Answer: D) Rs. 40 Explanation: Let the cost price of the item = Rs. 50 Sold at 10% loss => for Rs. 50 loss  S.P = Rs. 45 From the  given data, 25/2 % gain if it is sold at Rs. 9 more 56.25 - 45 = 9 => 11.25 = 9 => 22.5 = 18 => 45 = 36 => 50 = ? => C.P = 50 x 3645 = 40   Hence, the Cost price of the item = Rs. 40.

Answer: B) 4 kmph Explanation: Let the distance in one direction = k kms Speed in still water = 4.5 kmph Speed of river = 1.5 Hence, speed in upstream = 4.5 - 1.5 = 3 kmph Speed in downstream = 4.5 + 1.5 = 6 kmph Time taken by Rajesh to row upwards = k/3 hrs Time taken by Rajesh to row downwards = k/6 hrs Now, required Average speed =Total distanceTotal speed = 2kk3 + k6 = 2k x 186k + 3k = 4 kmph    Therefore, the average speed of the whole journey = 4kmph.

Answer: D) 140 mts Explanation: Speeds of two trains = 30 kmph and 58 kmph => Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s Given a man takes time to cross length of faster train = 18 sec   Now, required Length of faster train = speed x time = 70/9  x  18 = 140 mts.

Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115  ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23   Hence, required number of gentlemen in the family = x = 23.

Answer: B) 105/103 Explanation: As given equal amounts of alloys are melted, let it be 1 kg. Required ratio of gold and silver = 513 + 58813 + 38 = 105103.   Hence, ratio of gold and silver in the resulting alloy = 105/103.

Answer: D) Rs. 3136 Explanation: Let total amount = Rs. P Total expenditure = (23 + 33 + 19 + 16)% of P = 91%ofP Remaining money = (100 - 91)% of P = 9% of P But given in the question that, 9% of P = 504 9p/100 = 504 => P = 50400/9 => P = Rs. 5600   Required money spent on Food & Insurance = 23 + 33 % = 56% of 5600 = 56 x 5600/100 = 56 x 56 = Rs. 3136

Answer: A) Rs. 1600 Explanation: Let the salaries of Maneela and Shanthi one year before be M1, S1 & now be M2, S2 respectively. Then, from the given data, M1/S1 = 3/4  .....(1) M1/M2 = 4/5 .....(2) S1/S2 = 2/3  .....(3) and M2 + S2 = 4160  .....(4)   Solving all these eqtns, we get M2 = Rs. 1600.

Answer: A) 277 Explanation: The given number series is    71      88       113       150       203          277    +17    +25       +37      +53        +74         +8      +12        +16       +21             +4          +4         +5   The series should be  71  88  112   150    203   276 i.e, the differences of the difference should be +4.   Hence, the odd man in the given series is 277.