Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: 10 boys can complete a work in 7 days and 10 girls take 14 days to complete the work. How many days will 5 boys and 10 girls take to complete the work ? 1624 0

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    13 days
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  • 2
    10 days
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  • 3
    7 days
    सही
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  • 4
    16 days
    सही
    गलत
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उत्तर : 3. "7 days"
व्याख्या :

Answer: C) 7 days Explanation: 1 boy's 1 day work = 1/70 1 girl's 1 day work = 1/140 (5 boys + 10 girls)'s 1 day work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7   5 boys and 10 girls will complete the work in 7 days.

प्र: A, B and C started a business where their initial capital was in the ratio of 2:3:4. At the end of 6 months, A invested an amount such that his total capital became equal to C's initial capital investment. If the annual profit of B is Rs. 3000 then what is the total profit  ? 1622 0

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    Rs. 8,640
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  • 2
    Rs. 9,850
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  • 3
    Rs. 10,000
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  • 4
    Rs. 11,220
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उत्तर : 3. "Rs. 10,000"
व्याख्या :

Answer: C) Rs. 10,000 Explanation: Ratio of investments of A, B & C = 2×6+4×6 : 3×12 : 4×12 = 36 : 36 : 48 = 6 : 6 : 8 But given that the annual profit of B is Rs. 3000 => 6 ratio = 3000 Then for the total annual profit of partners is 20 ratio = 3000 x 20/6 = 10,000.

प्र: In how many ways can the letters of the word 'LEADER' be arranged ? 1620 0

  • 1
    360
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  • 2
    420
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  • 3
    576
    सही
    गलत
  • 4
    220
    सही
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उत्तर : 1. "360"
व्याख्या :

Answer: A) 360 Explanation: No. of letters in the word = 6No. of 'E' repeated = 2Total No. of arrangement = 6!/2! = 360

प्र: Area of a square and a rectangle are equal. If side of the square is 40 cm and length of the rectangle is 64 cm, what is the perimeter of the rectangle ? 1618 0

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    187 cm
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  • 2
    178 cm
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  • 3
    149 cm
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  • 4
    194 cm
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उत्तर : 2. "178 cm"
व्याख्या :

Answer: B) 178 cm Explanation: Area of square = 40 x 40 = 1600 sq.cm Given that the areas of Square and Rectangle are equal => Area of rectangle = 1600 Sq.cm We know that, Area of rectangle = L x B Given L = 64 cm Breadth of rectangle = 1600/64 = 25 cm Perimeter of the rectangle = 2(L + B) = 2(64+25) = 178 cm.

प्र: Uma sold an article for 3400 and got a profit of 25%. If he had sold the article for Rs. 3265. How much profit% would Uma have got ? 1601 0

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    22%
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  • 2
    27%
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  • 3
    20%
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  • 4
    18%
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उत्तर : 3. "20%"
व्याख्या :

Answer: C) 20% Explanation: Given       125% ---- 3400 => 100% ---- ? => ? = 3400x100/125 = 2720 => Cost price of the article = Rs. 2720 Profit when article sold at Rs. 3265 = 3265 - 2720 = 545 Hence, Profit% = Gain x 100/cost price => P% = 545 x 100/2720 => P% = 20%

प्र: Value of vehicle at end of each year depreciates at the rate of 3/5th of value at the beginning. If Initial value is 10,000Rs then at the end of three years its value is ? 1601 0

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    Rs. 6000
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  • 2
    Rs. 3600
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  • 3
    Rs. 2160
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    गलत
  • 4
    Rs. 415
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उत्तर : 3. "Rs. 2160"
व्याख्या :

Answer: C) Rs. 2160 Explanation: End of first year     :  10000 x (3/5) = Rs. 6000End of second year :  6000 x (3/5) = Rs. 3600End of third year    :  3600 x (3/5) = Rs. 2160

प्र: Two parallel chords on the same side of the centre of a circle are 5 cm apart. If the chords are 20 and 28 cm long, what is the radius of the circle? 1601 0

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    14.69 cm
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  • 2
    15.69 cm
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  • 3
    18.65 cm
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  • 4
    16.42 cm
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उत्तर : 2. "15.69 cm"
व्याख्या :

Answer: B) 15.69 cm Explanation: Draw the two chords as shown in the figure. Let O be the center of the circle. Draw OC perpendicular to both chords. That divides the two chords in half.So CD = 10 and AB = 14. Draw radii OA and OD, both equal to radius r.We are given that BC = 5, the distance between the two chords. LetOB = x. We use the Pythagorean theorem on right triangle ABO AO² = AB² + OB² r² = 14² + x² We use the Pythagorean theorem on right triangle DCO DO² = CD² + OC² We see that OC = OB+BC = x+5, so r² = 10² + (x+5)² So we have a system of two equations: r² = 14² + x² r² = 10² + (x+5)² Since both left sides equal r², set the right sidesequal to each other. 14² + x² = 10² + (x+5)² 196 + x² = 100 + x² + 10x + 25 196 = 125 + 10x 71 = 10x 7.1 = x r² = 14² + x² r² = 196 + (7.1)² r² = 196 + 50.41 r² = 246.41 r = √246.41 r = 15.69745202 cm

प्र: In the following number series, one of the numbers is wrong. Find it out? 77, 79, 76, 81, 75, 85 1599 0

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    79
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  • 2
    81
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  • 3
    75
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  • 4
    85
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उत्तर : 3. "75"
व्याख्या :

Answer: C) 75 Explanation: Here in the given series, it follows a pattern that   77 + 2 = 79   79  - 3 = 76   76 + 5 = 81   81 -  7 = 74   74 + 11 = 85   Consecutive adding and subtracting of prime numbers.   So the wrong number in the given series is 75.

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