Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: Rs. 7444 is divided among 5 ladies, 3 gents and 3 girls. The ratio of share of a lady, a gents and a girl is 7: 4: 3. What is the share of gents ? 3207 05b5cc741e4d2b4197774f9cc
5b5cc741e4d2b4197774f9cc- 1Rs. 1595.14true
- 2Rs. 1793.4false
- 3Rs. 595.14false
- 4Rs. 1551.5false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "Rs. 1595.14"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) Rs. 1595.14 Explanation: Ratio of the share of a lady, a gents and a girl is 7 : 4 : 3No of ladies, gents and girls are 5, 3, 3Thus effective ratio of ladies, gents and girls is 7 x 5 : 4 x 3 : 3 x 3 = 35 : 12 : 9so part of gents = (12/56) x 7444 = Rs. 1595.142so part of 1 gents = 1595.142/3 = Rs. 531.71.
рдкреНрд░: Simplify the following equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 3204 05b5cc604e4d2b4197774b4fd
5b5cc604e4d2b4197774b4fd- 1226.65true
- 2196.55false
- 3202.35false
- 4216.66false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "226.65"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 226.65 Explanation: 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? ┬а ┬а55.55 155.00 ┬а15.55 ┬а ┬а0.5 ┬а ┬а0.05 _______ 226.65 _______ ┬а Hence, the value of the given equation┬а55.55 + 155 + 15.55 + 0.5 + 0.05 = 226.65.
рдкреНрд░: The ratio of KarthikтАЩs and KalyanтАЩs ages is 4: 5. If the difference between the present age of Kalyan and the age of Karthik 5 years hence is 3 years, then what is the total of present ages of Karthik and Kalyan? 3202 05b5cc77fe4d2b419777501a1
5b5cc77fe4d2b419777501a1- 156 yearsfalse
- 262 yearsfalse
- 369 yearsfalse
- 472 yearstrue
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "72 years"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 72 years Explanation: Let us consider Karthik as K1 and Kalyan as K2. Given┬аk18+k1┬аand K2 - (K1 + 5) = 3┬а K2 - K1 = 8 K2 = 8 + K1 Now,┬а k18+k1=┬а45 => K1 = 32 years Therefore K2 = 40 years. K1 + K2 = 72 years.
рдкреНрд░: Suppose today is Friday, what day of the week will it be 65 days from now? 3195 05b5cc69be4d2b4197774c7de
5b5cc69be4d2b4197774c7de- 1Saturdayfalse
- 2Sundaytrue
- 3Fridayfalse
- 4Thursdayfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "Sunday"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) Sunday Explanation: The day of the week repeats every 7 days. Given today is Friday. Again Friday┬аis repeated on the 7th day, 14th,...┬аon 7 multiple days. Hence, Friday is on the 63rd day, as 63 is multiple of 7. ┬а Now, the required day of the week on the 65th day is Sunday.
рдкреНрд░: Two goods trains each 520 m long, are running in opposite directions on parallel tracks. Their speeds are 42 km/hr and 36 km/hr respectively. Find the time taken by the slower train to cross the driver of the faster one ? 3194 05b5cc76fe4d2b4197774ff3f
5b5cc76fe4d2b4197774ff3f- 160 secfalse
- 248 sectrue
- 345 secfalse
- 434 secfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "48 sec"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 48 sec Explanation: Relative speed = 42 + 36 = 78 km/hr = 653┬аm/s Distance = (520 + 520) =1040 mts. Time =┬а1040├Ч365= 48 sec
рдкреНрд░: A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ? 3193 05b5cc71ee4d2b4197774f57c
5b5cc71ee4d2b4197774f57c- 14/3 hrsfalse
- 22/3 hrstrue
- 33/2 hrsfalse
- 41/4 hrsfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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- SingleChoice
рдЙрддреНрддрд░ : 2. "2/3 hrs"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 2/3 hrs Explanation: Let the original speed and time is S and Tthen distance = S x TNow the speed changes to 2/3S and T is T+20As the distance is sameS x T = 2/3Sx(T+20)solving this we get t = 40 minutes =40/60 = 2/3 hour
рдкреНрд░: Amith can row a boat d km upstream and the same distance downstream in 5 hours 15 minutes. Also, he can row the boat 2d km upstream in 7 hours. How long will it take to row the same distance 2d km downstream for Amith ? 3182 05b5cc6c3e4d2b4197774dc63
5b5cc6c3e4d2b4197774dc63- 14 hrs 10 minfalse
- 23 hrs 15 minfalse
- 33 hrs 30 mintrue
- 44 hrs 1 minfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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- SingleChoice
рдЙрддреНрддрд░ : 3. "3 hrs 30 min"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 3 hrs 30 min Explanation: Let the speed of boat and stream be x and y kmph respectively. According to question d/x+y + d/x-y = 5h 15m or 21/4 hrs ......(i) and 2d/x-y = 7...... (ii) From eq. (i) and (ii) 2d/x+y = 7/2 Hence, Amith will take to row 2d km distance downstream in 7/2 hrs = 3.5 hrs = 3 hrs 30 min.
рдкреНрд░: Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x ? 3180 05b5cc6dce4d2b4197774e9bf
5b5cc6dce4d2b4197774e9bf- 111.8false
- 212.9false
- 313.7false
- 414.5true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "14.5"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 14.5 Explanation: Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.k/l = 5/x ------ (1)k = m - 18 ------ (2)m + 9 = 47 ------ (3)k - l = m ----- (4)(3) => m = 47 - 9 = 38 years(2) => k = 38 -18 = 20 years(1) => 20/l = 5/x => l = 4x(4) => 4x - 20 = 38=> 4x = 58 => x = 14.5

