Quantitative Aptitude Practice Question and Answer

Q: Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ? 2888 0

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    360 m
    Correct
    Wrong
  • 2
    420 m
    Correct
    Wrong
  • 3
    460 m
    Correct
    Wrong
  • 4
    320 m
    Correct
    Wrong
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Answer : 2. "420 m"
Explanation :

Answer: B) 420 m Explanation: Let the length of the stationary train Y be LY Given that length of train X, LX = 300 m Let the speed of Train X be V. Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively. => 300/V = 25 ---> ( 1 ) (300 + LY) / V = 60 ---> ( 2 ) From (1) V = 300/25 = 12 m/sec. From (2) (300 + LY)/12 = 60 => 300 + LY = 60 (12) = 720 => LY = 720 - 300 = 420 m Length of the stationary train = 420 m

Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2886 1

  • 1
    1
    Correct
    Wrong
  • 2
    2
    Correct
    Wrong
  • 3
    4
    Correct
    Wrong
  • 4
    8
    Correct
    Wrong
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Answer : 2. "2"
Explanation :

Answer: B) 2 Explanation: Given a2 + b2 = c2   Now  1logc+ab  + 1logc-ab    = logbc+a + logbc-a   = logbc2-a2 = 2logbb = 2

Q: The average age of seven persons sitting in a row facing east is 26 years. If the average age of the first three persons is 19 years and the average age of the last three persons is 32 years, then find the age of the person sitting in the middle of the row ? 2884 0

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    32 yrs
    Correct
    Wrong
  • 2
    29 yrs
    Correct
    Wrong
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    24 yrs
    Correct
    Wrong
  • 4
    27 yrs
    Correct
    Wrong
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Answer : 2. "29 yrs"
Explanation :

Answer: B) 29 yrs Explanation: Total age seven persons = (26 x 7)yearsTotal age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.

Q: The calendar for the year 2018 will be the same for the year 2883 0

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    2023
    Correct
    Wrong
  • 2
    2027
    Correct
    Wrong
  • 3
    2029
    Correct
    Wrong
  • 4
    2022
    Correct
    Wrong
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Answer : 3. "2029"
Explanation :

Answer: C) 2029 Explanation: How to find the years which have the same Calendars :   Leap year calendar repeats every 28 years. Here 28 is distributed as 6 + 11 + 11.   Rules: a) If given year is at 1st position after Leap year then next repeated calendar year is Givenyear+6. b) If given year is at 2nd position after Leap year then next repeated calendar year is Givenyear+11. c) If given year is at 3rd position after Leap year then next repeated calendar year is Givenyear+11.   Now, the given year is 2018 We know that 2016 is a Leap year. 2016    2017    2018    2019  2020 Lp Y      1st     2nd      3rd     Lp Y   Here 2018 is at 2 nd position after the Leap year. According to rule b) the calendar of 2018 is repeated for the year is 2018 + 11 = 2029.

Q: At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ? 2881 0

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    5%
    Correct
    Wrong
  • 2
    6%
    Correct
    Wrong
  • 3
    4%
    Correct
    Wrong
  • 4
    3%
    Correct
    Wrong
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Answer : 1. "5%"
Explanation :

Answer: A) 5% Explanation: Given compound interest for 3 years = Rs. 1513.2   and simple interest for 5 years = Rs. 2400   Now, we know that  C.I = P1+R100n - 1   => 1513.2 = P1+R1003 - 1 ...........(A)   And S.I = PTR/100   => 2400 = P5R/100 ..................(B)   By solving (A) & (B), we get   R = 5%.

Q: A supplier supplies cartridges to a news paper publishing house. He earns a profit of 25% by selling cartridges for Rs. 1540. Find the cost price of the Cartridges ? 2881 0

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    Rs. 1100
    Correct
    Wrong
  • 2
    Rs. 1793.4
    Correct
    Wrong
  • 3
    Rs. 1440
    Correct
    Wrong
  • 4
    Rs. 1232
    Correct
    Wrong
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Answer : 4. "Rs. 1232"
Explanation :

Answer: D) Rs. 1232 Explanation: Let Cost Price(C.P) = Pgain% = {(S.P-C.P)/C.P} x 10025 = {(1540-P)/P} x 10025/100 = (1540-P)/P=> P = 4(1540)-4P=> 5P = 4(1540)=> P = 1232So, Cost Price = Rs. 1232

Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 2867 0

  • 1
    100
    Correct
    Wrong
  • 2
    1
    Correct
    Wrong
  • 3
    4
    Correct
    Wrong
  • 4
    0
    Correct
    Wrong
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Answer : 1. "100"
Explanation :

Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28   It is in the form of  a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c   Here a = 37, b = 35 & c = 28    => a + b + c = 37 + 35 + 28 = 100       Therefore,   = 100

Q: Jagan went to another town covering 240 km by car moving at 60 kmph. Then he covered 400km by train moving at 100 kmph and then rest 200 km he covered by a bus moving at 50 kmph. The average speed during the whole journey was ? 2864 0

  • 1
    36 kmph
    Correct
    Wrong
  • 2
    35 kmph
    Correct
    Wrong
  • 3
    72 kmph
    Correct
    Wrong
  • 4
    70 kmph
    Correct
    Wrong
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Answer : 4. "70 kmph"
Explanation :

Answer: D) 70 kmph Explanation: By car 240 km at 60 kmphTime taken = 240/60 = 4 hr. By train 240 km at 60 kmphTime taken = 400/100 = 4 hr. By bus 240 km at 60 kmphTime taken = 200/50 = 4 hr. So total time = 4 + 4 + 4 = 12 hr. and total speed = 240+400+200 = 840 kmAverage speed of the whole journey = 840/12 = 70 kmph.

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