Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: 5 years ago Sushma was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find their ages ? 4218 0

  • 1
    24 and 13 years
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  • 2
    48 and 24 years
    सही
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  • 3
    35 and 11 years
    सही
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  • 4
    33 and 15 years
    सही
    गलत
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उत्तर : 3. "35 and 11 years"
व्याख्या :

Answer: C) 35 and 11 years Explanation: Let the age of sushma be x and the age of her son is yThen five years before x-5=5(y-5) ...(1)Five years hence x+5 = 3(y+5)-8 .....(2) By soving (1) & (2), we get5y - 15 = 3y + 7y = 11 => x = 35 Therefore, the age of Sushma = 35 and her son = 11.

प्र: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 kmph. Then find the speed of faster train  ? 4214 0

  • 1
    68 kmph
    सही
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  • 2
    52 kmph
    सही
    गलत
  • 3
    76 kmph
    सही
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  • 4
    50 kmph
    सही
    गलत
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उत्तर : 1. "68 kmph"
व्याख्या :

Answer: A) 68 kmph Explanation: Let the speed of the faster train be 'X' kmph, Then their relative speed= X - 48 kmphTo cross slower train by faster train, Distance need to be cover = (400 + 600)m = 1 km. and Time required = 180 sec = 180/3600 hr = 1/20 hr.Time = Distance/Speed => 1/20 = 1/(x-48)X = 68 kmph

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उत्तर : 3. "11 बजे सुबह"

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उत्तर : 1. "\({40\over3}\)"

प्र: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 4139 0

  • 1
    75 min
    सही
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  • 2
    82 min
    सही
    गलत
  • 3
    90 min
    सही
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  • 4
    101 min
    सही
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उत्तर : 3. "90 min"
व्याख्या :

Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.

प्र: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 4125 0

  • 1
    1080 cm
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  • 2
    180 m
    सही
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  • 3
    108 m
    सही
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  • 4
    118 cm
    सही
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उत्तर : 3. "108 m"
व्याख्या :

Answer: C) 108 m Explanation: We know the rule that,   At particular time for all object , ratio of height and shadow are same.   Let the height of the pole be 'H'   Then  188=H48   => H = 108 m.

प्र: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 4119 0

  • 1
    7 : 12
    सही
    गलत
  • 2
    8 : 13
    सही
    गलत
  • 3
    9 : 4
    सही
    गलत
  • 4
    2 : 5
    सही
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उत्तर : 2. "8 : 13"
व्याख्या :

Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13

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उत्तर : 2. "30 min"
व्याख्या :

Answer: B) 30 min Explanation: Distance travelled by Ramu = 45 x 4 = 180 km Somu travelled the same distance in 6 hours. His speed = 180/6 = 30 km/hr Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr. Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively. Hence difference in the time taken = 0.5 hours = 30 minutes.

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