Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Find the odd one out ? Hawk , Parrot , Owl , Eagle 5155 05b5cc76ae4d2b4197774fe9d
5b5cc76ae4d2b4197774fe9d- 1Eaglefalse
- 2Owlfalse
- 3Parrottrue
- 4Hawkfalse
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उत्तर : 3. "Parrot"
व्याख्या :
Answer: C) Parrot Explanation: All except Parrot are birds of prey.
प्र: Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is ? 5148 05b5cc6ebe4d2b4197774eea0
5b5cc6ebe4d2b4197774eea0- 1387 kmsfalse
- 2242 kmsfalse
- 3145 kmsfalse
- 4444 kmstrue
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उत्तर : 4. "444 kms"
व्याख्या :
Answer: D) 444 kms Explanation: 1h ----- 5 kms? ------ 60 kms Time = 12 hrs Relative Speed = 16 + 21 = 37 kmph T = 12 hrs D = S x T = 37 x 12 = 444 kms.
प्र: Rajeev start a business with Rs. 10000, Deepu joins him after 2 month with 20% more investment than Rajeev, after 2 month Shakti joins him with 40% less than Deepu. If the profit earned by them at the end of the year is equal to the twice of the difference between investment of Rajeev and ten times the investment of Shakti. Find the profit of Rajeev ? 5139 05b5cc6c6e4d2b4197774de2c
5b5cc6c6e4d2b4197774de2c- 150000false
- 248000false
- 338000true
- 440000false
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उत्तर : 3. "38000"
व्याख्या :
Answer: C) 38000 Explanation: Here from the given information, The ratio of investments of Rajeev, Deepu & Shakti is R : D : S = (10000 × 12) : (12000 × 10) : (7200 × 8) = 25 : 25 : 12 Now the Profit = 2 × (72000-10000) = 124000 Share of Rajeev = 124000 x 25/62 = 48000 Profit of Rajeev = 48000 - 10000 = 38000
प्र: Find the Odd One Out of the following Number Series? 3, 14, 36, 67, 113, 168 5117 05b5cc6b1e4d2b4197774d34b
5b5cc6b1e4d2b4197774d34b- 114false
- 236false
- 367true
- 4113false
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उत्तर : 3. "67"
व्याख्या :
Answer: C) 67 Explanation: Here the given number series is 3, 14, 36, 67, 113, 168 It follows a pattern that 3 3 + 1 x 11 = 3 + 11 = 14 14 + 2 x 11 = 14 + 22 = 36 36 + 3 x 11 = 36 + 33 = 69 69 + 4 x 11 = 69 + 44 = 113 113 + 5 x 11 = 113 + 55 = 168 Hence, the wrong number is 67.
प्र: Find out the wrong number in the following series: 5, 15, 30, 80, 180, 540, 1080 5115 05b5cc70ee4d2b4197774f376
5b5cc70ee4d2b4197774f376- 1540false
- 2180false
- 330false
- 480true
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उत्तर : 4. "80"
व्याख्या :
Answer: D) 80 Explanation: There should be 90 instead of 80so we can have a series5, 5x3, 15x2, 30x3, 90x2, 180x3, 540x2 and 1080x3 and so on...
प्र: Find the next number in the series 141,137,146,130,155,119,... 5099 05b5cc771e4d2b4197774ffc1
5b5cc771e4d2b4197774ffc1- 1147false
- 2168true
- 3162false
- 4182false
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उत्तर : 2. "168"
व्याख्या :
Answer: B) 168 Explanation: The pattern is -4, +9,-16, +25, -36 The next number=119+49=168
प्र: 30 आदमी किसी काम को 25 दिन में कर सकते हैं तो उसी काम को 75 आदमी कितने दिन में कर पायेंगे? 5096 25d1498d097a68b089a7aa7a0
5d1498d097a68b089a7aa7a0- 115false
- 212false
- 316false
- 410true
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उत्तर : 4. "10"
प्र: When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died ? 4979 05b5cc745e4d2b4197774fa18
5b5cc745e4d2b4197774fa18- 150 yrsfalse
- 260 yrstrue
- 370 yrsfalse
- 465 yrsfalse
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उत्तर : 2. "60 yrs"
व्याख्या :
Answer: B) 60 yrs Explanation: Let the Father be x years when he died Average Age 10 years ago be A Total Age 10 years ago = 6*A Total Age after 10 years(Just before father's Death) = 6A + 6*10 = 6A + 60 Father Died and Baby was born => the Total number of people in the family is Same (6) Baby born today so age of baby = 0 (6A +60 - x)/6 = 6A/6 => A + 10 -(x/6) = A => x/6 = 10 => x = 60 Therefore we can conclude that the father was 60 years old when he died.