Answer: B) 2/3 hrs Explanation: Let the original speed and time is S and Tthen distance = S x TNow the speed changes to 2/3S and T is T+20As the distance is sameS x T = 2/3Sx(T+20)solving this we get t = 40 minutes =40/60 = 2/3 hour

Answer: B) 48 sec Explanation: Relative speed = 42 + 36 = 78 km/hr = 653 m/s Distance = (520 + 520) =1040 mts. Time = 1040×365= 48 sec

Answer: A) Rs. 1595.14 Explanation: Ratio of the share of a lady, a gents and a girl is 7 : 4 : 3No of ladies, gents and girls are 5, 3, 3Thus effective ratio of ladies, gents and girls is 7 x 5 : 4 x 3 : 3 x 3 = 35 : 12 : 9so part of gents = (12/56) x 7444 = Rs. 1595.142so part of 1 gents = 1595.142/3 = Rs. 531.71.

Answer: C) 3 hrs 30 min Explanation: Let the speed of boat and stream be x and y kmph respectively. According to question d/x+y + d/x-y = 5h 15m or 21/4 hrs ......(i) and 2d/x-y = 7...... (ii) From eq. (i) and (ii) 2d/x+y = 7/2 Hence, Amith will take to row 2d km distance downstream in 7/2 hrs = 3.5 hrs = 3 hrs 30 min.

Answer: A) 56 Explanation: The given number series follows a pattern that, 9 9 x 0.5 + 0.5 = 5 5 x 1 + 1 = 6 6 x 2 + 2 = 14 14 x 4 + 4 = 60 (not equals to 56) 60 x 8 + 8 = 488.   Hence, the odd one in the given number series is 56.

Answer: D) Data is not sufficient Explanation: Let the sum be Rs. p, rate be R% p.a. and time be T years. Then,  P×T×(R+2)100-P×T×R100=108  ⇒2PT= 10800  ...... (1)  And,   P×R×(T+2)100-P×R×T100=180   ⇒2PR = 18000 ......(2) Clearly, from (1) and (2), we cannot find the value of pSo, the data is not sufficient.

Answer: C) 47 Explanation: The next number in the series is 143 143 136 110       0    7      26 (Differences)  13 - 1 , 23 - 1, 33 - 1, 43 - 1,...Now the next number is given by110 - (43 - 1) = 110 - 63 = 47.

Answer: A) 226.65 Explanation: 55.55 + 155 + 15.55 + 0.5 + 0.05 = ?    55.55 155.00  15.55    0.5    0.05 _______ 226.65 _______   Hence, the value of the given equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = 226.65.