Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 4146 05b5cc6dee4d2b4197774ea65
5b5cc6dee4d2b4197774ea65- 120true
- 235false
- 354false
- 440false
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उत्तर : 1. "20"
व्याख्या :
Answer: A) 20 Explanation: Numbers of students in section A = x ∴ Numbers of students in section B and C = (100 – x) ∴ x 70 + (100 – x) 87.5 = 84 100 => 70x + 87.5 100 – 87.5x = 8400 => 8750 – 17.5x = 8400 => 17.5x = 8750 – 8400 => x = 20.
प्र: Find the missing number in the given number series? 2676, 445, ?, 21,6, 2, 1 4137 05b5cc69de4d2b4197774c8b2
5b5cc69de4d2b4197774c8b2- 188true
- 292false
- 396false
- 4102false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 1. "88"
व्याख्या :
Answer: A) 88 Explanation: The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that, From right side, 1 1 x 1 + 1 = 2 2 x 2 + 2 = 6 6 x 3 + 3 = 21 21 x 4 + 4 = 88 88 x 5 + 5 = 445 445 x 6 + 6 = 2676 Hence the missing number in the given number series is 88.
प्र: Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ? 4134 05b5cc73de4d2b4197774f91b
5b5cc73de4d2b4197774f91b- 110true
- 218false
- 312false
- 415false
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उत्तर : 1. "10"
व्याख्या :
Answer: A) 10 Explanation: Given total rupees = 20 RsNo. of one rupee stamps = 3Now, remaining money = Rs. 17With that he buys only 2 and 5 rupee stampsLet number of Rs. 5 stamps = KLet number of Rs. 2 stamps = L5K + 2L = 17K = 3, L = 1 (possible)L = 6, K = 1 (possible)=> But given that they are different in number so, K is not equal to 3one rupee stamps = 32 two stamps = 65 rupee stamps = 1Total number of stamps = 10.
प्र: If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price. 4131 05b5cc75ee4d2b4197774fcb1
5b5cc75ee4d2b4197774fcb1- 16:31false
- 211:30false
- 37:30true
- 431:6false
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उत्तर : 3. "7:30"
व्याख्या :
Answer: C) 7:30 Explanation: Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.M.P. = (6/5) S.P.Since the percentage discount = Percentage profit,65S.P - S.P65S.P×100 = S.P -C.PC.P×100Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.PM.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.PTherefore, Ratio of discount to C.P= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]= 7/30 Therefore, the ratio is 7 : 30
प्र: 96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part ? 4110 05b5cc6e2e4d2b4197774ec5c
5b5cc6e2e4d2b4197774ec5c- 142true
- 254false
- 346false
- 458false
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उत्तर : 1. "42"
व्याख्या :
Answer: A) 42 Explanation: Let x and y be the two parts of 96. x/7 = y/9 => x:y = 7:9 => The smallest part is = 7/16 x 96 = 42.
प्र: The number of ways in which 8 distinct toys can be distributed among 5 children? 4106 05b5cc699e4d2b4197774c700
5b5cc699e4d2b4197774c700- 15P8false
- 25^8true
- 38P5false
- 48^5false
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उत्तर : 2. "5^8"
व्याख्या :
Answer: B) 5^8 Explanation: As the toys are distinct and not identical, For each of the 8 toys, we have three choices as to which child will receive the toy. Therefore, there are 58 ways to distribute the toys. Hence, it is 58 and not 85.
प्र: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4105 05b5cc74fe4d2b4197774faea
5b5cc74fe4d2b4197774faea- 11124false
- 21420false
- 31345false
- 41250true
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उत्तर : 4. "1250"
व्याख्या :
Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.
प्र: Find the remainder when 1234 x 1235 x 1237 is divided by 8. 4095 05b5cc77ae4d2b41977750142
5b5cc77ae4d2b41977750142- 14false
- 22false
- 30false
- 46true
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उत्तर : 4. "6"
व्याख्या :
Answer: D) 6 Explanation: When we divide 1234 by 8, remainder is 2 When we divide 1235 by 8, remainder is 3 When we divide 1237 by 8, remainder is 5 ---> 2 x 3 x 5 = 30 As 30 will not be the remainder because it is greater than 8, when 30 divided by 8, remainder = 6.

