Quantitative Aptitude Practice Question and Answer
8Q: 19 friends went to a restaurant for a combined weekend dinner party. 13 of them spent Rs. 79 each on their dinner and the rest spent Rs. 4 more than the average expenditure of all the 19. What was the total money spent by them? 1225 05b5cc6bae4d2b4197774d7a3
5b5cc6bae4d2b4197774d7a3- 1Rs. 1398.96false
- 2Rs. 1457.09false
- 3Rs. 1662.35false
- 4Rs. 1536.07true
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Answer : 4. "Rs. 1536.07"
Explanation :
Answer: D) Rs. 1536.07 Explanation: Let average expenditure was Rs. R 13 x 79 + 6x(R + 4) = 19R => R = Rs. 80.84 Total money = 19 x 80.84 = Rs. 1536.07.
Q: A town having teenagers(boys & girls) of 5000 requires 150 litre of water per head. It has a tank measuring 20 m × 15 m × 5 m. The water of this tank will sufficient for ____ days. 1223 05b5cc6c5e4d2b4197774dd82
5b5cc6c5e4d2b4197774dd82- 18false
- 26false
- 34false
- 42true
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Answer : 4. "2"
Explanation :
Answer: D) 2 Explanation: Total Water reqduired = 5000 × 150 lit = 750,000 litres = 750 cu.m. Volume of tank = 20 × 15 × 5 = 1500 Cu.m. Number of days required =1500/750 = 2 days.
Q: How many minutes does a watch lose per day, if its hands coincide every 64 minutes ? 1223 05b5cc6d7e4d2b4197774e714
5b5cc6d7e4d2b4197774e714- 136 7/9 minfalse
- 232 8/11 mintrue
- 334 3/11 minfalse
- 465 5/11 minfalse
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Answer : 2. "32 8/11 min"
Explanation :
Answer: B) 32 8/11 min Explanation: 55 min. spaces are covered in 60 min. 60 min. spaces are covered in min. = min. Loss in 64 min. = min. Loss in 24 hrs = min. = min.
Q: A man can row 8 kmh in still water. If the river is running at 2 kmh, it takes 4 hrs more upstream than to go downstream for the same distance. Then the distance is given by 1218 05b5cc6c8e4d2b4197774df00
5b5cc6c8e4d2b4197774df00- 154 kmsfalse
- 232 kmsfalse
- 345 kmsfalse
- 460 kmstrue
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Answer : 4. "60 kms"
Explanation :
Answer: D) 60 kms Explanation: Let the distance be d. d8-2-d8+2 = 4 => 2d = 120 => d = 60 kms.
Q: To fill 8 vacancies there are 15 candidates of which 5 are from ST. If 3 of the vacancies are reserved for ST candidates while the rest are open to all, Find the number of ways in which the selection can be done ? 1215 05b5cc6c4e4d2b4197774dcb3
5b5cc6c4e4d2b4197774dcb3- 17920true
- 274841false
- 314874false
- 410213false
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Answer : 1. "7920"
Explanation :
Answer: A) 7920 Explanation: ST candidates vacancies can be filled by C35 ways = 10 Remaining vacancies are 5 that are to be filled by 12 => C512= (12x11x10x9x8)/(5x4x3x2x1) = 792 Total number of filling the vacancies = 10 x 792 = 7920
Q: Find the area of the square whose side is equal to the diagonal of a rectangle of length 3 cm and breadth 4 cm. 1202 05b5cc698e4d2b4197774c66b
5b5cc698e4d2b4197774c66b- 125 sq.cmtrue
- 216 sq.cmfalse
- 39 sq.cmfalse
- 44 sq.cmfalse
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Answer : 1. "25 sq.cm"
Explanation :
Answer: A) 25 sq.cm Explanation: Given length of the rectangle = 3 cm Breadth of the rectangle = 4 cm Then, the diagonal of the rectangle D = 32 + 42 = 25 = 5 Then, it implies side of square = 5 cm We know that Area of square = S x S = 5 x 5 = 25 sq.cm.
Q: A man has only 20-paise and 25-paise coins in a bag. If he has 50 coins in all totaling to Rs.10.25, then the number of 20-paise coins is 1202 05b5cc73ae4d2b4197774f8c4
5b5cc73ae4d2b4197774f8c4- 142false
- 245true
- 338false
- 436false
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Answer : 2. "45"
Explanation :
Answer: B) 45 Explanation: Let number of 20 ps coins = x and number of 25 ps coins = y Given total coins in the bag = 50 x + y = 50.......(1) But the total money in the bag = Rs. 10.25 0.20x + 0.25y = 10.25 20x + 25y = 1025.........(2) Now multiplying (1) by 25 we get 25x+25y=1250.............(3) By solving (2) and (3) 20x + 25y = 1025; => x = 45; Then, the no. of 20 ps coins are 45.
Q: 40% of 80? 1100 05b5cc6ade4d2b4197774d11f
5b5cc6ade4d2b4197774d11f- 136false
- 232true
- 342false
- 444false
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Answer : 2. "32"
Explanation :
Answer: B) 32 Explanation: Here 40% of 80 is given as 40100 x 80 = 8 x 4 = 32