Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 2902 05b5cc74ae4d2b4197774fa9a
5b5cc74ae4d2b4197774fa9a- 118false
- 214true
- 322false
- 424false
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उत्तर : 2. "14"
व्याख्या :
Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14
प्र: If (1 × 2 × 3 × 4 ........ × n) = n!, then 15! - 14! - 13! is equal to ___? 2889 05b5cc6bee4d2b4197774d997
5b5cc6bee4d2b4197774d997- 114 × 13 × 13!false
- 215 × 14 × 14!false
- 314 × 12 × 12!false
- 415 × 13 × 13!true
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उत्तर : 4. "15 × 13 × 13!"
व्याख्या :
Answer: D) 15 × 13 × 13! Explanation: 15! - 14! - 13! = (15 × 14 × 13!) - (14 × 13!) - (13!) = 13! (15 × 14 - 14 - 1) = 13! (15 × 14 - 15) = 13! x 15 (14 - 1) = 15 × 13 × 13!
प्र: If 4th december 1999 is Monday then what day is 3rd january 2000 ? 2883 05b5cc73ae4d2b4197774f8ba
5b5cc73ae4d2b4197774f8ba- 1Sundayfalse
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdaytrue
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उत्तर : 4. "Wednesday"
व्याख्या :
Answer: D) Wednesday Explanation: Here from 4th December 1999 to 3rd January 2000,there is a difference of 30 days.Number of odd days = 30/7 = 2 odd days Then no. of odd days = 2 => tuesday and wednesday(from monday). Hence on 3rd january it is wednesday.
प्र: Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay ? 2874 05b5cc6eee4d2b4197774ef04
5b5cc6eee4d2b4197774ef04- 141 yrsfalse
- 240 yrstrue
- 337 yrsfalse
- 433 yrsfalse
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उत्तर : 2. "40 yrs"
व्याख्या :
Answer: B) 40 yrs Explanation: Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively. => A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8) => 3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8 V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8 => 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8 => 10 - 20/3 = 10/12 A - 9/12 A => 10/3 = A/12 => A = 40.
प्र: A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group ? 2865 05b5cc6dde4d2b4197774e9d3
5b5cc6dde4d2b4197774e9d3- 1600true
- 2610false
- 3609false
- 4599false
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उत्तर : 1. "600"
व्याख्या :
Answer: A) 600 Explanation: Two men, three women and one child can be selected in ⁴C₂ x ⁶C₃ x ⁵C₁ ways = 600 ways.
प्र: The average age of seven persons sitting in a row facing east is 26 years. If the average age of the first three persons is 19 years and the average age of the last three persons is 32 years, then find the age of the person sitting in the middle of the row ? 2865 05b5cc6dce4d2b4197774e97e
5b5cc6dce4d2b4197774e97e- 132 yrsfalse
- 229 yrstrue
- 324 yrsfalse
- 427 yrsfalse
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उत्तर : 2. "29 yrs"
व्याख्या :
Answer: B) 29 yrs Explanation: Total age seven persons = (26 x 7)yearsTotal age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.
प्र: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2854 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
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उत्तर : 2. "2"
व्याख्या :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
प्र: In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ? 2853 05b5cc701e4d2b4197774f175
5b5cc701e4d2b4197774f175- 1Quarter monthsfalse
- 2Half yeartrue
- 32 yearsfalse
- 41 yearfalse
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उत्तर : 2. "Half year"
व्याख्या :
Answer: B) Half year Explanation: 3300 ----- 3% ↑ (1st time interval, 99) → 3399. Here, time interval is given as half-yearly i.e. 6 months.

