Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: In a 40 litre mixture of alcohol & water, the ratio of alcohol and water is 5 : 3. If 20% of this mixture is taken out and the same amount of water is added then what will be the ratio of alcohol and water in final mixture? 2690 05b5cc6b2e4d2b4197774d3be
5b5cc6b2e4d2b4197774d3be- 11:1true
- 22:1false
- 33:1false
- 41:2false
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उत्तर : 1. "1:1"
व्याख्या :
Answer: A) 1:1 Explanation: Quantity of alohol in the mixture = 40 x 5/8 = 25 lit Quantity of water = 40 - 25 = 15 lit According to question, Required ratio = 20 - 40 x 20100 x 5815 - 40 x 20100 x 38 + 40 x 20100 = 2015 - 3 + 8 = 1 : 1
प्र: P, Q, R, S, T and U are six consecutive odd numbers and their average is 52. What is the product of P and U ? 2690 05b5cc6b9e4d2b4197774d711
5b5cc6b9e4d2b4197774d711- 12212false
- 22154false
- 32349false
- 42679true
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उत्तर : 4. "2679"
व्याख्या :
Answer: D) 2679 Explanation: Let x, x+2, x+4, x+6, x+8 and x+10 are six consecutive odd numbers. Given that their average is 52 Then, x + x+2 + x+4 + x+6 + x+8 + x+10 = 52×6 6x + 30 = 312 x = 47 So Product = 47 × 57 = 2679
प्र: A number increased by 30% gives 390. The number is 2688 05b5cc6dde4d2b4197774ea1e
5b5cc6dde4d2b4197774ea1e- 1180false
- 2300true
- 3480false
- 4260false
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उत्तर : 2. "300"
व्याख्या :
Answer: B) 300 Explanation: Let the number be 'N'Given N + 30N/100 = 390=> 130N/100 = 390=> N = 390 x 10/13=> N = 300.
प्र: 6 men can complete a piece of work in 12 days. 8 women can complete the same piece of work in 18 days whereas 18 children can complete the piece of work in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day how many men would be required totally? 2686 05b5cc6ade4d2b4197774d125
5b5cc6ade4d2b4197774d125- 138false
- 272false
- 336true
- 476false
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उत्तर : 3. "36"
व्याख्या :
Answer: C) 36 Explanation: Given 4men, 12 women and 20 children work for 2 days. Workdone for 2 days by 4men, 12 women and 20 children = 4 x 26 x 12 + 12 x 28 x 18 + 20 x 218 x 10 = 12 Therefore, remaining work = 1 - 12 = 12 To complete the same work by only men in 1 day, We know that M1 x D1 = M2 x D2 Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1 12 x 6 = M x 1 => M = 12 x 6 = 72 => But the remaining work = 1/2 Men required => 1/2 x 72 = 36 Only men required to Complete the remaining work in 1 day = 36.
प्र: Find the odd man out from the given alternatives ? 2681 05b5cc6cee4d2b4197774e232
5b5cc6cee4d2b4197774e232- 197false
- 2233false
- 3437true
- 4599false
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उत्तर : 3. "437"
व्याख्या :
Answer: C) 437 Explanation: Except 437 all others are prime numbers.
प्र: A,B and C enter into a partnership in the ratio 72:43:65. After 4 months, A increases his share by 50%. If the total profit at the end of one year be Rs. 21600, then B's share in the profit is : 2679 05b5cc783e4d2b419777501ec
5b5cc783e4d2b419777501ec- 1Rs. 4000true
- 2Rs. 6000false
- 3Rs. 9000false
- 4Rs. 3000false
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उत्तर : 1. "Rs. 4000"
व्याख्या :
Answer: A) Rs. 4000 Explanation: Given ratio of initial investments = 72:43:65 = 105 : 40 : 36. Let the initial investments be 105x, 40x and 36x. ∴A:B:C = 105x×4 + 150100×105x×8 : 40x×12 : 36x×12 = 1680x : 480x : 432x = 35 : 10 : 9. Hence, B's share = 21600×1054 = Rs. 4000.
प्र: 40 % of 250 = 50% ? 2678 05b5cc7c9e4d2b41977750ea4
5b5cc7c9e4d2b41977750ea4- 1200true
- 2100false
- 3150false
- 4400false
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उत्तर : 1. "200"
व्याख्या :
Answer: A) 200 Explanation: As per given 40100×250 =50100×x ⇒x=200
प्र: If selling price is doubled, the profit triples. Find the profit percent ? 2677 05b5cc723e4d2b4197774f6af
5b5cc723e4d2b4197774f6af- 1100%true
- 2200%false
- 3300%false
- 4400%false
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उत्तर : 1. "100%"
व्याख्या :
Answer: A) 100% Explanation: Let the C.P be Rs.100 and S.P be Rs.x, Then The profit is (x-100)Now the S.P is doubled, then the new S.P is 2xNew profit is (2x-100)Now as per the given condition; => 3(x-100) = 2x-100By solving, we get x = 200Then the Profit percent = (200-100)/100 = 100Hence the profit percentage is 100%

