Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: M, N and O can complete the work in 18, 36 and 54 days respectively. M started the work and worked for 8 days, then N and O joined him and they all worked together for some days. M left the job one day before completion of work. For how many days they all worked together? 3135 05b5cc695e4d2b4197774c4fb
5b5cc695e4d2b4197774c4fb- 14false
- 25true
- 33false
- 46false
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उत्तर : 2. "5"
व्याख्या :
Answer: B) 5 Explanation: Let M, N and O worked together for x days. From the given data,M alone worked for 8 daysM,N,O worked for x daysN, O worked for 1 day But given thatM alone can complete the work in 18 daysN alone can complete the work in 36 daysO alone can complete the work in 54 days The total work can be the LCM of 18, 6, 54 = 108 units M's 1 day work = 108/18 = 6 unitsN's 1 day work = 108/36 = 3 unitsO's 1 day work = 108/54 = 2 units Now, the equation is8 x 6 + 11x + 5 x 1 = 10848 + 11x + 5 = 10811x = 103 - 4811x = 55x = 5 days. Hence, all M,N and O together worked for 5 days.
प्र: What is better, to have 70% discount or 40 and 30% discount consequently ? 3128 05b5cc70ee4d2b4197774f38f
5b5cc70ee4d2b4197774f38f- 140% is betterfalse
- 270% is bettertrue
- 3Both are samefalse
- 4Nonefalse
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उत्तर : 2. "70% is better"
व्याख्या :
Answer: B) 70% is better Explanation: Let Price be Rs.100 1st CASE: Then 100 x 70/100 = 70=> price after discount = 100-70 = Rs.30 2nd CASE: Then 100 x 40/100 = 40=> price after discount = 100-40 = Rs.60then60 x 30/100 = 18=> price after 2 consequent discount = 60-18 = Rs.42 =>from 1 and 2 cases, 70% discount is better.
प्र: Two trains start from same place at same time at right angles to each other. Their speeds are 36km/hr and 48km/hr respectively. After 30 seconds the distance between them will be ? 3127 05b5cc731e4d2b4197774f819
5b5cc731e4d2b4197774f819- 1900 mtsfalse
- 2300 mtsfalse
- 3250 mtsfalse
- 4500 mtstrue
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उत्तर : 4. "500 mts"
व्याख्या :
Answer: D) 500 mts Explanation: Using pythagarous theorem,distance travelled by first train = 36x5/18x30 = 300mdistance travelled by second train = 48x5/18x30 = 400mso distance between them =√( 90000 + 160000) = √250000 = 500mts.
प्र: A driver of auto rickshaw makes a profit of 20% on every trip when he carries 3 passengers and the price of petrol is Rs. 30 a litre. Find the % profit for the same journey if he goes for 4 passengers per trip and the price of petrol reduces to Rs. 24 litres ? 3126 05b5cc6fee4d2b4197774f157
5b5cc6fee4d2b4197774f157- 168%false
- 280%false
- 375%false
- 4100%true
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उत्तर : 4. "100%"
व्याख्या :
Answer: D) 100% Explanation: When 3 passengers income was 3xexpense= Rs.30 profit =20% of 30 = Rs.6 That means his earning is Rs.36. so that per passenger fare must be Rs.12. When 4 passengersearning = 12x4=Rs.48.expense =Rs.24.profit = Rs.24 = 100%
प्र: एक स्कूल में लड़कों और लड़कियों का अनुपात क्रमशः 4ः6 है। यदि लड़कों की संख्या में 200 की वृद्धि की जाती हैं तो यह अनुपात 5ः6 हो जाता है। स्कूल में लड़कियों की संख्या कितनी है? 3125 05d1b06bf1fc62311c773685b
5d1b06bf1fc62311c773685b- 11200true
- 2800false
- 31000false
- 4500false
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उत्तर : 1. "1200"
प्र: Ashwin fires two bullets from the same place at an interval of 15 minutes but Rahul sitting in a bus approaching the place hears the second sound 14 minutes 30 seconds after the first. If sound travels at the speed of 330 meter per second, what is the approximate speed of bus? 3124 05b5cc670e4d2b4197774c060
5b5cc670e4d2b4197774c060- 1330/29 m/strue
- 2330 x 30 m/sfalse
- 3330/14 m/sfalse
- 4330/900 m/sfalse
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उत्तर : 1. "330/29 m/s"
व्याख्या :
Answer: A) 330/29 m/s Explanation: Second gun shot take 30 sec to reach rahul imples distance between two. given speed of sound = 330 m/s Now, distance = 330 m/s x 30 sec Hence, speed of the bus = d/t = 330x30/(14x60 + 30) = 330/29 m/s.
प्र: P, Q, R, S, T and U are six consecutive odd numbers and their average is 52. What is the product of P and U ? 3122 05b5cc6b9e4d2b4197774d711
5b5cc6b9e4d2b4197774d711- 12212false
- 22154false
- 32349false
- 42679true
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उत्तर : 4. "2679"
व्याख्या :
Answer: D) 2679 Explanation: Let x, x+2, x+4, x+6, x+8 and x+10 are six consecutive odd numbers. Given that their average is 52 Then, x + x+2 + x+4 + x+6 + x+8 + x+10 = 52×6 6x + 30 = 312 x = 47 So Product = 47 × 57 = 2679
प्र: How many 6-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that the digits should not repeat and the second last digit is even ? 3121 05b5cc731e4d2b4197774f7bf
5b5cc731e4d2b4197774f7bf- 1521false
- 2720true
- 3420false
- 4225false
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उत्तर : 2. "720"
व्याख्या :
Answer: B) 720 Explanation: Let last digit is 2when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways.so for last digit = 2, total numbers=240 Similarly for 4 and 6When last digit = 4, total no. of ways =240and last digit = 6, total no. of ways =240so total of 720 even numbers are possible.