Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: The number of ways in which 8 distinct toys can be distributed among 5 children? 4494 05b5cc699e4d2b4197774c700
5b5cc699e4d2b4197774c700- 15P8false
- 25^8true
- 38P5false
- 48^5false
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उत्तर : 2. "5^8"
व्याख्या :
Answer: B) 5^8 Explanation: As the toys are distinct and not identical, For each of the 8 toys, we have three choices as to which child will receive the toy. Therefore, there are 58 ways to distribute the toys. Hence, it is 58 and not 85.
प्र: If a soldier fires 7 shots from a gun in 12 minutes then find the total number of shots fired by the man in 3/2 hrs. 4472 05b5cc6b4e4d2b4197774d49b
5b5cc6b4e4d2b4197774d49b- 145false
- 244false
- 346true
- 447false
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उत्तर : 3. "46"
व्याख्या :
Answer: C) 46 Explanation: Here given soldier shots 7 shots in 12 min => 1 shot doen't take any time in 12 min => Only 6 shots take 12 min 12 min ------ 6 shots 90 min ------ ? shots => 90 x (6/12) = 45 Therefore, total shots fired in 90 minutes = 45 + 1 = 46 shots.
प्र: राम एवं नरेश किसी काम को 20 दिनों में समाप्त करते हैं, जबकि नरेश इसी कार्य को 36 दिनों में समाप्त करता है। दोनों को मजदूरी के रूप में 720 रूपये मिलते हैं। इसमें राम को मजदूरी के रूप में कितनी रकम प्राप्त होगी? 4463 25d1497e1489f2f135e08ded4
5d1497e1489f2f135e08ded4- 1300रूपयेfalse
- 2380रूपयेfalse
- 3400रूपयेfalse
- 4320रूपयेtrue
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उत्तर : 4. "320रूपये"
प्र: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 4459 05b5cc73ae4d2b4197774f8d8
5b5cc73ae4d2b4197774f8d8- 17 hrsfalse
- 27.5 hrstrue
- 38 hrsfalse
- 48.25 hrsfalse
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उत्तर : 2. "7.5 hrs"
व्याख्या :
Answer: B) 7.5 hrs Explanation: Let there are L men job requires LK man hours. job completed in first 4 hrs = L x 4 = 4L job completed in next 4 hrs = 4 x L/2 = 2L job completed in next 4 hrs = 4 x L/4 = L job completed in last 4 hrs = 4 x L/8 = L/2 4L + 2L + L + L/2 = KL K = 7+1/2 = 7.5 hours.
प्र: Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ? 4458 05b5cc73ae4d2b4197774f8ce
5b5cc73ae4d2b4197774f8ce- 1E = 15 & Y = 3false
- 2E = 14 & Y = 12false
- 3E = 40 & Y = 22false
- 4E = 4 & Y = 2true
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उत्तर : 4. "E = 4 & Y = 2"
व्याख्या :
Answer: D) E = 4 & Y = 2 Explanation: Let the the age of the elder boy = E Let the the age of the younger boy = Y Given that Y = cube root of EY => Y3 = EY => E = Y2 .....(1)By the condition of number replacement the age of the father is YE The Mother's age = EY/2 But she is 3 years less than father => EY/2 + 3 = YE2YE = EY + 6 ......(2) Then now from the given options we can identify which satisfies the all the conditions. Here Y =2 and E = 4 satisfies all the conditions.
प्र: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4423 05b5cc74fe4d2b4197774faea
5b5cc74fe4d2b4197774faea- 11124false
- 21420false
- 31345false
- 41250true
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उत्तर : 4. "1250"
व्याख्या :
Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.
प्र: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 4416 05b5cc6bde4d2b4197774d8de
5b5cc6bde4d2b4197774d8de- 1A gain of Rs. 27false
- 2A loss of Rs. 37true
- 3A loss of Rs. 27false
- 4A gain of Rs. 37false
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उत्तर : 2. "A loss of Rs. 37"
व्याख्या :
Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is: 64 − 27 = 37 A loss of Rs.37
प्र: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 kmph. Then find the speed of faster train ? 4406 05b5cc6dee4d2b4197774ea56
5b5cc6dee4d2b4197774ea56- 168 kmphtrue
- 252 kmphfalse
- 376 kmphfalse
- 450 kmphfalse
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उत्तर : 1. "68 kmph"
व्याख्या :
Answer: A) 68 kmph Explanation: Let the speed of the faster train be 'X' kmph, Then their relative speed= X - 48 kmphTo cross slower train by faster train, Distance need to be cover = (400 + 600)m = 1 km. and Time required = 180 sec = 180/3600 hr = 1/20 hr.Time = Distance/Speed => 1/20 = 1/(x-48)X = 68 kmph