Answer: A) 1:7 Explanation: Let the speed of the trains be x and y respectively length of train1 = 47xlength of train2 = 31yRelative speed= x + yTime taken to cross each other = 33 s=> 47x+31yx+y= 33=> (47x + 31 y) = 33(x + y)=> 14x = 2y=> x/y = 2/14 = 1/7  = 1:7

Answer: B) 24 Explanation: Sum of Interior angle is 180 .and it is given that interior angle is 150 more than exterior,so let exterior angle is x then interior will be x+150 now , interior + exterior =180x+150+x=180x=15 now , number of sides of polygon = 360 / exterior anglen = 360 / 15n = 24

Answer: B) 44 Explanation:   4             3             4             7               15        ? ×1-1      ×1+1       ×2-1       ×2+1           ×3-1   15x3 - 1 = 45 - 1 = 44

Answer: D) 7.5 hrs Explanation: Ratio of times taken by A and B = 160 : 100A can do the work in 12 daysLet B can do the work in "D" days=> 160:100 = 12 : D=> D = 12 x 100/160 = 7.5 hrs

Answer: B) 45 Explanation: Let number of 20 ps coins = x and number of 25 ps coins = y Given total coins in the bag = 50 x + y = 50.......(1) But the total money in the bag = Rs. 10.25 0.20x + 0.25y = 10.25 20x + 25y = 1025.........(2) Now multiplying (1) by 25 we get 25x+25y=1250.............(3) By solving (2) and (3) 20x + 25y = 1025; => x = 45; Then, the no. of 20 ps coins are 45.

Answer: B) 3/10 Explanation: Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20Let E = event of getting a multiple of 4 or 15 =multiples od 4 are {4, 8, 12, 16, 20}And multiples of 15 means multiples of 3 and 5= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.= the common multiple is only (15).=> E = n(E)= 6Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.

Answer: D) 1022 Explanation: Lowest 4-digit number is 1000.LCM of 3, 4 and 5 is 60.Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.Now, add the remainder 2 that's required. Thus, the answer is 1022.

Answer: C) 462 Explanation: Assume that the number is taken as XYZ.Condition 1 => Z = sq.root(x) => Possible digits of X is 1,4,9Condition 2 => Y = X + ZX Y Z1 2 14 6 29 12 3 => (wrong because it is 4 digit.) and 121 is not divisible by 2 The answer is 462.