Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Two trains of equal length are running on parallel lines in the same direction at 36 km/hr and 26 km/hr. The faster train passes the slower train in 36 sec. The length of each train is ? 1344 05b5cc6e0e4d2b4197774eb93
5b5cc6e0e4d2b4197774eb93- 128 mtsfalse
- 254 mtsfalse
- 324 mtsfalse
- 450 mtstrue
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उत्तर : 4. "50 mts"
व्याख्या :
Answer: D) 50 mts Explanation: Let the length of each train be x mts. Then, distance covered = 2x mts. Relative speed = 36 - 26 = 10 km/hr. = 10 x 5/18 = 25/9 m/sec. 2x/36 = 25/9 => x = 50 mts.
प्र: A man sold two flats for Rs. 4.15 lakhs each. On one he gained 2% and on the other he lost 2%. What percent is the effect of the sale on the whole ? 1343 05b5cc6d3e4d2b4197774e4cd
5b5cc6d3e4d2b4197774e4cd- 10.25 %false
- 20.04 %true
- 30.5 %false
- 40 %false
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उत्तर : 2. "0.04 %"
व्याख्या :
Answer: B) 0.04 % Explanation: In this type cases we always have loss only. Loss% = Common Gain or Loss102= 2102= 1/25 = 0.04 %
प्र: Area of a square and a rectangle are equal. If side of the square is 40 cm and length of the rectangle is 64 cm, what is the perimeter of the rectangle ? 1341 05b5cc6c2e4d2b4197774dbe1
5b5cc6c2e4d2b4197774dbe1- 1187 cmfalse
- 2178 cmtrue
- 3149 cmfalse
- 4194 cmfalse
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उत्तर : 2. "178 cm"
व्याख्या :
Answer: B) 178 cm Explanation: Area of square = 40 x 40 = 1600 sq.cm Given that the areas of Square and Rectangle are equal => Area of rectangle = 1600 Sq.cm We know that, Area of rectangle = L x B Given L = 64 cm Breadth of rectangle = 1600/64 = 25 cm Perimeter of the rectangle = 2(L + B) = 2(64+25) = 178 cm.
प्र: Simplify the following expression? 40% of (244 x ?) = 48 1340 05b5cc6aae4d2b4197774cf5b
5b5cc6aae4d2b4197774cf5b- 124false
- 222false
- 320true
- 418false
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उत्तर : 3. "20"
व्याख्या :
Answer: C) 20 Explanation: We know that 40% = 40100 = 25⇒25 x 244 x ? = 48? = 48 x 5 x 42 x 24 = 20
प्र: The ratio between the length and breadth of a rectangular field is 5 : 4 if the breadth is 20m less than the length, the perimeter of the field is : 1340 05b5cc70be4d2b4197774f2e6
5b5cc70be4d2b4197774f2e6- 1260mfalse
- 2280mfalse
- 3360mfalse
- 4none of thesefalse
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उत्तर :
व्याख्या :
Answer: Explanation:
प्र: The average of marks in 3 subjects is 224. The first subject marks is twice the second and the second subject marks is twice the third. Find the second subject marks ? 1337 05b5cc6cce4d2b4197774e17c
5b5cc6cce4d2b4197774e17c- 1384false
- 296false
- 3192true
- 4206false
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उत्तर : 3. "192"
व्याख्या :
Answer: C) 192 Explanation: Let the third subject marks be 'x'=> Second subject marks = 2x=> Third subject marks = 4xGiven avg = 224x + 2x + 4x = 224 x 3=> 7x = 224 x 3=> x = 96Hence, Second subject marks = 2x = 2 x 96 = 192.
प्र: What least number must be substracted from 627349 so that the remaining number is divisible by 15 ? 1337 05b5cc754e4d2b4197774fb9a
5b5cc754e4d2b4197774fb9a- 11false
- 22false
- 33false
- 44true
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उत्तर : 4. "4"
व्याख्या :
Answer: D) 4 Explanation: On dividing 627349 by 15, we get remainder = 4.Therefore, the obtained remainder is the least number to be subtracted from the given number so that the the mnumber is divisible by 15.Here 4 is the least number to be subtracted from 627349 so that it is divisible by 15.
प्र: What is 15 as a decimal? 1332 05b5cc6aae4d2b4197774cf8e
5b5cc6aae4d2b4197774cf8e- 10.333false
- 20.666false
- 30.200true
- 40.452false
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उत्तर : 3. "0.200"
व्याख्या :
Answer: C) 0.200 Explanation: Here I converted the original fraction to a fraction with the denominator being 10, because decimals can be written in the tenths place. Divide numerator and denominator with '2'15 x 22 = 210 = 0.2

