Quantitative Aptitude Practice Question and Answer
8Q: 26 पुरूष एक काम को 17 दिनों में पूरा कर सकते हैं। 13 दिनों में का पूरा करने के लिए और कितने लोगों को काम पर लगाना चाहिए? 3436 15d14995a489f2f135e08df26
5d14995a489f2f135e08df26- 19false
- 28true
- 36false
- 418false
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Answer : 2. "8"
Q: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 3436 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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Answer : 4. "9:1"
Explanation :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Q: A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ? 3419 05b5cc720e4d2b4197774f613
5b5cc720e4d2b4197774f613- 145false
- 224false
- 342false
- 454true
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Answer : 4. "54"
Explanation :
Answer: D) 54 Explanation: By trial and error method from the given options, as 54 - 45 = (1/11) x (45+54) = 99/11 = 9 Hence this satisfies the given conditions. Then the woman's husband age is 54.
Q: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ? 3417 05b5cc6e7e4d2b4197774edb0
5b5cc6e7e4d2b4197774edb0- 11900true
- 22100false
- 31700false
- 42000false
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Answer : 1. "1900"
Explanation :
Answer: A) 1900 Explanation: Given 2000 ---- 54 days The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days. i.e, 2000 ----- 39 days == m ---- 20 days => m x 20 = 2000 x 39 m = 3900 So total men for 20 days is 3900 => 2000 old and 1900 new reinforcement. Hence, reinforcement = 1900.
Q: If the rate increases by 2%, the simple interest received on a sum of money increases by Rs. 108. If the time period is increased by 2 years, the simple interest on the same sum increases by Rs.180. The sum is ? 3400 05b5cc767e4d2b4197774fe0b
5b5cc767e4d2b4197774fe0b- 1Rs. 540false
- 2Rs. 415false
- 3Rs. 404false
- 4Data is not sufficienttrue
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Answer : 4. "Data is not sufficient"
Explanation :
Answer: D) Data is not sufficient Explanation: Let the sum be Rs. p, rate be R% p.a. and time be T years. Then, P×T×(R+2)100-P×T×R100=108 ⇒2PT= 10800 ...... (1) And, P×R×(T+2)100-P×R×T100=180 ⇒2PR = 18000 ......(2) Clearly, from (1) and (2), we cannot find the value of pSo, the data is not sufficient.
Q: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest ? 3397 05b5cc6ebe4d2b4197774eeb9
5b5cc6ebe4d2b4197774eeb9- 120% p.atrue
- 215% p.afalse
- 318% p.afalse
- 424% p.afalse
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Answer : 1. "20% p.a"
Explanation :
Answer: A) 20% p.a Explanation: Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year. Rate of interest = (100 x 240) / (1200) = 20% p.a
Q: Cube root of 729 then square it 3395 05b5cc658e4d2b4197774bdf7
5b5cc658e4d2b4197774bdf7- 19false
- 236false
- 381true
- 4144false
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Answer : 3. "81"
Explanation :
Answer: C) 81 Explanation: 729 = 9 x 9 x 9 => Cube root of 729 = 9 Now, required square of 9 = 9 x 9 = 81.
Q: A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ? 3388 05b5cc70ee4d2b4197774f337
5b5cc70ee4d2b4197774f337- 122/7 x 24/35true
- 222/7 x 36 x 4false
- 322/7 x 36/5false
- 422/7 x 37/21false
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Answer : 1. "22/7 x 24/35"
Explanation :
Answer: A) 22/7 x 24/35 Explanation: Since level of water increased in cylinder by height 4. This is because of the rectangular block . Therefore , area of rectangular block immersed in water is = 227×6×6×4 Thats why portion of block immersed in water is = (22/7 * 36 * 4) / total vol. of rectangle = (22/7 * 36 * 4)/ (7*5*6) = (22/7 * 24)/ 35.

