Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: If a trader sold two cars each at Rs. 325475 and gains 12% on the first and loses 12% on the second, then his profit or loss percent on the whole is ? 4012 0

  • 1
    1.44% loss
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  • 2
    14.4% loss
    सही
    गलत
  • 3
    0%
    सही
    गलत
  • 4
    14.4% profit
    सही
    गलत
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उत्तर : 1. "1.44% loss"
व्याख्या :

Answer: A) 1.44% loss Explanation: SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.In this case, there will be loss and percentage of loss is given by = [(profit%)(loss%)]/100 = (12)(12)/100 % = 1.44%

प्र: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3962 0

  • 1
    127.5 m
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  • 2
    254 m
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  • 3
    184 m
    सही
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  • 4
    212 m
    सही
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उत्तर : 1. "127.5 m"
व्याख्या :

Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.

प्र: एक बस बिना कोई रूकावट के 60 किमी/घंटे की रफ्तार से चल रही है। परन्तु ,रूकावट के साथ 50 किमी/घंटा की रफ्तार से चल पाती है। रूकावट की दर ज्ञात करें? 3945 0

  • 1
    15 मिनट प्रति घंटा
    सही
    गलत
  • 2
    20 मिनट प्रति घंटा
    सही
    गलत
  • 3
    12 मिनट प्रति घंटा
    सही
    गलत
  • 4
    10 मिनट प्रति घंटा
    सही
    गलत
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उत्तर : 4. "10 मिनट प्रति घंटा"

प्र: A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares? 3944 0

  • 1
    10000 and 15000
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  • 2
    15000 and 10000
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  • 3
    5000 and 20000
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  • 4
    20000 and 5000
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उत्तर : 1. "10000 and 15000"
व्याख्या :

Answer: A) 10000 and 15000 Explanation: As both A and B invest the same amounts, the ratio of their profits at the end of the year is equal to the ratio of the time periods for which they have invested.   Thus, the required ratio of their profits = A : B = 8 : 12 = 2 : 3.   Hence, share of A in the total profit = 2 x 25000/5 = Rs.10000   Similarly, share of B in the total profit = 3 x 25000/5 = Rs.15000

प्र: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ? 3935 0

  • 1
    145
    सही
    गलत
  • 2
    165
    सही
    गलत
  • 3
    175
    सही
    गलत
  • 4
    135
    सही
    गलत
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उत्तर : 3. "175"
व्याख्या :

Answer: C) 175 Explanation: Given that,  working days = 5  working hours = 8  A man get rupess per hour is Rs.2.40  So in one day the man get total rupees is 2.40 x 8 = 19.2  So in 5 days week the man get total rupees is 19.2 x 5 = 96  So in 4 week the man get total rupees is 96 x 4 = 384  So the man worked for = 160hours in 4 weeks    But given that the man earned Rs.432    Hence remaning money is (432-384 = 48)which is earn by doing overtime work   Overtime hours  = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.

प्र: What is the next number in the given Number Series? 5, 24, 94, 279, ? 3919 0

  • 1
    587
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  • 2
    554
    सही
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  • 3
    489
    सही
    गलत
  • 4
    499
    सही
    गलत
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उत्तर : 2. "554"
व्याख्या :

Answer: B) 554 Explanation: The given number series follows a pattern that 5 x 5 – 1 = 24 24 x 4 – 2 = 94 94 x 3 – 3 = 279 279 x 2 – 4 = 554

प्र: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3916 0

  • 1
    1:3
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  • 2
    2:1
    सही
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  • 3
    3:2
    सही
    गलत
  • 4
    2:3
    सही
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उत्तर : 3. "3:2"
व्याख्या :

Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.

प्र: 8 couples (husband and wife) attend a dance show "Nach Baliye' in a popular TV channel ; A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is atleast one couple will be selected is : 3902 0

  • 1
    8/39
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  • 2
    15/39
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  • 3
    12/13
    सही
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  • 4
    None of these
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उत्तर : 2. "15/39"
व्याख्या :

Answer: B) 15/39 Explanation: P( selecting atleast one couple) = 1 - P(selecting none of the couples for the prize)     = 1-16C1× 14C1×12C1×10C116C4=1539

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