Quantitative Aptitude Practice Question and Answer
8Q: Find the sum to 200 terms of the series 2 + 5 + 7 + 6 + 12 + 7 + .... 1781 05b5cc754e4d2b4197774fb9f
5b5cc754e4d2b4197774fb9f- 130,400true
- 230,200false
- 334,600false
- 438,400false
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Answer : 1. "30,400"
Explanation :
Answer: A) 30,400 Explanation: we can treat every two consecutive terms as one.So, we will have a total of 100 terms of the nature:(2 + 5) + (7 + 6) + (12 + 7).... => 7, 13, 19,.... We know the sum of n terms nn+12 Now, a= 7, d=6 and n=100Hence the sum of the given series is S= 100/2 x[2 x 7 + 99 x 6]=> 50[608]=> 30,400.
Q: If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x+y is equal to ? 1774 05b5cc761e4d2b4197774fd62
5b5cc761e4d2b4197774fd62- 15false
- 24false
- 33false
- 42true
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Answer : 4. "2"
Explanation :
Answer: D) 2 Explanation: Since 653xy is divisible by 5 as well as 2, so y = 0.Now, 653x0 must be divisible by 8.So, 3x0 must be divisible by 8. This happens when x = 2x + y = (2 + 0) = 2.
Q: Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 m x 5 m when 10% of its volume is occupied by concrete ? 1772 05b5cc6eee4d2b4197774ef16
5b5cc6eee4d2b4197774ef16- 16000true
- 25400false
- 33800false
- 44700false
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Answer : 1. "6000"
Explanation :
Answer: A) 6000 Explanation: Let 'B' be the nuber of bricks. => 10 x 4/100 x 5 x 90/100 = 25/100 x 15/100 x 8/100 x B => 10 x 20 x 90 = 15 x 2 x B => B = 6000
Q: Rajeev's age is four more than the age of Shilpa. The age of Shilpa can be obtained by subtracting four times her age 4 years ago from the four times her age after 4 years. What was Rajeev's age before 4 years ? 1771 05b5cc6c7e4d2b4197774dea5
5b5cc6c7e4d2b4197774dea5- 136 yearsfalse
- 228 yearsfalse
- 332 yearstrue
- 440 yearsfalse
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Answer : 3. "32 years"
Explanation :
Answer: C) 32 years Explanation: Let Shilpa's present age is p years According to question, p = 4(x+4) – 4(x–4) p = 4x+16 – 4x+16 p = 32 Shilpa's present age = 32 years Rajeev is four years older than Shilpa => Shilpa's present age = Rajeev's age 4 years before. => Rajeev's age 4 years before = 32 years.
Q: A certain sum is invested at simple interest at 18% p.a. for two years instead of investing at 12% p.a. for the same time period. Therefore the interest received is more by Rs. 840. Find the sum ? 1770 05b5cc6e2e4d2b4197774ec39
5b5cc6e2e4d2b4197774ec39- 1Rs. 5858false
- 2Rs. 8800false
- 3Rs. 7000true
- 4Rs. 6350false
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Answer : 3. "Rs. 7000"
Explanation :
Answer: C) Rs. 7000 Explanation: Let the sum be Rs. S.(S x 18 x 2)/100 - (S x 12 x 2)/100 = 840 => 36S/100 - 24S/100 = 840 => 12S/100 = 840 => S = 7000.
Q: 36 identical books must be arranged in rows with the same number of books in each row. Each row must contain at least three books and there must be at least three rows. A row is parallel to the front of the room. How many different arrangements are possible ? 1769 05b5cc6cfe4d2b4197774e2f4
5b5cc6cfe4d2b4197774e2f4- 15true
- 26false
- 37false
- 48false
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Answer : 1. "5"
Explanation :
Answer: A) 5 Explanation: The following arrangements satisfy all 3 conditions. Arrangement 1: 3 books in a row; 12 rows. Arrangement 2: 4 books in a row; 9 rows.Arrangement 3: 6 books in a row; 6 rows.Arrangement 4: 9 books in a row; 4 rows.Arrangement 5: 12 books in a row; 3 rows. Therefore, the possible arrangements are 5.
Q: The difference between the squares of two consecutive odd integers is always divisible by ? 1765 05b5cc77fe4d2b419777501b5
5b5cc77fe4d2b419777501b5- 18true
- 22false
- 36false
- 44false
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Answer : 1. "8"
Explanation :
Answer: A) 8 Explanation: Let the two consecutive odd integers be (2x + 1) and (2x + 3)Then, (2x + 3)2 - (2x + 1)2 = (2x + 3 + 2x + 1) (2x + 3 - 2x - 1) = (4x + 4)(2)= 8 (x + 1), which is always divisible by 8
Q: There are 11 True or False questions. How many ways can these be answered ? 1763 05b5cc6d0e4d2b4197774e385
5b5cc6d0e4d2b4197774e385- 111!/2false
- 21024false
- 311!false
- 42048true
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Answer : 4. "2048"
Explanation :
Answer: D) 2048 Explanation: Given 11 questions of type True or False Then, Each of these questions can be answered in 2 ways (True or false) Therefore, no. of ways of answering 11 questions = 211 = 2048 ways.