a class, the teacher drinks 9 litres of water, a boy drinks 7 litres of water and a girl drinks 4 litres of water. If after a class 42 litres of water was consumed, find the number of girls in the class ? 1606 05b5cc745e4d2b4197774fa2c
5b5cc745e4d2b4197774fa2c- 18false
- 26false
- 35false
- 43true
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Answer : 4. "3"
Explanation :
Answer: D) 3 Explanation: Given teacher drinks 9 ltrLet number of boys be 'A'.Let number of girls be 'B'.Boy drinks 7 ltr and girl drinks 4 ltrAfter class total water consumed = 42 ltrThen,9 + 7A + 4B = 42=> 7A + 4B = 33By trial and error method,The only integers which satisfy the equation is A = 3 and B = 3Therefore, number of girls in the class = 3.
Q: A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container ? 1602 05b5cc6c3e4d2b4197774dc86
5b5cc6c3e4d2b4197774dc86- 188.01 litfalse
- 287.48 littrue
- 387.51 litfalse
- 487.62 litfalse
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Answer : 2. "87.48 lit"
Explanation :
Answer: B) 87.48 lit Explanation: For these type of problems, Quantity of Diesel remained = q1-pqn Here p = 12 , q = 120 => 1201-121203 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.
Q: A sum of Rs. 8,000 is deposited for 3 years at 5% per annum compound interest (compounded annually). The difference of interest for 3 years and 2 years will be 1601 05b5cc695e4d2b4197774c4ec
5b5cc695e4d2b4197774c4ec- 1Rs. 387false
- 2Rs. 441true
- 3Rs. 469false
- 4Rs. 503false
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Answer : 2. "Rs. 441"
Explanation :
Answer: B) Rs. 441 Explanation: Given principal amount = Rs. 8000 Time = 3yrs Rate = 5% C.I for 3 yrs = 8000 x 105100 x 105100 x 105100 - 8000= Rs. 1261 Now, C.I for 2 yrs = 8000 x 105100 x 105100= Rs. 820 Hence, the required difference in C.I is 1261 - 820 = Rs. 441
Q: Find the principal if the interest compounded at the rate of 10% per annum for two years is Rs. 420 ? 1601 05b5cc701e4d2b4197774f17a
5b5cc701e4d2b4197774f17a- 1Rs. 2000true
- 2Rs. 2100false
- 3Rs. 1900false
- 4Rs. 2150false
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Answer : 1. "Rs. 2000"
Explanation :
Answer: A) Rs. 2000 Explanation: Given, Compound rate, R = 10% per annumTime = 2 yearsC.I = Rs. 420Let P be the required principal.A = (P+C.I)Amount, A = P1 + r100n (P+C.I) = P1 + 101002 (P+420) = P[11/10][11/10] P-1.21P = -420 0.21P = 420 Hence, P = 420/0.21 = Rs. 2000