Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: A trader mixes 36 kg of rice at Rs. 20 per kg with 14 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is: 2673 05b5cc76ae4d2b4197774fe4a
5b5cc76ae4d2b4197774fe4a- 125%false
- 221.14%false
- 322.54%true
- 427.32%false
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उत्तर : 3. "22.54%"
व्याख्या :
Answer: C) 22.54% Explanation: C.P. of 50 kg rice = Rs. (36 x 20 + 14 x 36) = Rs. (720 + 504) = Rs.1224. S.P. of 56 kg rice = Rs. (50 x 30) = Rs.1500. Profit = 1500 - 1224 = Rs.276 Profit % = ProfitC.P×100 = 2761224×100 = 22.54%.
प्र: A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 840 km ? 2671 05b5cc745e4d2b4197774fa0e
5b5cc745e4d2b4197774fa0e- 139 daysfalse
- 237 daysfalse
- 335 daystrue
- 433 daysfalse
- उत्तर देखेंउत्तर छिपाएं
- Workspace
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उत्तर : 3. "35 days"
व्याख्या :
Answer: C) 35 days Explanation: Distance d = 1200kmlet S be the speed he walks 15 hours a day(i.e 24 - 9)so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speedso 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs=> 490/14 = 35 days So he will take 35 days to cover 840 km.
प्र: The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ? 2667 15b5cc73ae4d2b4197774f8bf
5b5cc73ae4d2b4197774f8bf- 114th elementfalse
- 29th elementfalse
- 312th elementtrue
- 47th elementfalse
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उत्तर : 3. "12th element"
व्याख्या :
Answer: C) 12th element Explanation: If we consider the third term to be ‘x”The 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.
प्र: A contractor undertook to complete a piece of work in 120 Days and employed 140 men upon it. At the end of 66 days only half of the work was done,so he put on 25 extra men. By how much time did he exceed the specific time ? 2662 05b5cc709e4d2b4197774f2ad
5b5cc709e4d2b4197774f2ad- 12 daystrue
- 23 daysfalse
- 34 daysfalse
- 45 daysfalse
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उत्तर : 1. "2 days"
व्याख्या :
Answer: A) 2 days Explanation: work done=total number of person x number of days;half of work done = 140 x 66;For half of remaining work 25 extra men are added.Therefore, total men for half work remaining = 140 + 25 = 165;Let 2nd half work will be completed in K days;140 x 66 = 165 x KK = 122;Hence, extra days => 122-120 = 2days.
प्र: एक ट्रेन की औसत गति कार की औसत गति का 3 गुना है। कार 8 घंटे में 520 किमी की दूरी तय करती है। 13 घंटे में ट्रेन कितनी दूरी तय करेगी?
2660 05d4aa50111160f2052371686
5d4aa50111160f2052371686- 12553 किमीfalse
- 22585 किमीfalse
- 32355 किमीfalse
- 42535 किमीtrue
- 5इनमें से कोई नहींfalse
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उत्तर : 4. "2535 किमी"
प्र: An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ? 2659 05b5cc736e4d2b4197774f87e
5b5cc736e4d2b4197774f87e- 155 kmstrue
- 235 kmsfalse
- 325 kmsfalse
- 465 kmsfalse
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 1. "55 kms"
व्याख्या :
Answer: A) 55 kms Explanation: Let x and y be the respective km's travelled by man via taxi and by his own car.Given x + y = 90 => x = 90 - yBut according to the question,7x + 6y = 5957(90-y) + 6y = 595=> 630 - 7y + 6y = 595=> y = 630 - 595 = 35=> x = 90 - 35 = 55Therefore, the distance travelled by taxi is 55 kms.
प्र: Find the missing number in the given number series? 514, 470, ?, 415, 404 2658 05b5cc6a9e4d2b4197774cf19
5b5cc6a9e4d2b4197774cf19- 1441false
- 2437true
- 3426false
- 4420false
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उत्तर : 2. "437"
व्याख्या :
Answer: B) 437 Explanation: Given number series is 514 470 ? 415 404 Here the pattern it follows is 514 514 - 44 = 470 470 - 33 = 437 437 - 22 = 415 415 - 11 = 404 Hence, the missing number in the given number series is 437.
प्र: Rajesh rows in still water with a speed of 4.5 kmph to go to a certain place and comes back. Find his average speed for the whole journey, if the river is flowing with a speed of 1.5 kmph? 2657 05b5cc67ee4d2b4197774c245
5b5cc67ee4d2b4197774c245- 12 kmphfalse
- 24 kmphtrue
- 36 kmphfalse
- 48 kmphfalse
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- Workspace
- SingleChoice
उत्तर : 2. "4 kmph"
व्याख्या :
Answer: B) 4 kmph Explanation: Let the distance in one direction = k kms Speed in still water = 4.5 kmph Speed of river = 1.5 Hence, speed in upstream = 4.5 - 1.5 = 3 kmph Speed in downstream = 4.5 + 1.5 = 6 kmph Time taken by Rajesh to row upwards = k/3 hrs Time taken by Rajesh to row downwards = k/6 hrs Now, required Average speed =Total distanceTotal speed = 2kk3 + k6 = 2k x 186k + 3k = 4 kmph Therefore, the average speed of the whole journey = 4kmph.