Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

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उत्तर : 2. "Rs 475"

प्र: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 4321 0

  • 1
    A gain of Rs. 27
    सही
    गलत
  • 2
    A loss of Rs. 37
    सही
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  • 3
    A loss of Rs. 27
    सही
    गलत
  • 4
    A gain of Rs. 37
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उत्तर : 2. "A loss of Rs. 37"
व्याख्या :

Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is:  64 − 27 = 37 A loss of Rs.37

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उत्तर : 4. "E = 4 & Y = 2"
व्याख्या :

Answer: D) E = 4 & Y = 2 Explanation: Let the the age of the elder boy = E   Let the the age of the younger boy = Y   Given that Y = cube root of EY   => Y3 = EY => E = Y2 .....(1)By the condition of number replacement the age of the father is YE   The Mother's age = EY/2   But she is 3 years less than father => EY/2 + 3 = YE2YE = EY + 6 ......(2)   Then now from the given options we can identify which satisfies the all the conditions.   Here Y =2 and E = 4 satisfies all the conditions.

प्र: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4262 0

  • 1
    1124
    सही
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  • 2
    1420
    सही
    गलत
  • 3
    1345
    सही
    गलत
  • 4
    1250
    सही
    गलत
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उत्तर : 4. "1250"
व्याख्या :

Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

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उत्तर : 4. "320रूपये"

प्र: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 4238 0

  • 1
    7 hrs
    सही
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  • 2
    7.5 hrs
    सही
    गलत
  • 3
    8 hrs
    सही
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  • 4
    8.25 hrs
    सही
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उत्तर : 2. "7.5 hrs"
व्याख्या :

Answer: B) 7.5 hrs Explanation: Let there are L men job requires LK man hours.   job completed in first 4 hrs = L x 4 = 4L job completed in next 4 hrs = 4 x L/2 = 2L job completed in next 4 hrs = 4 x L/4 = L job completed in last 4 hrs = 4 x L/8 = L/2 4L + 2L + L + L/2 = KL K = 7+1/2 = 7.5 hours.

प्र: In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes  ? 4238 0

  • 1
    446
    सही
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  • 2
    415
    सही
    गलत
  • 3
    404
    सही
    गलत
  • 4
    430
    सही
    गलत
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उत्तर : 4. "430"
व्याख्या :

Answer: D) 430 Explanation: Let the total number of valid votes be 'V'. 70% of V = 70/100 x V = 7V/10 Number of votes secured by the other candidate = V - 7V/100 = 3V/10 Given, 7V/10 - 3V/10 = 172 => 4V/10 = 172 => 4V = 1720 => V = 430.

प्र: If a soldier fires 7 shots from a gun in 12 minutes then find the total number of shots fired by the man in 3/2 hrs. 4236 0

  • 1
    45
    सही
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  • 2
    44
    सही
    गलत
  • 3
    46
    सही
    गलत
  • 4
    47
    सही
    गलत
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उत्तर : 3. "46"
व्याख्या :

Answer: C) 46 Explanation: Here given soldier shots 7 shots in 12 min => 1 shot doen't take any time in 12 min  => Only 6 shots take 12 min  12 min ------ 6 shots  90 min ------ ? shots  => 90 x (6/12) = 45  Therefore, total shots fired in 90 minutes = 45 + 1 = 46 shots.

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