Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ? 1436 05b5cc741e4d2b4197774f9d6
5b5cc741e4d2b4197774f9d6- 16/19false
- 23/10true
- 37/10false
- 46/17false
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उत्तर : 2. "3/10"
व्याख्या :
Answer: B) 3/10 Explanation: Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20Let E = event of getting a multiple of 4 or 15 =multiples od 4 are {4, 8, 12, 16, 20}And multiples of 15 means multiples of 3 and 5= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.= the common multiple is only (15).=> E = n(E)= 6Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.
प्र: A can complete a piece of work in 12 days and B is 60% more efficient than A. In how many days B will complete the same work ? 1433 05b5cc6dde4d2b4197774ea05
5b5cc6dde4d2b4197774ea05- 18.7 hrsfalse
- 25.2 hrsfalse
- 35 hrsfalse
- 47.5 hrstrue
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उत्तर : 4. "7.5 hrs"
व्याख्या :
Answer: D) 7.5 hrs Explanation: Ratio of times taken by A and B = 160 : 100A can do the work in 12 daysLet B can do the work in "D" days=> 160:100 = 12 : D=> D = 12 x 100/160 = 7.5 hrs
प्र: A lady took loan from a bank at the rate of 12% p.a. simple interest. After 3 years she had to pay Rs. 5400 interest only for the period. The principal amount borrowed by her was : 1418 05b5cc6dbe4d2b4197774e904
5b5cc6dbe4d2b4197774e904- 1Rs. 15,000true
- 2Rs. 1,50,000false
- 3Rs. 1500false
- 4Rs. 1,62,000false
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उत्तर : 1. "Rs. 15,000"
व्याख्या :
Answer: A) Rs. 15,000 Explanation: Principal = Rs.(100 x 5400)/(12 x 3)= Rs. 15000.
प्र: How many minutes does a watch lose per day, if its hands coincide every 64 minutes ? 1410 05b5cc6d7e4d2b4197774e714
5b5cc6d7e4d2b4197774e714- 136 7/9 minfalse
- 232 8/11 mintrue
- 334 3/11 minfalse
- 465 5/11 minfalse
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उत्तर : 2. "32 8/11 min"
व्याख्या :
Answer: B) 32 8/11 min Explanation: 55 min. spaces are covered in 60 min. 60 min. spaces are covered in min. = min. Loss in 64 min. = min. Loss in 24 hrs = min. = min.
प्र: 19 friends went to a restaurant for a combined weekend dinner party. 13 of them spent Rs. 79 each on their dinner and the rest spent Rs. 4 more than the average expenditure of all the 19. What was the total money spent by them? 1409 05b5cc6bae4d2b4197774d7a3
5b5cc6bae4d2b4197774d7a3- 1Rs. 1398.96false
- 2Rs. 1457.09false
- 3Rs. 1662.35false
- 4Rs. 1536.07true
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उत्तर : 4. "Rs. 1536.07"
व्याख्या :
Answer: D) Rs. 1536.07 Explanation: Let average expenditure was Rs. R 13 x 79 + 6x(R + 4) = 19R => R = Rs. 80.84 Total money = 19 x 80.84 = Rs. 1536.07.
प्र: Find the area of the square whose side is equal to the diagonal of a rectangle of length 3 cm and breadth 4 cm. 1365 05b5cc698e4d2b4197774c66b
5b5cc698e4d2b4197774c66b- 125 sq.cmtrue
- 216 sq.cmfalse
- 39 sq.cmfalse
- 44 sq.cmfalse
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उत्तर : 1. "25 sq.cm"
व्याख्या :
Answer: A) 25 sq.cm Explanation: Given length of the rectangle = 3 cm Breadth of the rectangle = 4 cm Then, the diagonal of the rectangle D = 32 + 42 = 25 = 5 Then, it implies side of square = 5 cm We know that Area of square = S x S = 5 x 5 = 25 sq.cm.
प्र: A man has only 20-paise and 25-paise coins in a bag. If he has 50 coins in all totaling to Rs.10.25, then the number of 20-paise coins is 1354 05b5cc73ae4d2b4197774f8c4
5b5cc73ae4d2b4197774f8c4- 142false
- 245true
- 338false
- 436false
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उत्तर : 2. "45"
व्याख्या :
Answer: B) 45 Explanation: Let number of 20 ps coins = x and number of 25 ps coins = y Given total coins in the bag = 50 x + y = 50.......(1) But the total money in the bag = Rs. 10.25 0.20x + 0.25y = 10.25 20x + 25y = 1025.........(2) Now multiplying (1) by 25 we get 25x+25y=1250.............(3) By solving (2) and (3) 20x + 25y = 1025; => x = 45; Then, the no. of 20 ps coins are 45.
प्र: 40% of 80? 1241 05b5cc6ade4d2b4197774d11f
5b5cc6ade4d2b4197774d11f- 136false
- 232true
- 342false
- 444false
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उत्तर : 2. "32"
व्याख्या :
Answer: B) 32 Explanation: Here 40% of 80 is given as 40100 x 80 = 8 x 4 = 32

