Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: If 10 men take 15 days to complete a work. In how many days will 37 men complete the work? 3469 05b5cc6bfe4d2b4197774da3d
5b5cc6bfe4d2b4197774da3d- 13 daysfalse
- 24 daystrue
- 35 daysfalse
- 46 daysfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "4 days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 4 days Explanation: Given 10 men┬аtake 15 days to complete a work => Total mandays┬а= 15 x 10 = 150 Let the work be 150 mandays. => Now 37 men can do 150 mandays┬аin 150/37 =~ 4 days
рдкреНрд░: Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay ? 3468 05b5cc6eee4d2b4197774ef04
5b5cc6eee4d2b4197774ef04- 141 yrsfalse
- 240 yrstrue
- 337 yrsfalse
- 433 yrsfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "40 yrs"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 40 yrs Explanation: Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively. => A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8) => 3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8 V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8 => 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8 => 10 - 20/3 = 10/12 A - 9/12 A => 10/3 = A/12 => A = 40.
рдкреНрд░: Three men, four women and six children can complete a work in 9 days. A women does┬а double the work a man does and a child does half the work a man does. How many women alone can complete this work in 9 days? 3461 05b5cc6b2e4d2b4197774d374
5b5cc6b2e4d2b4197774d374- 17true
- 28false
- 39false
- 46false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "7"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 7 Explanation: Given (3 Men + 4 Women + 6 Children) -----> 9 days But W = 2M and C = M/2 Now, convert Men and Children into Women by 3W2┬а+┬а4W┬а+┬а6W4=>┬а32┬а+┬а4┬а+┬а32┬а=┬а7┬аWomen┬а Therefore, 7 women alone can complete this work in 9 days.
рдкреНрд░: Find the odd one out of the floowing number series? 270, 261, 279, 252, 289, 243 3448 05b5cc639e4d2b4197774ba8c
5b5cc639e4d2b4197774ba8c- 1270false
- 2279false
- 3289true
- 4243false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "289"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 289 Explanation: Here the given number series is┬а270, 261, 279, 252, 289, 243 270 - 9 = 261 261 + 18 = 279 279 - 27 = 252 252 + 36 = 288 (not equals to 289) 288 - 45 = 243 ┬а Hence, the odd number in the given number series is 289.
рдкреНрд░: If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ? 3446 15b5cc74ae4d2b4197774fabd
5b5cc74ae4d2b4197774fabd- 1Rs. 175false
- 2Rs. 325false
- 3Rs. 340true
- 4Rs. 260false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "Rs. 340"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) Rs. 340 Explanation: Assume first child (the youngest) get = Rs. x According to the question ;each son having Rs. 30 more than the younger one Second child will get = Rs. x + 30 Third child will get = Rs. x + 30 + 30 = x + 60 Forth child will get = Rs. x + 30 + 30 + 30 = x + 90 Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120 Total amount they got = Rs. 2000 x + (x+30) + (x+60) + (x+90) + (x+120) = 20005x + 300 = 20005x = 1700x = Rs. 340So the youngest child will get Rs. 340.
рдкреНрд░: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ┬а? 3443 05b5cc6dee4d2b4197774ea79
5b5cc6dee4d2b4197774ea79- 12413 sq.mfalse
- 21234 sq.mfalse
- 34312 sq.mtrue
- 42143 sq.mfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "4312 sq.m"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 4312 sq.m Explanation: Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.┬а┬а ┬а2╧Аs = 264 and┬а2╧Аl = 352┬а┬а ┬а ┬аs =┬а2642╧А and l =┬а3522╧А┬а┬а┬а Difference between the areas =╧Аl2-╧Аs2┬а┬а┬а ┬а┬а=┬а╧А1762╧А2-1322╧А2┬а ┬а┬а= 1762╧А-1322╧А┬а┬а ┬а = (176 - 132)(176 + 132) /┬а╧А┬а┬а ┬а = (44 x 308) / (22/7) = 4312 sq.m
рдкреНрд░: The percentage discount offered for "Buy 6 get 1 free is" ? 3429 05b5cc72ce4d2b4197774f788
5b5cc72ce4d2b4197774f788- 185.78 %false
- 258. 48 %false
- 319.25 %false
- 414.285 %true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "14.285 %"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 14.285 % Explanation: Total Items = 7Discounted = 1Percentage = 1/7 x 100= 14.285%
рдкреНрд░: Running 3/4th of his usual rate, a man is 15min late. Find his usual time in hours┬а ? 3424 05b5cc6d8e4d2b4197774e782
5b5cc6d8e4d2b4197774e782- 12/3 hrsfalse
- 23/4 hrstrue
- 31/3 hrsfalse
- 41/4 hrsfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "3/4 hrs"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 3/4 hrs Explanation: Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time ┬а so 1/3rd of the usual time = 15minor usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.

