Quantitative Aptitude Practice Question and Answer
8Q: The number of ways in which 8 distinct toys can be distributed among 5 children? 4409 05b5cc699e4d2b4197774c700
5b5cc699e4d2b4197774c700- 15P8false
- 25^8true
- 38P5false
- 48^5false
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Answer : 2. "5^8"
Explanation :
Answer: B) 5^8 Explanation: As the toys are distinct and not identical, For each of the 8 toys, we have three choices as to which child will receive the toy. Therefore, there are 58 ways to distribute the toys. Hence, it is 58 and not 85.
Q: Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ? 4392 05b5cc73ae4d2b4197774f8ce
5b5cc73ae4d2b4197774f8ce- 1E = 15 & Y = 3false
- 2E = 14 & Y = 12false
- 3E = 40 & Y = 22false
- 4E = 4 & Y = 2true
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Answer : 4. "E = 4 & Y = 2"
Explanation :
Answer: D) E = 4 & Y = 2 Explanation: Let the the age of the elder boy = E Let the the age of the younger boy = Y Given that Y = cube root of EY => Y3 = EY => E = Y2 .....(1)By the condition of number replacement the age of the father is YE The Mother's age = EY/2 But she is 3 years less than father => EY/2 + 3 = YE2YE = EY + 6 ......(2) Then now from the given options we can identify which satisfies the all the conditions. Here Y =2 and E = 4 satisfies all the conditions.
Q: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 4371 05b5cc6bde4d2b4197774d8de
5b5cc6bde4d2b4197774d8de- 1A gain of Rs. 27false
- 2A loss of Rs. 37true
- 3A loss of Rs. 27false
- 4A gain of Rs. 37false
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Answer : 2. "A loss of Rs. 37"
Explanation :
Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is: 64 − 27 = 37 A loss of Rs.37
Q: If a soldier fires 7 shots from a gun in 12 minutes then find the total number of shots fired by the man in 3/2 hrs. 4359 05b5cc6b4e4d2b4197774d49b
5b5cc6b4e4d2b4197774d49b- 145false
- 244false
- 346true
- 447false
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Answer : 3. "46"
Explanation :
Answer: C) 46 Explanation: Here given soldier shots 7 shots in 12 min => 1 shot doen't take any time in 12 min => Only 6 shots take 12 min 12 min ------ 6 shots 90 min ------ ? shots => 90 x (6/12) = 45 Therefore, total shots fired in 90 minutes = 45 + 1 = 46 shots.
Q: राम एवं नरेश किसी काम को 20 दिनों में समाप्त करते हैं, जबकि नरेश इसी कार्य को 36 दिनों में समाप्त करता है। दोनों को मजदूरी के रूप में 720 रूपये मिलते हैं। इसमें राम को मजदूरी के रूप में कितनी रकम प्राप्त होगी? 4357 25d1497e1489f2f135e08ded4
5d1497e1489f2f135e08ded4- 1300रूपयेfalse
- 2380रूपयेfalse
- 3400रूपयेfalse
- 4320रूपयेtrue
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Answer : 4. "320रूपये"
Q: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 4346 05b5cc73ae4d2b4197774f8d8
5b5cc73ae4d2b4197774f8d8- 17 hrsfalse
- 27.5 hrstrue
- 38 hrsfalse
- 48.25 hrsfalse
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Answer : 2. "7.5 hrs"
Explanation :
Answer: B) 7.5 hrs Explanation: Let there are L men job requires LK man hours. job completed in first 4 hrs = L x 4 = 4L job completed in next 4 hrs = 4 x L/2 = 2L job completed in next 4 hrs = 4 x L/4 = L job completed in last 4 hrs = 4 x L/8 = L/2 4L + 2L + L + L/2 = KL K = 7+1/2 = 7.5 hours.
Q: In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes ? 4334 05b5cc6e2e4d2b4197774ec34
5b5cc6e2e4d2b4197774ec34- 1446false
- 2415false
- 3404false
- 4430true
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Answer : 4. "430"
Explanation :
Answer: D) 430 Explanation: Let the total number of valid votes be 'V'. 70% of V = 70/100 x V = 7V/10 Number of votes secured by the other candidate = V - 7V/100 = 3V/10 Given, 7V/10 - 3V/10 = 172 => 4V/10 = 172 => 4V = 1720 => V = 430.
Q: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4330 05b5cc74fe4d2b4197774faea
5b5cc74fe4d2b4197774faea- 11124false
- 21420false
- 31345false
- 41250true
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Answer : 4. "1250"
Explanation :
Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.