Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: 80% of 900 + 162 x 4 x ? = 113 - 99 3297 05b5cc669e4d2b4197774bf6d
5b5cc669e4d2b4197774bf6d- 10.5true
- 21false
- 34false
- 40false
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उत्तर : 1. "0.5"
व्याख्या :
Answer: A) 0.5 Explanation: 80x900/100 + 256 x 4 x ? = 1331 - 99 720 + 1024 x ? = 1232 ? = 1232 - 720/1024 ? = 512/1024 = 0.5 ? = 0.5
प्र: अ, ब और स किसी काम को क्रमशः 10 दिन, 15 दिन, और 20 दिनों में पूरा करते हैं। अ व ब किसी काम को शुरू करते हैं, काम शुरू होने के दो दिन बाद ब की जगह स आ जाता है तथा उस दिन के 1 दिन बाद अ काम करना छोड़ देता हैं, तो बताएँ पूरा काम समाप्त होनें में कितना समय लगेगा? 3287 05d1485969aeb0a08f1e67225
5d1485969aeb0a08f1e67225- 113false
- 2\(13 {1 \over 13 }\)true
- 3\(18 {4 \over 3 }\)false
- 418false
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उत्तर : 2. " \(13 {1 \over 13 }\)"
प्र: एक दूकानदार 33मीटर कपड़ा बेचता है और उसे 11 मीटर कपड़े के विक्रय मूल्य के बराबर लाभ हुआ । उसका लाभ प्रतिशत क्या होगा- 3278 15d1331bc925caa2d5bbbff70
5d1331bc925caa2d5bbbff70- 150%true
- 252%false
- 345%false
- 455%false
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उत्तर : 1. "50%"
प्र: What is the probability of an impossible event? 3273 05b5cc69ee4d2b4197774c995
5b5cc69ee4d2b4197774c995- 10true
- 2-1false
- 30.1false
- 41false
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उत्तर : 1. "0"
व्याख्या :
Answer: A) 0 Explanation: The probability of an impossible event is 0. The event is known ahead of time to be not possible, therefore by definition in mathematics, the probability is defined to be 0 which means it can never happen. The probability of a certain event is 1.
प्र: How many 7 digit numbers can be formed using the digits 1, 2, 0, 2, 4, 2, 4? 3269 05b5cc7d1e4d2b41977751295
5b5cc7d1e4d2b41977751295- 1120false
- 2360true
- 3240false
- 4424false
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उत्तर : 2. "360"
व्याख्या :
Answer: B) 360 Explanation: There are 7 digits 1, 2, 0, 2, 4, 2, 4 in which 2 occurs 3 times, 4 occurs 2 times. Number of 7 digit numbers = 7!3!×2! = 420 But out of these 420 numbers, there are some numbers which begin with '0' and they are not 7-digit numbers. The number of such numbers beginning with '0'. =6!3!×2! = 60 Hence the required number of 7 digits numbers = 420 - 60 = 360
प्र: A batsman scores 26 runs and increases his average from 14 to 15. Find the runs to be made if he wants top increasing the average to 19 in the same match ? 3265 05b5cc745e4d2b4197774fa22
5b5cc745e4d2b4197774fa22- 174true
- 279false
- 372false
- 460false
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उत्तर : 1. "74"
व्याख्या :
Answer: A) 74 Explanation: Number of runs scored more to increse the ratio by 1 is 26 - 14 = 12To raise the average by one (from 14 to 15), he scored 12 more than the existing average.Therefore, to raise the average by five (from 14 to 19), he should score 12 x 5 = 60 more than the existing average. Thus he should score 14 + 60 = 74.
प्र: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 3257 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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उत्तर : 4. "9:1"
व्याख्या :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
प्र: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ? 3254 05b5cc6dee4d2b4197774ea79
5b5cc6dee4d2b4197774ea79- 12413 sq.mfalse
- 21234 sq.mfalse
- 34312 sq.mtrue
- 42143 sq.mfalse
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उत्तर : 3. "4312 sq.m"
व्याख्या :
Answer: C) 4312 sq.m Explanation: Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively. 2πs = 264 and 2πl = 352 s = 2642π and l = 3522π Difference between the areas =πl2-πs2 = π1762π2-1322π2 = 1762π-1322π = (176 - 132)(176 + 132) / π = (44 x 308) / (22/7) = 4312 sq.m