Answer: B) 70 years Explanation: Let Kumar’s present age be "x" years and Sailesh’s present age be "y" years.Then, according to the first condition, x - 10 = 3(y - 10) => x - 3y = - 20 ........(1) Now, Kumar’s age after 10 years = (x + 10) years. Sailesh’s age after 10 years = (y + 10) years. (x + 10) = 2 (y + 10)  => x - 2y = 10 ......(2)   Solving (1) and (2), we get x = 70 and y = 30 Kumar’s present age = 70 years    and  Sailesh’s present age = 30 years.

Answer: A) 10000 and 15000 Explanation: As both A and B invest the same amounts, the ratio of their profits at the end of the year is equal to the ratio of the time periods for which they have invested.   Thus, the required ratio of their profits = A : B = 8 : 12 = 2 : 3.   Hence, share of A in the total profit = 2 x 25000/5 = Rs.10000   Similarly, share of B in the total profit = 3 x 25000/5 = Rs.15000

Answer: A) 45 metric tonnes Explanation: 2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton  i.e. 3 engines of latter type consumes 1 ton for one hour Hence 9 engines consumes 3 tons for one hour For 15 hours it is 15 x 3 = 45 metric tonnes.

Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.

Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.

Answer: C) 175 Explanation: Given that,  working days = 5  working hours = 8  A man get rupess per hour is Rs.2.40  So in one day the man get total rupees is 2.40 x 8 = 19.2  So in 5 days week the man get total rupees is 19.2 x 5 = 96  So in 4 week the man get total rupees is 96 x 4 = 384  So the man worked for = 160hours in 4 weeks    But given that the man earned Rs.432    Hence remaning money is (432-384 = 48)which is earn by doing overtime work   Overtime hours  = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.

Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.

Answer: B) 554 Explanation: The given number series follows a pattern that 5 x 5 – 1 = 24 24 x 4 – 2 = 94 94 x 3 – 3 = 279 279 x 2 – 4 = 554