Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: What was the day on 2nd Jan 1901 ? 4247 05b5cc709e4d2b4197774f28f
5b5cc709e4d2b4197774f28f- 1Tuesdayfalse
- 2Wednesdaytrue
- 3Mondayfalse
- 4Thursdayfalse
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उत्तर : 2. "Wednesday"
व्याख्या :
Answer: B) Wednesday Explanation: 2nd Jan 1901 means(1900 years and 2 day)Now, 1600 years have 0 odd day300 years have 1 odd day2 days has 2 odd dayTotal no. of odd days = 0 + 1 + 2 = 3 daysHence, the day on 2nd Jan 1901 was Wednesday.
प्र: Two trains of equal length, running with the speeds of 60 and 40 kmph, take 50 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions ? 4230 05b5cc6e5e4d2b4197774ed06
5b5cc6e5e4d2b4197774ed06- 110 sectrue
- 211 secfalse
- 312 secfalse
- 48 secfalse
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उत्तर : 1. "10 sec"
व्याख्या :
Answer: A) 10 sec Explanation: Relative Speed = 60 -40 = 20 x 5/18 = 100/18 Time = 50 Distance = 50 x 100/18 = 2500/9 Relative Speed = 60 + 40 = 100 x 5/18 Time = 2500/9 x 18/500 = 10 sec.
प्र: A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ? 4215 05b5cc741e4d2b4197774f99f
5b5cc741e4d2b4197774f99f- 1400false
- 2600false
- 3900true
- 4700false
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उत्तर : 3. "900"
व्याख्या :
Answer: C) 900 Explanation: 6,400 gents, 2400 ladies in that company.So total 8,800employees.for 8,800 employees, we want 2400 ladies.for 12,100employees we want how many ladies ?=> (12,100/8,800) x 2400 = 3300.So we want 3300 - 2400 = 900 more ladies.
प्र: Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage Raju's sister was 10years younger to him at the time of his marriage. The present age of Raju's sister is ? 4203 05b5cc6e2e4d2b4197774ec61
5b5cc6e2e4d2b4197774ec61- 130false
- 232false
- 338true
- 4Nonefalse
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उत्तर : 3. "38"
व्याख्या :
Answer: C) 38 Explanation: Let Raju's age at the time of his marriage = X years Then from given data => X + 8 = 6/5 X X = 40. Since got married 8 years ago, his present age = 48 His sister is 10 years younger => 48 - 10 = 38 years.
प्र: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 4197 05b5cc6bde4d2b4197774d8de
5b5cc6bde4d2b4197774d8de- 1A gain of Rs. 27false
- 2A loss of Rs. 37true
- 3A loss of Rs. 27false
- 4A gain of Rs. 37false
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उत्तर : 2. "A loss of Rs. 37"
व्याख्या :
Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is: 64 − 27 = 37 A loss of Rs.37
प्र: P is faster than Q. P and Q each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, P's speed is equal to ? 4195 05b5cc6dfe4d2b4197774eab7
5b5cc6dfe4d2b4197774eab7- 13 km/hrfalse
- 24 km/hrtrue
- 35 km/hrfalse
- 46 km/hrfalse
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उत्तर : 2. "4 km/hr"
व्याख्या :
Answer: B) 4 km/hr Explanation: Let P's speed = x km/hr. Then, Q's speed = (7 - x) km/ hr. So, 24/x + 24/(7 - x) = 14 x2 - 98x + 168 = 0 (x - 3)(x - 4) = 0 => x = 3 or 4. Since, P is faster than Q, so P's speed = 4 km/hr and Q's speed = 3 km/hr.
प्र: There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ? 4186 05b5cc754e4d2b4197774fbaf
5b5cc754e4d2b4197774fbaf- 1105true
- 27! x 6!false
- 37!/5!false
- 4420false
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उत्तर : 1. "105"
व्याख्या :
Answer: A) 105 Explanation: Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room, Then, 7C1 x 6C2 x 4C4 = 7 x 15 x 1 = 105
प्र: Deepa started a business in 2009 by investing Rs.50,000. She invested Rs. 20,000 as additional amount in 2010 and her friend Sushma joined her with an amount of Rs.70,000. Deepa invested another Rs. 20,000 in 2011 and Avanthi joined them with Rs. 70,000. At the end of these 3 years, they earned a profit of Rs. 3,00,000. Find Sushma's share ? 4156 05b5cc72ce4d2b4197774f750
5b5cc72ce4d2b4197774f750- 1Rs. 75,000false
- 2Rs. 85,000false
- 3Rs. 98,000false
- 4Rs. 1,00,000true
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उत्तर : 4. "Rs. 1,00,000"
व्याख्या :
Answer: D) Rs. 1,00,000 Explanation: Deepa invested Rs.50,000 for 12 months, Rs.(50000 + 20000) for 12 months and Rs.(50000 + 20000 + 20000) for 12 months.i.e, she invested Rs.50,000 for 12 months, Rs.70000 for 12 months and Rs.90000 for 12 months.Sushma invested Rs. 70000 for 2 years; i.e, Rs.70000 for 24 monthsAnd, Avanthi invested Rs.70000 for 1 year; i.e, Rs. 70000 for 12 months. Their investing ratio:Deepa : Sushma : Avanthi = (50,000 x 12 + 70000 x 12 + 90000 x 12):(70000 x 24):(70000 x 12)= (25,20,000):(16,80,000):(8,40,000) = 252:168:84 = 3:2:1 Total profit for 3 years = Rs.3,00,000Therefore, Sushma's share = Rs.(3,00,000 x 2 /(3+2+1)) = Rs.(3,00,000 x 2/6) = Rs.1,00,000.

